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56 Cards in this Set
- Front
- Back
Buffer
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Chemical system that resists pH changes by neutralizing add acid or base
Significant amounts of weak acid/conjugate base or weak base/conjugate acid (more than the added acid/base) |
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Acidosis
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A condition in which acid affects the equilibrium between hemoglobin and oxygen
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Common Ion Effect
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When the conjugate base is already present, it reduces the ionization of the acid, leading to a less acidic (higher pH) solution
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X is small approximation
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For a weak acid or weak base, the concentration of it and its conjugate is essentially identical to the initial concentration
Applicable when the initial concentrations are not two dilute and the equilibrium constant is relatively small |
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Stoichiometry calculation
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Calculate how the addition of adding an acid or base to a buffer changes the relative amounts of acid and conjugate base
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Equilibrium calculation
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Calculate the pH based on the new amounts of acid and conjugate base
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Henderson-Hasselbalch Equation
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pH=pKa+log([base]/[acid])
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Buffer Range
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Lowest effective pH occurs when the base is one-tenth as concentrated as the acid (pH=pKa-1)
Highest pH occurs when the base is ten times as concentrated as the acid (pH=pKa+1) |
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Buffer Capacity
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Amount of acid or base that you can add to a buffer without causing a large change in pH: increases with increases with increasing absolute concentrations of the buffer components
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pH at equivalence point of a strong acid-strong base titration
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7.00
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[H3O+][OH-]
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10^-14
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Ksp
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[C]^c+[D]^d
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Molar solubility
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Solubility in mol/L
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Effect of pH on solubility
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Solubility of an ionic compound with a strongly or weakly basic anion increases with increasing acidity (decreasing pH)
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Q<Ksp
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Solution is unsaturated and more of the solid can dissolve
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Q=Ksp
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Solution is saturated
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Q>Ksp
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The solution is supersaturated
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Group 1
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(Add 6M HCl) Insoluble chlorides: only form precipitates with Ag, Hg, and Pb
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Group 2
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(add H2S, 0.2M HCl) Acid-insoluble sulfides: for precipitates with Cu, Bi, Cd, Pb, Hg, As, Sb, and Sn
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Group 3
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(Add OH-) Base-insoluble sulfides and hydroxides: form precipitate with Al, Fe, Cr, Zn, Ni, Co, Mn, Fe
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Group 4
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(Add (NH4)2HPO4, NH3) Insoluble phosphates: form precipitates with Ba, Ca, and MgNH4
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Group 5
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(Same as Group 4) Alkali metal ions and Na, K, and NH4
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Complex ion
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contains a central metal ion bound to one or more ligands--formation is highly favored
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Ligand
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neutral molecule or ion that acts as a Lewis base with the central metal ion
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Solubility of an ionic compound containing a metal cation that forms complex ions
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Increases in the presence of Lewis bases that complex with the cation
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Amphoteric
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Hydroxides that can act as a base or an acid, especially with Al, Cr, Zn, Pb, and Sn
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Entropy
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Thermodynamic function that increase with the number of energetically equivalent ways to arrange the components of the system to achieve a particular state
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Equation for entropy
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S=klnW (k=the Boltzmann constant=1.38*10^-23, W=the number of energetically equivalent ways to arrange the system)
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Macrostate
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Constant when P, V, and T of a closed system are constant, number of Joules of energy in a given space
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Microstate
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Exact arrangement within a macrostate, each microstate adds up to a macrostate (Two 2J atoms and one 1J atom+one 3J atom are different microstates within the same macrostate)
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Second Law of Thermodynamics
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For any spontaneous process, the energy of the universe increases (∆Suniv>O)
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State function
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Value only depends on the state of the system, not how it got there
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Calculating ∆S
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∆S=Sfinal-Sinitial
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Entropy of solid-->liquid-->gas
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Increases
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Calculating ∆Suniv
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∆Suniv=∆Ssys+∆Ssurr
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Effect of Release of Heat on Entropy
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Increases entropy of surrounds
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Units of entropy
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J/K
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Entropy as heat given is given off/abosorbed
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As the temperature outside becomes significantly higher/lower, ∆Ssurr becomes smaller as heat is given off/absorbed, respectively
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Calculating ∆Ssurr
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-∆Hsys/T
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Gibbs Free Energy
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∆G=∆H-T∆S
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∆G<0
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Spontaneous
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∆G>0
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Nonspontaneous
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∆G when ∆H is negative and ∆S is positive
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∆G<0, the reaction is spontaneous
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∆G when ∆H is positive and ∆S is negative
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∆G>0, the reaction is nonspontaneous
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∆G when ∆H and ∆S are both negative
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∆G<0 at low temperatures and ∆G>0 at hight temperatures
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∆G when ∆H and ∆S are both positive
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∆G>0 at low temperatures and ∆G<0 at high temperatures
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Calculating ∆S˚rxn
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∆S˚rxn=S˚products-S˚reactants
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Third Law of Thermodynamics
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The entropy of a perfect crystal at absolute 0 is zero
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Entropy dependence
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Extensive: depends on the amount of substance
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S˚as related to molar mass
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The more massive a noble gas, the greater its entropy at 25˚C
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S˚ as related to molecular complexity
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S˚ increases with molecular complexity, overruling molar mass
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S˚ of dissolution
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Increases
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Calculating ∆S˚rxn
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∆S˚rxn=∑nS˚(products)-∑nS˚(reactants)
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Calculating ∆G˚rxn
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∆G˚rxn=∆S˚rxn-T∆S˚rxn=∑n∆G˚formation(products)-∑n∆G˚formation(reactants)
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∆Grxn under nonstandard conditions
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∆Grxn=∆G˚rxn+RTlnQ=-RTlnK
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lnK
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-(∆H˚rxn(1/T)+∆S˚rxn)/R
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