Reagent

Introduction: Microbiology is the study of all living microorganisms like bacteria, fungi, protozoans…etc, and non-living microorganisms like viruses, viroids and prions. The significance of identifying an unknown microorganism is first to understand what type of organism it is and what structures it has to help figure out their potential benefit, danger or even neutrality to humans. Physicians benefit from this by identifying what their patients are suffering from and how to treat them. Also…

(three to five times), and 2 mL of ECL™ Prime Western Blotting Detection Reagent (Biorad) was added to detect the peroxidase present. Types of antibodies Preparation ratio Β-actin 1:2000 Bax 1:1000 p53 1:1000 Cytochrome c 1:500 Caspase 8 1:2000 Table 1. The list of antibodies…

we could see the colour of the solution was changing from blue to black slowly. Not only that , but black precipitate settling at the bottom of the beaker. Equation : (s) + heat ---> CuO (s) + (l) Preperation of chloride complex Reagent Appearance Volume/Mass Concentration HCL Colorless Liquid 50 drops…

Selective acylation of nucleosides has also been carried out by N-acyltetrazole (Bhat et al., 1998) and carboxylic acids activated in situ with carbonyldiimidazole (Sinha et al., 1995). (7) N-Benzoyltetrazole has been developed as a mild and selective reagent for the monobenzoylation of the exocyclic amino groups in adenine and cytosine nucleobases (Bhat et al., 1997). In a related report, 1-acetyl-4-nitrobenzotriazole readily acetylated the exocyclic amine of cytidine (Reid et al., 2006). This…

Homogenates of liver were provided. The homogenates were made by homogenizing liver in a 1:20 w/v (1g: 20 ml) ratio in a sucrose-phosphate buffer, in which 250mM of sucrose and 50mM NaPO, with a pH of 7.4 were added. This information was used to conduct an experiment to determine the concentration of DNA, protein, and carbohydrates in different homogenate samples, including heart, liver, and kidney of Bos taurus, while also looking for the diverse protein sizes found in each homogenate sample.…

Purpose The purpose in this lab is to determine the presence of certain macromolecules made by cells by detecting carbohydrates, lipids and proteins with four different indicators. Materials Test tubes Test tube rack Benedict's solution Iodine Biuret reagent White paper Hot water bath Vegetable oil Glucose Sucrose Starch Protein Distilled water Post-lab questions A positive test for starch would be with iodine, because the starch turned black and opaque after the test and is the only…

During the phase and process of the bacterial unknown project, vast amounts of test were performed in order to determine an unknown species of bacteria. Within the many procedures of identifying the unknown bacteria, I was first given a tube with the unknown bacteria, from which later on I started subcultures by streaking bacteria from the original tube onto a tryptic soy agar (TSA) slant. Throughout the process of identifying the unknown, new subcultures were produced in order to use the newest…

barring exceptions should give a positive test for it (Harpercollege.edu 2015) . These give a positive test because hydrochloric acid dehydrates the carbohydrate to give an aldehyde . This aldehyde then condenses with phenol molecules in the Molisch reagent to give a coloured product which is most times purple or red. Based on literature all tested…

identifying reducing sugars, which are simple sugars that include monosaccharides and some disaccharides. The Benedict’s reagent is made of Copper (II) sulfate ion which reduces to Copper (I) during the test. It is made by adding copper sulfate with sodium citrate and carbonate that is dissolved in 400mLs of water (Benedict’s Test). The chemical reaction within this test is…

balanced equation for this reaction? 2 Which reagent is limiting? Explain why. 3 How many grams of hydrogen cyanide will be formed? Show your work. Answer: 1) 2 CH4 + 2 NH3 + 3 O2 = 2 HCN + 6 H2O 2) The reagent that is limiting is CH4. To get the moles of 10g of NH3, you divide 10 by 17 and that equals 0.58. To get the moles of 8g of CH4 you divide 8 by 16 and that equals 0.5. Because you have some more oxygen left over you have to find the limiting reagent. You divide the coefficient by the…