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30 Cards in this Set

  • Front
  • Back
amphoteric
acts as either acid or base
define Ka and relate to pKa
Ka = equilibrium constant for acidic dissociation
-intrinsic property of acid

pKa = -log(Ka)
Ka = 10^(-pKa)
strong/weak/very weak acid by pKa and Ka
*substitute in base, Kb, pKb

strong acid:
Ka >> 1
pKa < 0

weak acid:
1 > Ka> 10^(-14)
0 < pKa < 14

very weak acid:
Ka < 10^(-14)
pKa. > 14
*weaker than H2O
relate acid and conjugate base strength
(qualitative and quantitative)
pKa (acid)+ pKb (conjugate base) = 14

strong acid/base had weak conjugate
weak acid/base usually have weak conjugates

heterolytic vs. homolytic cleavage
ionic vs. covenant bond breaking
oxyacid (relative strength)
*acidic H bonded to oxygen
*formed by hydration of non-metal oxide CO2 + H2O → H2CO3

1st : resonances electron withdrawal from central atom puts partial positive on acidic oxygen, increasing acidity
"excess oxygen count" =
#O - #H = # pi bond
*each added O decreases pKa by 5

2nd: inductive effect:
(if excess O is same)
more electronegative central atom will be more acidic
normality (N)
molar equivalents of H+: used to describe polyprotic acids

N for 1 M diprotic acid is 2 N
metal oxides and metal hydroxides
metal oxide (lewis base)
CaO + H2O → Ca(OH)2

metal hydroxide (bronsted base)
Ca(OH)2
non-metal oxides and non-metal hydrides
non-metal oxide (lewis acid)
SO3 + H2O → H2SO4

non-metal hydride (brownsted acid)
H2SO4
relative acidity strength (haloacids)
compare in period:
more electronegative = more acidic

compare in group:
larger ionic radius = more acidic
neutralization of lewis acid + lewis base
non-metal oxide + metal oxide→ neutral salt
SO3 + CaO → CaSO4 (s)
equations for pH of
1) either strong acid / base
2) either weak acid / base
3) both weak acid + weak base
1) dissociates / hydrolizes water completely
[H+] = mol acid

2) pH = 1/2 pKa - 1/2 log (HA)
pOH = 1/2 pKb -1/2 log (A-)

3) pH = pKa + log (base/acid)
*Henderson-Hasselbalch
*can use M or mols
*addition of H2O doesn't affect ratio of acid to base so dilution doesn't affect pH
relate pH and pOH
pH + pOH = 14
approximate pka of and physiological preference

carboxylic acid + carboxylate
amine + alkyl ammonium
H2PO4(-) + HPO4 (2-)
carbonate + bicarbonate

(phenol)
phenol pKa 9.5 -10.5

**pKa in lower range when R-group amino acid
diprotic and triprotic acid pKa / pKb relations

amino acids (pKa)
pKa1 + pKb3 = 14
pKa2 + pKb2 = 14
pKa3 + pKb1 = 14

*for a given pH, pay attention to which values are applicable

-amino acids with acid side-chains are triprotic
-amino acids with neutral side-chains are diprotic
(pKa for c-terminus = 2-3)
(pKa for n-terminus (ammonium)= 9-10)
pH estimates of polyprotic acid
-half equivalence point
-equivalence point
1st half equivalence point:
pH = pKa1

1st equivalence point:
pH = (pKa1 + pKa2) / 2
*this is not affected by initial concentrations
pH at half equivalence and equivalence point for weak acid/base (quantitative)
half equivalence: pH = pKa
(*HA = A- in HH equation)

equivalence point:
pH = (pKa (acid) + pKa (titrant)) / 2
pH of equiv point (qualitative)
-weak acid
-weak base
-strong acid/base
pH at equiv point for weak acid will be >7
pH at equiv point for weak base will be <7
pH at equiv point for strong base/acid will be =7
*consider conjugates
explain how buffer work
addition of OH- or H+ will convert weak acid or base to its conjugate which doesn't affect pH greatly

there is plenty of HA to A- and the ratio is close to 1 so little change in henderson-hasselbalch
2 ways to make a buffer
(pH considerations)
1) combine equal molar proportions of weak acid and its weak conjugate base (salt)

2) titrate a weak acid/base with 1/2 equivalents of strong base/acid
(half-equivalence point)

pick acid whose pKa is (+/-) 1 from desired pH
*carboxylic acid for pH 2-5
*amine for pH 8-11

*to work: acid:base ratio must not exceed 10:1 or 1 pH unit
respitatory acidosis
retention of blood CO2
blood pH drops
respiratory alkalosis
loss of blood CO2
increase in blood pH
metabolic acidosis
loss of HCO3(-)
blood pH drops
metabolic alkalosis
loss of H3O+
blood pH raises
shape of strong-strong titration curve and explanations
starts close to pH =0 with no initial changes in pH
*concentration of H+ is high so it takes a lot of titrant to make 10-fold ratio change

large pH vs. titrant slope at equivalence point
*H+ concentration is low so 10-fold difference takes little titrant
shape of weak-strong titration curve and explanations
-starting pH = (pKa - log(HA)) / 2

-"lip-o-weakness" initially there is a large slope because no buffering
*larger lip for weaker acid

-small pH change at and around half-titration point (pH = pKa) because of buffering
(HA : A- ratio changes slowest)

-sharp slope at equivalence point (lack of buffering)
pH = (pKa acid + pH titrant) / 2
*higher pH for weaker acid

-pH then dictated by titrant
Altering concentration of strong acid and weak acid (titrations)
*match with molarity of titrant
strong: different starting pH
same equiv point at 7

weak: different pH at equiv. point, (same amount of titrant to reach)
-different starting pH
-same half-equiv point pKa = pH
-picking an indicator to determine equivalence point
-indicator range
pH of equiv. point (+/-) 1 pKa of indicator

*pH equiv point =
(pKa acid + pH titrant) / 2

*less particular for strong-strong because of large pH range of equivalence point

indicators span 3 pH units with 3 colors

base : acid
10 : 1 color A
1 : 1 mix A + B
1 : 10 color B
log (1/x) =
-log(x)
effect of diluting a buffer
none