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33 Cards in this Set

  • Front
  • Back
inverse functions
Let f and g be two functions. If

f(g(x)) = x and g(f(x)) = x,

then g is the inverse of f and f is the inverse of g.
quotient rule
used when dividing 2 functions or to find the derivative of a fraction

f(prime)(x)*g(x) - f(x)*g(prime)(x)
~OVER~
g^2
how to check limit answers
use TABLE to enter x values
limit of a constant is...
GENERALLY, that constant
how to find limits
factor> cancel> input limit
how to find infinite limits
divide all terms by biggest exponent> input 0 as limit
if left limit doesn't equal right limit...
the limit DNE
if there is a jump
the limit DNE
if there's a hole...
f(a) DNE, BUT the limit DOES exist
if there is a hole/jump...
it is not continuous at that point
IVT
Intermediate Value Theorem
Intermediate Value Theorem
to use this the func MUST:
-be continuous within boundaries
-change signs (+/-) from one endpoint to the other
root def
where the function crosses the x-axis
Marginal Cost Function
find 1st derivative> input x
derivative of: e^e(constant)
0; taken out of func
derivative of: sqrt(x)
written as: x^1/2
derivative: 1/2x^-1/2
derivative of: 4root(x)
can be written as: x^1/4
derivative: 1/4x^-3/4
when there is an exponent on the outside of a log/ln...
ln((x^2)-2)^1/2
bring it to the front of the log/ln
1/2 ln((x^2)-2)
derivative of: log/ln (x)
x'/x
Limit definition of the derivative
f(x+h)-f(x)
-OVER-
h
(x+h)^2
x^2 + 2xh + h^2

NOT JUST x^2+ h^2
when working limit definition of the derivative...
ALWAYS WRITE

lim
x->h
AROC
average rate of change
f(x1) - f(x0)
-OVER-
x1-x0
IROC
first derivative
critical values
where the function increases and decreases
to find critical values...

?
first derivative> take highest divisible number out in front> factor> reverse signs
to find inflexion points
after we find critical values
2nd derivative> set = 0
implicit differentiation
1st derivative> turn y into y-prime (unlike x that turns into 1)> always bring y-prime to the outside of the ()'s by itself> divide both sides by whats in the ()'s
inverse functions
must:
-strinctly be increasing or decreasing
-continuous
*polynomials = always continuous
inverse function of TANGENT LINE
find slope of tangent line(1st derivative) input given points into g'(y0)= 1
-OVER-
f'(x0) (or vica versa)
>input points into equation of tangent line
equation of tangent line
y-y0=m(x-x0)
elasticities
E=(p/x)(x-prime)

E <-1 it is inelastic (demand not sensitive to small change in P)
E > -1 it is elastic (D sensitive to small change in P)
E = -1 it is 'unitary elastic' (any change in P, D has exact change)
how to find Linear Approximation
first derivative> substitute point> gives slope> slope point form:
y-y0=M(x-x0)