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15 Cards in this Set

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KEY WORDS
PERMUTATION
COMBINATION
RATIO
DESC 1
IF YOU CAN DETERMINE THE NUMBER OF OUTCOMES IN AN EVENT AND THE NUMBER OF OUUTCOMES IN THE SAMPLE SPACE, YOU CAN DETERMINE THE PROBABILITY. IT IS JUST A RATION
DESC 2
USE PERMUTATIONS, COMBINATIONS AND RATIONS OF GEOMETRIC AREAS TO SOLVE PROBABILITY PROBLEMS
deffinitions and explictations
SAMPLE SPACE
TEH SET OF ALL POSSIBLE OUTCOMES EXP: IF YOU ROLL A DIE, THE SET OF ALL POSSIBLE OUTCOMES
SAMPLE SPACE
A SPECIFIC OUTCOME OR TYPE OF OUTCOME. EVENT
POSSIBLE RESULTS OF A PROBABILITY EVENT. OUTCOMES
THE RATIO OF THE NUMBER OF WAYS AN EVENT CAN OCCUR TO THE NUMBER IF POSSIBLE OUTCOMES. THEORETICAL PROBABILITY
TWO EVENTS IN WHICH EITHER ONE MUST HAPPEN BUT THEY CANNOT HAPPEN AT THE SAME TIME. COMPLEMENTARY EVENTS

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Copyright © 2005-2007 Tuolumne Technology Group, Inc.Terms of Service —
A SPECIFIC OUTCOME OR TYPE OF OUTCOME. EVENT
POSSIBLE RESULTS OF A PROBABILITY EVENT. OUTCOMES
THE RATIO OF THE NUMBER OF WAYS AN EVENT CAN OCCUR TO THE NUMBER IF POSSIBLE OUTCOMES. THEORETICAL PROBABILITY
TWO EVENTS IN WHICH EITHER ONE MUST HAPPEN BUT THEY CANNOT HAPPEN AT THE SAME TIME. COMPLEMENTARY EVENTS

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Copyright © 2005-2007 Tuolumne Technology Group, Inc.Terms of Service —
NUMBER OF WAYS EVENT A or Event B can occur n(A or B)=n(A) * (b)
A or Event B can occur n(A or B)=n(A) * (b)
Outcomes of an event B)
numbers of way sEvents A AND THEN Event B can occur\
N(a AND THEN b)= N(a) * (b)
Outcomes of an event c)
number of ways Events A or B, but not A and B could occur n(A or B) = n(A) *(B)-n(upside down u)B)
probaility of event
P(E)=# of outcomes in an event/# of outcomes in a sample space =P(E)=n(E)/n(S)
what is the symbol of probabiltiy and event does not occur?
1- P(E)
define perutation:
AN ARRANGEMENT OF THE ELEMENTS FROM A GIVEN SET IN A DEFINTE ORDR
PERMUTAION EXAMPLE: gIVEN{A,b,c] there are 6 arrrangemtnes. even though each arrangemetn has the same letters, the order is different in each
pe A-B-C, A-C-B, B-A-C, B-C-A, C-A-B, C-B-A
Combination: uniques subsets of the elements of set, regardless how they are arranged show example
EX: Given [A,B, C], THERE IS 1 ARRANGEMENT BECAUSE EACH RRANGEMENT HAS TEH SAME LETTERS,
A-B-C, A-C-B, B-A-C, B-C-A, C-A-B, C-B-A
DO EXAMPLE 1 PAGE 93
D) 26*26*26*10*10*10-REPLACEMENT ALLOWED
(0-9) STANDS FOR 10 FIGURES
DO EXAMPLE 2 PAGE 93
SOLUTIONS=GO OVER WITH AMY