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7 Cards in this Set
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- Back
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how would calculate the risk of a woman being a carrier of x linked gene if she has an uneffected son?
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there were four outcomes:
carrier or non carrier x affected or unaffected son unaffected son is 1/2*1/2 = 1/4 for carrier or 1/2*1 for not carrier. so probability of her being carrier is outcome 1/4 divided by all possible outcomes that happened (1/4 + 1/2) = 1/3 |
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huntington example: joe had mother with huntington's and is now 50 years old with no symptoms (70% show symptoms by 50). what is his risk for having it?
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so inherited gene and no symptoms is 1/2 X .3 = 15% chance
no inherit and no symptoms 1/2 * 1 = 50% so those are his only two things right now. for carrier .15 for if he's carrier / (.15 + .5) for total current outcomes = 23% |
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what scenarios might be calculated with bayesian
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being tested for diseases, nonpenetrant disorders,
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what is binomial expansion formula
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n!
____ * (p^m q^n-m) m! (n-m)! |
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if looking at pedigree. arrow points to person of interest
or person asking u |
proband. person of interest. arrow with p
consultand. just arrow |
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twins denoted mono and di
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mono has extra line.
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brackets and dotted line
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bracket for adopted. dotted line to social parent
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