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96 Cards in this Set
- Front
- Back
Chemical equilibrium
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-many important processes can proceed in both forward and reverse directions
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Ways to perturb an equilibrium processes
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-add a catalyst
-change the temperature -change overall P, or partial P of a component -change [] -add more reactant/ product -add more solvent/dilute -remove reactant/product -add reactive chemical -change volume -add an un-reactive chemical |
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dynamic process
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rate forward=rate reverse (at equ.)
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give example of dynamic process
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cars bumper to bumper on a bridge
-for every entering car, one must leave the bridge, however, the # of cars on a bridge is not changing (reaction has not stopped) |
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equilibrium can be --- and ---
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chemical and physical processes
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fritz haber
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invented most of the poisonous gases used to kill germans
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le chateliers principle
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if an external stress is applied to a system at eq. the system will adjust in order to attempt to relieve the stress
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equilibrium means
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the rate of the forward reaction must = the rate of the reverse reaction (DONT HAVE TO BE THE SAME AMOUNT)
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if some un-reactive gas is added the equilibrium will
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not change! However the overall pressure will be increased but there is no change in the partial pressures of the gases in equilibrium.
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Quantitative aspects of equilbrium
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-predict dissection of reaction when its not obvious
-calculate concentration of reactants/products once equ. is reached |
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Give examples of Quantitative aspects of equilbrium
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-acid/base chem--> biochemistry
-how to maintain pH (blood level pH) -solubility of metal compounds--> environment, dentistry |
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Give the equilibrium reaction
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aA+bB <-> cC+dD
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Rate forward=
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kforward[A]^a[B]^b
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Rate reverse=
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kreverse[C]^c[D]^d
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What is Kc
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Kc is the equ. constant (K is the ratio of Kforward/Kreverse)c is concentration
-use concentration (mol/L- (M) |
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For Kc only include
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[]'s of gases or solutions
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For Kp only
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involves gases
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For K expressions its always..
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products over reactants
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Magnitude of K- if K is >10^3
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product favored eq
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Magnitude of K- if K is <10^-3
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reactant favored eq
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Magnitude of K- if K is 10^-3<k<10^3
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hard to tell comparable
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kp=
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Kc(RT)^^n
^n= change in moles of GAS T=kelvins |
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acid base chem is
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proton transfer (H+)
-relevant to metabolic/biochemical pathways, food, pharmaceuticals |
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Relevant acids in acid base chem
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HCl-produced by epitheal cells in stomach
Aspirin DNA Citric acid Formic acid |
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Relevant bases in acid base chem
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caffeine, anaesthetics (novocaine) (all "caine" compounds), neurotransmitters
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Arrehenius Acid base definition
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acid-donates H+
base-donates OH- |
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Bronsted laury Acid base definition
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acid-donates H+
base-accepts H+ |
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H2O is
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amphoteric
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amphoteric
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can act as either an acid or a base depending on the situation
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Why do acids donate H+
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-electro negativity and polarity
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For Kc only include
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[]'s of gases or solutions
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For Kp only
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involves gases
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For K expressions its always..
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products over reactants
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Magnitude of K- if K is >10^3
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product favored eq
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Magnitude of K- if K is <10^-3
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reactant favored eq
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Magnitude of K- if K is 10^-3<k<10^3
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hard to tell comparable
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kp=
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Kc(RT)^^n
^n= change in moles of GAS T=kelvins |
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acid base chem is
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proton transfer (H+)
-relevant to metabolic/biochemical pathways, food, pharmaceuticals |
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Relevant acids in acid base chem
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HCl-produced by epitheal cells in stomach
Aspirin DNA Citric acid Formic acid |
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Relevant bases in acid base chem
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caffeine, anaesthetics (novocaine) (all "caine" compounds), neurotransmitters
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Arrehenius Acid base definition
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acid-donates H+
base-donates OH- |
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Bronsted laury Acid base definition
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acid-donates H+
base-accepts H+ |
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H2O is
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amphoteric
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amphoteric
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can act as either an acid or a base depending on the situation
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Why do acids donate H+
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-electro negativity and polarity
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7 strong acids
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HCl, H2SO4, HI,HBr, HClO3, HClO4, HNO3
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H3O+ is the
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strongest acid that can exist in H2O "levelling effect"
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For a strong acid, its conj base is
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NON-BASIC(cannot accept H+)
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Weak acids
