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19 Cards in this Set

  • Front
  • Back
-Which type of codec has the lowest bandwidth requirement?
G.723
-G.711 uses what coding scheme?
PCM
-G.726 uses what coding scheme?
ADPCM
-G.728 uses what coding scheme?
LDCELP
-G.729 uses what coding scheme?
CS-ACELP
-G.723 uses what coding scheme?
MPMLQ
-What is the disadvantage of encapsulating more samples per PDU?
The delay becomes more variable
-What would be the size of voice samples from Cisco voice equipment if a G.728 codec were used?
20 ms
-What is the overhead for Frame Relay?
6 Bytes
-How many bytes in the Ethernet II overhead are used for CRC?
4 bytes
-What is the overhead associated with IPSec?
50 to 57 bytes
-What is the overhead associated with MPLS?
4 bytes
-Which two examples of protocol-specific encapsulation
X.25 over TCP/IP
Ipv6 over Ipv4
-Which two examples of experimental encapsulation?
L2F
L2TP
-Which 3 factors must be considered when calculating the total bandwidth of a VoIP call?
Codec Size
Network-Link Overhead
Sample Size
-Using a G.729 codec and Frame Relay without CRTP, what is the total bandwidth required for a 40-byte voice sample size?
17200 bps
-What is the function of comfort noise generation?
Provides white noise to make the call sound connected
-What is the formula used to calculate the total bandwidth?
Total Bandwidth = ([Layer_2_Overhead + IP_UDP_RTP Overhead + Sample_Size] / Sample_Size) * Codec_Speed
-Using a G.729 codec and Frame Relay without CRTP, what is the total bandwidth required for a 40-byte voice sample?
17200 bps
Remember...
Total Bandwidth = ([Layer_2_Overhead + IP_UDP_RTP Overhead + Sample_Size] / Sample_Size) * Codec_Speed