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16 Cards in this Set
- Front
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Stoichiometry |
The study of chemical quantities consumed or produced in a chemical reaction |
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Steps to Solving a Stoichiometry Problem |
Step 1: Balance the equation. This equation is already balanced Step 2: Find the moles of the reactant. Step 3: Use the mole ratio between the reactant and product to find the moles of product made. Step 4: Convert moles of product to the desired unit. |
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Mole to Mole Calculations |
Mole to mole ratio comes from balanced chemical equations |
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= 2.25 moles of O2 |
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Rules for Mole to Mole Calculations |
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Mole Ratio |
As the ratio of moles of one substance to the moles of another substance in a balanced equation |
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Moles to Mass Caculations |
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Moles to Mass: How many grams of glucose are produced when 3 moles of water react with carbon dioxide. |
= 90g or C6H12O6 |
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Mass To Moles |
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Mass to Moles: If 8g of SO2 reacts, how many moles of CS2 are formed? |
= 0.06 moles CS2 |
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Mass to Mass |
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Mass to Mass: How many grams of NH4NO3 are needed to produce 33g of N2O in the following reaction: NH4NO3 --> N2O + 2H2O? |
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Molar Volume |
22.4L = 1 mol or 22.4L / 1 mol |
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How many moles of nitrogen are present in a 2 L sample held at STP? |
2L X 1 mol / 22.4L = 0.089 mols |
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We have approximately 68.02 g of liquid hydrogen peroxide. How many liters of oxygen gas will be produced in this reaction if carried out at STP? |
Step 1: 2H2O2 --> 2H2O(gas) + 02(gas) Step 2: 68.02g 2H2O2 / 1 X 1 mole / 34.01g = 2 moles Step 3: 2 moles 2H2O2 X 1 mol O2 / 2H2O2 = 1 mol O2 Step 4: 1 mol O2 X 22.4L / 1 mol = 22.4L of O2 |
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Molarity (M or mol/L) |
Is the ratio of moles of solute to liters of solution. Molarity is calculated by dividing the number of moles of solute by the liters of solution. Molarity = moles solute /Liters solution This give you the concentration of the solution Represented by = # M |