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18 Cards in this Set

  • Front
  • Back
Basic Aldol reaction
Whats involved
Catalysts
How?
Aldehyde or Ketone with alpha hydrogen
HCOCH3 + NaOH/Ethanol > HCOCH2CH(OH)CH3
Base makes enolate ion, attacks electrophillic carbonyl carbon
aldol (aldehyde + alcohol)
When will aldol happen (equillibrium)
equillibrium favors aldol reaction for monosubstituted aldehydes
favors reactants for disubstituted aldehydes and most ketones
When will aldol happen (instead of alpha substitution)
for alpha sub, full equiv. of base, low temp
for condensation, catalytic amnt of weak base
Driving force for aldol condensation basic conditions
E1cB (cb=conj base)
Aldol condensation reaction
Beta-Hydroxy ketone or aldehyde + base (or acid, but not really) >conjugated enone. Very stable
Implications of aldol condensation
Even ketones or disubstituted aldehydes that are otherwise reactant favored for aldol, can be immediately condensed, driving the reaction towards completion
Mixed aldol reactions, one product condition
otherwise?
Normally, mixed aldol leads to two symmetrical and two mixed products.
IF
One partner has no alpha hydrogen and an unhindered carbonyl carbon, other carbonyl will enolize and attack
IF
One partner has a much more acidic alpha H (e.g., keto-ester), will enolize
Intramolecular aldol reaction
H3C-COCH2CH2CO-CH3
H3C-COCH2CH2CO-CH3 + NaOH/Ethanol > 5 membered enone ring with methyl group at beta position
STERIC FACTORS
Claisen condensation
Requirements
reagents
products
Requires ester with alpha hydrogen AND FULL EQUIVALENT OF BASE
2(H3C-COOEt )+ NaOEt/Ethanol >> + H3O+>
H3C-COCH2COOEt
Beta-keto ester
Ester on claisen acceptor is leaving group
Driving force of claisen condensation
deprotonation of flanked carbon's acidic hydrogen,
thermodynamic sink
Conj base removes acidic hydrogen leaving a negative charged shared by flanking O's.
H3O+ workup returns the hydrogen
Mixed Claisen
Applicable when one compound has no alpha hydrogen, acts as acceptor
not always good idea
Claisen like reaction
involves a ketone/aldehyde with an alpha hydrogen and an ester with no alpha hydrogen
alpha substitution of ketone, acyl substitution of ester results in B-diketone
Intramolecular Claisen(Name?)
Requirement
Reagent
Result
Dieckmann Cyclization
requires an alkyl chain with two terminal esters
i.e.
EtO-CO-CH2CH2CH2CH2-CO-OEt +NaOEt/Ethanol >> + H30+ > 5 membered ketone with alpha COOEt
Where to go after dieckman cyclization
the acidic, flanked alpha carbon can react with R'X group with NaOEt, then H30+ + heat removes the COOEt group via decarboxylation
Michael Reaction
Requirement
Reagents
Products
Enolate ion will attack B carbon of a/B-unsaturated ketone
H30+ workup yields a ketone with a substituted beta carbon bonded to alpha carbon of donor
Good Michael Donors:
Good Michael Acceptors
Donors:
any carbon flanked by two carbonyls (assuming an alpha hydrogen), Bketo-nitrile, RCH2NO2 (Hydrogen is very acidic)
Acceptors:
Conjugated enone, R=CHCN, R=CH-NO2
Stork reaction
how
example
reagents
Enamine "enolizes" for positive N and negative alpha C, attacks conjugated enone, H20 replaces enamine with carbonyl
e.g.
Cyclohexanone + secondary amine + michael acceptor>
1-aminogroup,2alkylketone-cyclohexa1,6-ene > 2alkylketonecyclohexanone
reagent: THF/H3O+
Robinson annulation
What does it combine
Reagents
What does it make
Michael reaction + intramolecular aldol condensation
NaOEt H30+
will form a ketone ring with substituents