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react partially and in an equilibrium fashion with water
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For a weak acid, its conj base is
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BASIC (can accept an H+ and regenerate HA)
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The more oxygens you have the
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stronger your acid will be
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Strong acid formula
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HX + H2O--> X- + H3O+
acid base |
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Strong base reactivity
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-any soluble ionic compound that delivers OH- in solution
eg. NaOH, KOH,Ba(OH)2 -any source of H- eg. NaH, CaH2, LiAlH4 -NaNH2-->Na+ + NH2- -any species with a fully negative C atom eg. Li+C-H3 |
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Kw applies to ALL
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aqueous solutions
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Kw=
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[H3O+][OH-]
these can never = 0 |
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pure H2O [H3O+]__[OH-]
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[H3O+]=[OH-]
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acidic solution [H3O+]__[OH-]
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[H3O+]>[OH-]
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basic solution [H3O+]__[OH-]
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[OH-]>[H3O+]
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pKw=
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pH+pOH=14
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pH=
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-log[H3O+]
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pOH=
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-log[OH-]
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pKw=
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-log[Kw]
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Acidic solutions [H3O+] goes up the pH goes
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down--pH<7
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Basicsolutions [H3O+] goes up the pH goes
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up-- pH>7
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pH can be negative or 0 for very
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acidic solutions
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percent ionization
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visualization of how much reaction actually took place
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percent ionization formula
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percent I= [H3O+]f/ [HA]i *100
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Ka*Kb=
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Kw
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Codine is
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a mild narcotic. Its an amine + a lone pair on the N atom. Its basic. To avoid odor and reactivity amine based pharmacitucals are converted to their hydrochloride salts
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Polyprotic acids
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can donate more than H+ in a successive manner
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Buffers
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soln' that resist pH upon addition of extra acid or extra base
-relevant to biochem. eg. blood |
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If something is too acidic the buffer
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will protonate N's
N:--> NH+ |
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If something is too basic the buffer
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will deprotonate OH's
OH:--> O- |
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Buffer must contain
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weak acid AND its conj. base
OR weak base AND its conj. acid |
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Why cant a strong acid/strong base pair be a buffer?
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Cannot soak up extra base, or extra acid. There is no resistance to acid addition
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Weak acids can soak up extra base because
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you are regenerating conj. base
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Buffers can survive
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repeated attempts at pH change
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pH=
(Called the H-H eq.) |
pKa+log([A-]/[HA])
where: [A-]= conj base conc. [HA]= weak acid conc can also use mols instead of M |
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what is pH not dependent on?
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pH is not dependent on solution volume for a buffer dilute a buffer-->No pH change
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For a strong acid soln:
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-dilute it
-[H3O+] goes down -pH goes up (less acidic) |
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What is the method applicable to all buffer pH problems
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1. write reaction that will occur
2. Find moles of buffer components and the added chemical 3. set up and do the lim. reactant problem 4. Find pH using H-H eq. in mol form |
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Method for making a buffer solution:
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1. Pick appropriate weak acid or weak base (the one with the best buffering capacity-- ability to soak up added acid or base) when [HA]=[A-]
- You want to use a weak acid whose pKa is closest to pH desired (same goes for base (pKb close to pOH)) 2. for good buffering need [HA]> or equal to 0.1M 3. Find necessary conc.'s by using H-H equation in reverse 4. Do stoich. calc's to get masses of each component |
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Q=
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reaction quotient which is written like K expression, but initial values of conc. or P are used
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when direction of rxn is not obvious you
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compare Q with K
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If Q<K
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too much reactant (den. too large) shifts to the RIGHT to use up reactants to make more products
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If Q>K
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too much product (num. too large) shifts left to make more reactants to use up the products
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If Q=K
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rxn is at equilibrium already
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Predicting the direction of a reaction when have weak acids or bases
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you need the Ka and Kb values to tell which is the strongest acid and strongest base
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Predicting the pH range of a salt solution (any ionic compound)
CATION |
-metals w/low +charge-> neutral
-metals w/high +charge->acidic -conj. acid of a weak base->acidic |
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Predicting the pH range of a salt solution (any ionic compound)
ANION |
-conj base of a strong acid->non-basic->neutral
-conj. base of a weak acid->basic |
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Metals with a low + charge
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Eg. Li+, Na+, K+, etc
these metals bind water molecules very weakly (O-H bonds of H2O stay intact, they do not get weaker) the H+ is not very likely to be grabbed by a base- neutral effect |
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Metals with a high + charge
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eg. Fe2+, Zn2+,Al3+ etc
H2O binds very strongly to these metals because O steals e- density from O-H bond and the O-H bond is weaker |
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If one component is acidic and the other is basic you need to compare
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Ka and Kb values
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If Ka>Kb
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acidic
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If Ka<Kb
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basic
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If Ka=Kb
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neutral
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