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15 Cards in this Set
- Front
- Back
- 3rd side (hint)
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KEY WORDS
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PERMUTATION
COMBINATION RATIO |
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DESC 1
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IF YOU CAN DETERMINE THE NUMBER OF OUTCOMES IN AN EVENT AND THE NUMBER OF OUUTCOMES IN THE SAMPLE SPACE, YOU CAN DETERMINE THE PROBABILITY. IT IS JUST A RATION
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DESC 2
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USE PERMUTATIONS, COMBINATIONS AND RATIONS OF GEOMETRIC AREAS TO SOLVE PROBABILITY PROBLEMS
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deffinitions and explictations
SAMPLE SPACE |
TEH SET OF ALL POSSIBLE OUTCOMES EXP: IF YOU ROLL A DIE, THE SET OF ALL POSSIBLE OUTCOMES
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SAMPLE SPACE
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A SPECIFIC OUTCOME OR TYPE OF OUTCOME. EVENT
POSSIBLE RESULTS OF A PROBABILITY EVENT. OUTCOMES THE RATIO OF THE NUMBER OF WAYS AN EVENT CAN OCCUR TO THE NUMBER IF POSSIBLE OUTCOMES. THEORETICAL PROBABILITY TWO EVENTS IN WHICH EITHER ONE MUST HAPPEN BUT THEY CANNOT HAPPEN AT THE SAME TIME. COMPLEMENTARY EVENTS With selected items: Study Print Export Play Memory Add to Cardfile Remove from Clipboard Copyright © 2005-2007 Tuolumne Technology Group, Inc.Terms of Service — |
A SPECIFIC OUTCOME OR TYPE OF OUTCOME. EVENT
POSSIBLE RESULTS OF A PROBABILITY EVENT. OUTCOMES THE RATIO OF THE NUMBER OF WAYS AN EVENT CAN OCCUR TO THE NUMBER IF POSSIBLE OUTCOMES. THEORETICAL PROBABILITY TWO EVENTS IN WHICH EITHER ONE MUST HAPPEN BUT THEY CANNOT HAPPEN AT THE SAME TIME. COMPLEMENTARY EVENTS With selected items: Study Print Export Play Memory Add to Cardfile Remove from Clipboard Copyright © 2005-2007 Tuolumne Technology Group, Inc.Terms of Service — |
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NUMBER OF WAYS EVENT A or Event B can occur n(A or B)=n(A) * (b)
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A or Event B can occur n(A or B)=n(A) * (b)
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Outcomes of an event B)
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numbers of way sEvents A AND THEN Event B can occur\
N(a AND THEN b)= N(a) * (b) |
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Outcomes of an event c)
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number of ways Events A or B, but not A and B could occur n(A or B) = n(A) *(B)-n(upside down u)B)
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probaility of event
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P(E)=# of outcomes in an event/# of outcomes in a sample space =P(E)=n(E)/n(S)
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what is the symbol of probabiltiy and event does not occur?
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1- P(E)
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define perutation:
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AN ARRANGEMENT OF THE ELEMENTS FROM A GIVEN SET IN A DEFINTE ORDR
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PERMUTAION EXAMPLE: gIVEN{A,b,c] there are 6 arrrangemtnes. even though each arrangemetn has the same letters, the order is different in each
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pe A-B-C, A-C-B, B-A-C, B-C-A, C-A-B, C-B-A
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Combination: uniques subsets of the elements of set, regardless how they are arranged show example
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EX: Given [A,B, C], THERE IS 1 ARRANGEMENT BECAUSE EACH RRANGEMENT HAS TEH SAME LETTERS,
A-B-C, A-C-B, B-A-C, B-C-A, C-A-B, C-B-A |
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DO EXAMPLE 1 PAGE 93
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D) 26*26*26*10*10*10-REPLACEMENT ALLOWED
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(0-9) STANDS FOR 10 FIGURES
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DO EXAMPLE 2 PAGE 93
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SOLUTIONS=GO OVER WITH AMY
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