number of moles of hydrochloric acid neutralizes for the three trials (2,4,5) were calculated using stoichiometry. It was calculated for trial 2 by convert 4.88 mL NaOH to L by divide by 1000 mL. Then, to get to mol of NaOH the molarity of NaOH was multiplied by 0.00488. Then to get from NaOH to HCl, the mole ratio 2 HCl to 1 mol NaOH was multiplied by 0.00122. To get the amount of HCl per beaker, 100 mL of HCl was divided by 1000 mL to get 0.1 L. Then, the liters were converted to moles by…
When we calculated the number of moles of each reactant we also realized that once the moles of CaCl2 were more than the amount of moles in Na2CO3 the chemical reaction stopped producing product. What we concluded from the data was the reaction yield depends on the amount of starting material. The trend from this chemical reaction is…
To find the moles of Magnesium, dimensional was used to multiply the molar mass of Magnesium to its measured mass, the final result is 5.3475936 x 10-3 moles. 0.13g Mg×(1mol/(24.31g))=5.3475936×〖10〗^(-3) After adding Hydrochloric acid and been heated on the hot plate, the total mass of evaporating dish plus Magnesium Chloride is 44.96…
determine the concentration of acetic acid in vinegar using molarity and percent by mass of acetic acid in vinegar. This means, vinegar is a crucial solution of acetic acid (HC2H302) in water. Molarity (in mole/L), or mass percent expressed the concentration of the acetic acid in vinegar where; Molarity = Moles of Acetic Acid / Volume of Vinegar (in L). Mass % = [Mass of Acetic Acid / Mass of Vinegar] x 100. In this experiment, titration will be used to determine the concentration of…
bottoms. From here, the methanol/ethanol distillate traveled to another column (column 3) where it was distilled into two more pure streams (98 mole % methanol in the distillate and 98 mole % ethanol in the bottoms). The n-propanol/n-butanol mixture was also fed to another column (column 2) where it was separated into streams of 98 mole % n-propanol and 98 mole % n-butanol. A snapshot of our simulation is included below, followed by a ChemCAD-generated stream box that details the compositions of…
formula are added together you have calculated the molecular mass . 2 A ) calculate how many moles of water (H_(2 ) 0 ) there would be in 200 g Number of moles is calculated by the formula, mole = (mass of substance (grams))/(relative molecular mass/relative) (200 g)/(( 1.0079×2)+ (15.999)) = 11.102 mol No of moles = 11.102…
The first way is a skin examination, which is when a doctor or nurse looks for any unusual moles on the patient’s skin. If the doctor notices anything unusual, then the patient will undergo a skin biopsy. A skin biopsy is when a piece of the abnormal skin growth is removed and sent to a lab to search for any signs of melanoma. There are four types…
experiment, a NaOH solution was standardized with a primary standard acid of potassium hydrogen phthalate (KHC8H4O4) in order to determine the molar concentration of the NaOH solution.1 The standardized NaOH solution was then used to determine the moles, mass, and percent by mass of CH3COOH in a sample of vinegar. The vinegar used in the experiment was labeled as “Harry Potter”. The reported molar concentration of the NaOH solution was 5.42E-02 mol/L…
gas law had to be utilized and manipulated to find the volume and divide that volume by moles of magnesium. Being close to the theoretical value, 22.4L, it verifies that one mole of all gases occupy 22.4L in any container under standard temperature and pressure. This information could be valuable in many ways. For example, it proves Avogadro’s Law which states that at a standard temperature and pressure, one mole of any gas will occupy the same value which is 22.4L. Like a puzzle piece, once…
it to be completely titrated. The data collected from the experiment allowed each group to calculate the cost effectiveness of each brand of antacid. To do so we were required to calculate how many moles of HCl were neutralized by one antacid tablet. Next we were required to calculate how many moles could be neutralized by one bottle of a certain antacid; to do this…