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17 Cards in this Set
- Front
- Back
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colorimetry
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set of solutions of known concentrations is placed in a series of containers. unknown concentration is compared w/ calibrateion set
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beer's law
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Absorbance=abc
a=prob. that substance absorbs light b= path legnth of light thru sample c= concentration of substance in solution |
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why aluminum expensive to produce
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1. high grade bauxite deposits (needed) occur outside US
2. Hall-Heroult process extremely energy intensive |
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2 uses for alum compound
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1. phosphate removal agents in water and waste treatment plants
2. soap, plastics, cosmetics |
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presences of SO4, K+, Al3+, H2O
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K+ : flame test; purple showed K+ was present
Al3+ : pH=1 to show Al present and acidic reaction SO4: Barium w/ crystals showed insoluble SO4 H2O: flame->bubbling; crackling noise of evaporation was H2O was present |
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"like dissolves like"
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polar compounds dissolve in polar solutions
nonpolar compounds dissolve in nonpolar solutions ex.ammonia soluble in water (both polar) |
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kerosene, pentanol, ethanol, water
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kerosene:w/ h2o=layered (nonpolar)
pentanol:w/kerosene=layered/mixture (nonpolar) ethonal:w/kerosene=layered (polar) water:w/ h2o=mixture (polar) |
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precipitation
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produces new compuond not soluble in aq. solution
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acid-base solution
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acid reacts w/ base to give water and salt
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complexation
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1 or more coordinate covalent bonds produced during formation
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redox
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electrons are transferred from one species to another
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why water sample need to be spiked w/ MgEDTA?
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to ensure there is Mg in the water sample b/c Mg is needed for the reaction to occur
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ion exchange resin
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monovalent cations are exchanged w/ divalent cations
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how AA is carried out
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hallow cathode lamps emit monochromatic light, which corresponds to ^E of elements being analyzed. atoms in sample having electronic engery separation ^E will absorb the light and amount of absorbance is proportional to concentration of metal atoms in sample
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beer-lambert law
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I(t)=I(o)(10^-abc)
I(o) is the intial light sorce and its decrease is proportional to the concentration of the metal in the sample |
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purpose of "standards" taht run as part of AA analysis?
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`the most accurate region of the calibration curve is between the max and min standard points
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problem w/ analyzing sample whose absorbance exceeds 1 absorbance unit?
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if the sample is above 1 au, there is little light transmitted for the PMT to detect.
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