Sea surface temperature

requires at least 6.8 hours at 1100 C. This requires a lot of time and energy for almost 7 hours continuously at 1100 C. With the surface concentration and the Dt product, we can calculated the initial dose for this Gaussian profile as Q=C(0,t) √(πD_t )=4*〖10〗^17 √π √(3.7*〖10〗^(-9) )=4.3*〖10〗^13 cm^(-2) This dose can be implanted in a narrow layer close to the surface, justifying for the implicit assumption of Gaussian profile that the initial distribution is the approximation of the delta…

considering the boiling point of ethanol is approximately 78 degrees Celsius. This is due to the fact that the mixture is a minimum boiling azeotrope (this is discussed in the next paragraph). But, once the temperature rose to 80 degrees, there was a very linear relationship between the temperature and the amount of distillate that was collected. This relationship was due to the fact that there was nothing stopping the impure vapors from condensation directly into the distillate. A similar but…

This was done to prevent any fracturing or pot lidding during the experiment. The temperature of the oven was raised 50 degrees Fahrenheit every hour or two depending on the batch. When the desired temperature of 350 degrees was reached, the temperature of the oven was then reduced every hour or two depending on the batch by 50 degrees Fahrenheit. Each batch was left out at room temperature to slowly cool. Once each batch was fully cooled they were assigned a sample number, to make…

The term Thermochemistry refers to when heat is evolved or absorbed during a chemical reaction. When calculating the amount of energy, the number will always be expressed as a positive number. A negative sign will indicate whether the energy is evolved or absorbed. If the sign is negative, then the energy is evolved and if the sign is positive, then the energy is absorbed. The amount of heat that is released or absorbed will also be in units of Joules or Kilojoules per mol. There are two other…

Evidence and Analysis: The literature Ksp for calcium hydroxide is 5.02×〖10〗^(-6), which is a relatively large Ksp value. This goes against the “rules of solubility” that labels calcium hydroxide as insoluble. According to the “rules of solubility”, calcium hydroxide should not be soluble in water; however, our results reveal that it does have some degree of solubility at standard conditions. We know this because we started with an initial concentration of calcium hydroxide and no concentration…

Case Study 1: 1.The most likely cause of the ABO typing discrepancy in the reverse type is due to “unexpected antibodies” such as a cold/room temperature reacting alloantibody. 2.Since the auto control didn’t agglutinate, an alloantibody is suspected. With that being said, it needs to be one that reacts at room temperature. Furthermore, based on the antigen typing of the patient P1 is suspected to be interfering with the ABO results. The Lewis antigen was ruled out due to it being present on…

caused by a warm surface giving up its heat to a cooler surface. Whenever there is a temperature difference between two surfaces, both surfaces will attempt to equalize. Radiant energy travels through space without heating the space itself. It only turns into heat when it contacts a cooler surface. Our human comfort relies just as much on radiant heat transfer as it does on air temperature, yet the majority of heating and air-conditioning professionals think only in terms of air temperature. As…

1. Cite everyday illustrations of the first and second laws of thermodynamics. How does the laws of thermodynamics underlie every organism’s ability to function? The first law of thermodynamics states that energy cannot be created or destroyed; however, it can be converted to other forms. An everyday illustration of the first law of thermodynamic is photosynthesis in which a plant uses sunlight, a form of light energy, to produce sugars that are assembled into glucose, which is a type of…

Paragraph 1 The crystal chemical relationship between quartz (SiO2) and FePO4 can be studied by putting them under a temperature range of 294K to 1073K in an attempt to study the evolution of their structures. In doing so, we would able to examine the other quartz homeotypes that emerge during high temperatures and known to show a-b transitions. This study of quartz homeotypes were essential because the new information that was gathered would aid greatly in the creation of new products and more…

Results: Figure 1; Repellent activity in percentage of the volatile extract of C. sinensis, C. limon, C. aurantifolia and positive control on Camponotus nearcticus. The activity was generally high on C. nearcticus with positive control recording 100% activity, C. limon having 95% and C. sinensis having the lowest activity of 82.5% activity. Figure 2; Observed percentage lethal activity of the volatile extracts on C. nearcticus at five concentration points after 180 minutes of exposure…