Weighted mean

Computations and Interpretation Mean = 7.02. After analyzing the scores of my population, I found that the mean average was 7.02 out of 10. This implies that the average student earned a “C” or 70% in the quiz. If I remove the outlier that consists of 0 out of 10 I believe that the average score would increase to a more meaningful average score. Median = 7. The median depicts how the center of all scores achieved was a “C”. The median may be a score or average of two, that is the farthest…

Part A. Socio-Demographic Characteristic Please write () in the appropriate column provided: 1. Gender Male ☐ Female ☐ 2. How old are you? 18-30 ☐ 31-40 ☐ 41-50 ☐ 51-60 ☐ > 60 ☐ 3. What is your marital status? Single ☐ Married ☐ Widowed/Separated ☐ 4. What is your educational degree? Illiterate ☐ Primary ☐ Secondary ☐ High school ☐ Post-graduate ☐ 5. What do you do for living? Student ☐ Unemployed ☐Self-employed ☐ Self-employed ☐ Government staff ☐…

Method: Although more or less, the end results were similar for all mental tasks performed on subjects under various categories as shown in all graphs of Chapter 6 and Fig B.1 to B.10 in appendix B, but for ease, mean accuracy chart is figured out here using all graphs and are shown next. The mean accuracy of BEEG using Confusion Matrix method (can be considered as standard method as most BCIs have used it for performance measure) is separately calculated in Chapter 6.2.2. The table below shows…

2-8- Statistical analysis Results are presented as mean±standard deviation (SD) of two replicated determinations. Data were subjected to one-way analysis of variance (ANOVA) and multiple comparisons were performed by Duncan's test. Statistical significance was set at P>0.05. All analyses were performed using SAS version 9.1 (PROC GLIMMIX; SAS Institute Inc., Cary, NC). 3. Results and discussion 3-1- physicochemical changes of grape juice contain encapsulated probiotics 3-1-1- pH According to…

Imprecision The lowest coefficients of variation for precision within and between series over the whole tested concentration range were found for the LIAISON CLIA and LC-MS/MS method. Then followed the RIA. The Immulite CLIA showed the highest overall values and thus the lowest precision. A detailed list of all calculated variation coefficients is provided in Table 1 (A). Sensitivity The limit of blank (LoB), limit of detection (LoD) and limit of quantification (LoQ) were determined for all…

eading Response # 1: Submit to Moodle 1. What is the commonly understood definition of gender difference? (max 100 words) /1 The term gender is generally thought of as a socially constructed difference between male and female. It is an identity or role associated with feminine and masculine traits that are prescribed based on one’s sex. When we see femininity, we assume female, as well, we see masculinity and we assume male. Gender is relational based and is defined by how we speak to and…

Question How does changing the size of the airplane affect how far the airplane goes. Hypothesis If we change the size of the airplane then the paper airplane will go further. Materials Paper, graph paper, meter stick, a pencil, Procedure: 1.I will build two identical paper airplanes. One will be my control airplane that is smaller and the other will be my test airplane the one that is bigger. 2.I will throw my control plane 10 times and I will use a meter stick to measure the distance of…

which are corrected, show that the rate of photosynthesis of a spinach/DPIP solution with translucent red filter was faster than the rate of photosynthesis of a spinach/DPIP solution with no filter. However, Fig. 3 and Fig. 4, which are expressed as means, show how…

Discussion: The distribution of each graph is quite comparable as they have similar means and standard deviation, where the preferred hand has a mean of 16.33 and a standard deviation of 2.842 whilst the non-preferred hand has a mean of 17.2 and standard deviation of 2.848. The normal distribution graph of each can be seen below: Preferred Hand vs. Non-preferred Hand: The graphs and boxplots (Figures 1.3- 1.6) seen previously in the results indicate that the two results did not have a normal…

Utilizing the information from the table above the mean, median and standard deviation will be calculated. The mean equals the average of the sample by adding all the values of the samples and then dividing by the total number of items. The mean for the samples collected is 14.87 ounces which rounded up 14.9 ounces. The median is calculated to be 14.8 ounces. The median is calculated by averaging the data in order and finding the midway point of the data set. Last to find is to find the…