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56 Cards in this Set

  • Front
  • Back
Buffer
Chemical system that resists pH changes by neutralizing add acid or base
Significant amounts of weak acid/conjugate base or weak base/conjugate acid (more than the added acid/base)
Acidosis
A condition in which acid affects the equilibrium between hemoglobin and oxygen
Common Ion Effect
When the conjugate base is already present, it reduces the ionization of the acid, leading to a less acidic (higher pH) solution
X is small approximation
For a weak acid or weak base, the concentration of it and its conjugate is essentially identical to the initial concentration
Applicable when the initial concentrations are not two dilute and the equilibrium constant is relatively small
Stoichiometry calculation
Calculate how the addition of adding an acid or base to a buffer changes the relative amounts of acid and conjugate base
Equilibrium calculation
Calculate the pH based on the new amounts of acid and conjugate base
Henderson-Hasselbalch Equation
pH=pKa+log([base]/[acid])
Buffer Range
Lowest effective pH occurs when the base is one-tenth as concentrated as the acid (pH=pKa-1)
Highest pH occurs when the base is ten times as concentrated as the acid (pH=pKa+1)
Buffer Capacity
Amount of acid or base that you can add to a buffer without causing a large change in pH: increases with increases with increasing absolute concentrations of the buffer components
pH at equivalence point of a strong acid-strong base titration
7.00
[H3O+][OH-]
10^-14
Ksp
[C]^c+[D]^d
Molar solubility
Solubility in mol/L
Effect of pH on solubility
Solubility of an ionic compound with a strongly or weakly basic anion increases with increasing acidity (decreasing pH)
Q<Ksp
Solution is unsaturated and more of the solid can dissolve
Q=Ksp
Solution is saturated
Q>Ksp
The solution is supersaturated
Group 1
(Add 6M HCl) Insoluble chlorides: only form precipitates with Ag, Hg, and Pb
Group 2
(add H2S, 0.2M HCl) Acid-insoluble sulfides: for precipitates with Cu, Bi, Cd, Pb, Hg, As, Sb, and Sn
Group 3
(Add OH-) Base-insoluble sulfides and hydroxides: form precipitate with Al, Fe, Cr, Zn, Ni, Co, Mn, Fe
Group 4
(Add (NH4)2HPO4, NH3) Insoluble phosphates: form precipitates with Ba, Ca, and MgNH4
Group 5
(Same as Group 4) Alkali metal ions and Na, K, and NH4
Complex ion
contains a central metal ion bound to one or more ligands--formation is highly favored
Ligand
neutral molecule or ion that acts as a Lewis base with the central metal ion
Solubility of an ionic compound containing a metal cation that forms complex ions
Increases in the presence of Lewis bases that complex with the cation
Amphoteric
Hydroxides that can act as a base or an acid, especially with Al, Cr, Zn, Pb, and Sn
Entropy
Thermodynamic function that increase with the number of energetically equivalent ways to arrange the components of the system to achieve a particular state
Equation for entropy
S=klnW (k=the Boltzmann constant=1.38*10^-23, W=the number of energetically equivalent ways to arrange the system)
Macrostate
Constant when P, V, and T of a closed system are constant, number of Joules of energy in a given space
Microstate
Exact arrangement within a macrostate, each microstate adds up to a macrostate (Two 2J atoms and one 1J atom+one 3J atom are different microstates within the same macrostate)
Second Law of Thermodynamics
For any spontaneous process, the energy of the universe increases (∆Suniv>O)
State function
Value only depends on the state of the system, not how it got there
Calculating ∆S
∆S=Sfinal-Sinitial
Entropy of solid-->liquid-->gas
Increases
Calculating ∆Suniv
∆Suniv=∆Ssys+∆Ssurr
Effect of Release of Heat on Entropy
Increases entropy of surrounds
Units of entropy
J/K
Entropy as heat given is given off/abosorbed
As the temperature outside becomes significantly higher/lower, ∆Ssurr becomes smaller as heat is given off/absorbed, respectively
Calculating ∆Ssurr
-∆Hsys/T
Gibbs Free Energy
∆G=∆H-T∆S
∆G<0
Spontaneous
∆G>0
Nonspontaneous
∆G when ∆H is negative and ∆S is positive
∆G<0, the reaction is spontaneous
∆G when ∆H is positive and ∆S is negative
∆G>0, the reaction is nonspontaneous
∆G when ∆H and ∆S are both negative
∆G<0 at low temperatures and ∆G>0 at hight temperatures
∆G when ∆H and ∆S are both positive
∆G>0 at low temperatures and ∆G<0 at high temperatures
Calculating ∆S˚rxn
∆S˚rxn=S˚products-S˚reactants
Third Law of Thermodynamics
The entropy of a perfect crystal at absolute 0 is zero
Entropy dependence
Extensive: depends on the amount of substance
S˚as related to molar mass
The more massive a noble gas, the greater its entropy at 25˚C
S˚ as related to molecular complexity
S˚ increases with molecular complexity, overruling molar mass
S˚ of dissolution
Increases
Calculating ∆S˚rxn
∆S˚rxn=∑nS˚(products)-∑nS˚(reactants)
Calculating ∆G˚rxn
∆G˚rxn=∆S˚rxn-T∆S˚rxn=∑n∆G˚formation(products)-∑n∆G˚formation(reactants)
∆Grxn under nonstandard conditions
∆Grxn=∆G˚rxn+RTlnQ=-RTlnK
lnK
-(∆H˚rxn(1/T)+∆S˚rxn)/R