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55 Cards in this Set

  • Front
  • Back
Limit def in symbols
lim f(x)= L for every E>0, there is
x->a a delta>0 so that
0<|x-a| <delta then |f(x)-L| <E
Verbal def of the limit
We say that Lim x->a f(x)=L if we can make the values of f(x) arbitrarily close to the number L by taking x sufficiently close to the number a (excluding the point at x=a)
Methods for computing limit
simplify
factor and cancel
multiply by conjugate
divide by x x->infinity
l'hospital's rule 0/0 infinity/infinity
horizontal asymptote
y=b for f(x) if one of the following is true: lim x-> +- inf. f(x)=b
vertical asymptote
x=a for f(x) if one of the following limits is infinite: lim x-> +- a f(x)
indeterminates
0/0 +- inf/+-inf 0(inf) 1^inf inf-inf
L'Hospital
0/0 inf/inf 0(inf) 1^inf

f(x)g(x)= f(x)/1/g(x)
f(x)^g(x)= e^g(x)ln(f(x))
Continuity def

and 3 things
lim x->a f(x)=f(a)

1. f(a) exists
2. the limit exists
3. 1 and 2 are the same number
IVT
if f is continuous on [a,b] and w is a number between f(a) and f(b), there isa t least one c in [a,b] so that f(c)= w

-if f is continuous, the range of a closed interval is an interval
-if f is continuous, and f(x1)>0, f(x2)<0, then there is a c between x1 and x2 where f(c)=0...at least one root
continuous vs differentiable
if f is differentiable at x=a, it is continuous at x=a. If f is continuous at x=a, we don't know if it is differentiable at x=a. That is, "all differentiable function are continuous, but not all continuous functions are differentiable."
Derivative def
f'(x)= lim h->0 f(x+h)-f(x)/h
inverses
if the point (a,b) is on the graph of f, then 1) the point (b,a) is on the graph of f^-1, and 2) f'(b)=1/f'(a)
Rolle's theorem
If f is continuous on [a,b] and f is differentiable on (a,b) and f(a)=f(b) then there is a c between a and b for which f'(c)=0
connection between root of a function and its derivative
-if f'(x) does not equal 0 on (a,b), then f(x) can have at most 1 root on [a,b]
-if f'(x)=0 has one solution on (a,b), the f can have at most 2 roots on [a,b]
-if f'(x)=0 has two solutions on (a,b) then f can have at most 3 roots on [a,b}
MVT def
if f is continuous on [a,b] and differentiable on (a,b) then there is a c in the interval (a,b) so that
f'(c)=f(b)-f(a)/b-a
The racetrack principle
if f(a)=g(a) and f'(x)>g'(x) for all x in [a,b] then f(x) >g(x) for x in [a,b]
linear approximation
the linearization of f at x=a is the tangent line approximation to f at x=a: y-f(a)=f'(a)(x-a)
differentials
delta y dy
if x changes from x to delta x, then there is a corresponding change in f:
delta y=f(x-delta x)-f(x)
dy=f'(x)dx
EVT
if f is continuous on [a,b] then f will attain a global max and global min on [a,b]. These points will be either at critical points or at endpoints
Local:
let x=a be a critical point of f
first and second derivative test
first derivative test:
-if f'(x) changes sign at x=a then we have a local min (- to +), or a local max (+ to -)
-if f'(x) does not change sign at x=a...

second derivative test:
-if f''(a)>0, we have a local min at x=a
-if f''(a) <0, we have a local max at x=a
-if f''(a)=0 the test is inconclusive
Global:
-on a closed interval: use EVT, build a chart using endpoints and critical points
-not on a close interval: if f'(x) only changes sign once at x=a, then x=a, y=f(a) is either a global min (-to+) or a global max (+to-)
Newton's method
f(x)=0 for x
xi+1=xi-f(xi)/f'(xi)
cf
cf'
f+-g
f'+-g'
fg
f'g+fg'
f(g(x))
f'(g(x))g'(x)
f/g
f'g-g'f/g^2
f(x)^g(x)
log diff
c
0
x^n
nX^n-1
e^x
e^x
a^x
a^x(ln(a))
ln|x|
1/x
loga(x)
1/x (1/ln(a))
sin(x)
cos(x)
cos(x)
-sin(x)
tan(x)
sec2(x)
sec(x)
sec(x)tan(x)
csc(x)
-csc(x)cot(x)
cot(x)
-csc2(x)
sin-1(x)
1/sqr(1-x2)
cos-1(x)
-1/sqr(1-x2)
tan-1(x)
1/1+x2
cf
cF
f+-g
F+-G
c
cx
x^n
1/n+1 (x^n+1)
1/x
ln|x|
e^x
e^x
cos(x)
sin(x)
sin(x)
-cos(x)
sec2(x)
tan(x)
sec(x)tan(x)
sec(x)
1/sqr(1-x2)
sin-1(x)
1/1+x2
tan-1(x)