Mixture

nitric acid into a 10 mL graduated cylinder. The concentrated nitric acid was placed into a reaction tube and clamped in the water bath. In step four, 1 mL of concentrated sulfuric acid was added slowly to the traction tube with nitric acid. Then the mixture was left to sit in the ice water bath for at least five minutes. A small plastic bag was filled with ice and a towel was wrapped around the bag. A towel was used to wrap the bag to insure that the bag was properly insulated. Then in step…

while you are using it. Now, for your ice-cream base. Remember, this is the fundamental mixture that you need to make a perfect ice cream. To make a perfect ice cream base: • The basic ratio to make a heavenly base is 2-8 yolks for 3 cups of dairy product. Adjust a number of egg yolks according to your desire. If you want a lighter base, decrease cream and yolks then put more milk. If you want a richer mixture, do the opposite. Yolks enhance the texture of your ice cream and act as an…

classify each sample as an element, a compound or a mixture. II. MATERIALS 10 beakers containing different samples of matter III. PROCEDURE First off, put on a laboratory apron. Then, take a few minutes at each lab station and record three physical property observations of each sample of matter. Record the three physical property observations in Column B on the table. Next, classify each sample as either an element, a compound, or a mixture in Column C. While classifying the samples, think…

BACKGROUND Ice cream is one of the Philippines’ most favored treats. Ice cream is so widely available that it is also sold in school cafeteria’s where children can have purchased them. It is a fact that ice cream isn’t exactly a health food. Its main ingredients are milk, cream, flavoring and the most important, sugar. Ice cream can be delicious but the downside of that is ice cream doesn’t provide us the nutrients the body needs daily. We believe that we can be able to…

Purpose The purpose of this experiment was to collect three different fractions of a mixture of hexane and toluene at differing temperatures. From there, the fractions would be measured via gas chromatography to discover the percent composition of hexane and toluene in each fraction with the ultimate goal of having one fraction with mostly hexane, one with mostly toluene, and one with an even mixture of the two. Along with this, there is also the goal of redistilling one of the fractions in…

around us is made up of either atoms, elements, molecules, mixtures or compounds. Atoms consist of three…

A mixture of two unknown liquids were obtained. The assigned mixture code was recorded in the notebook (#10). The mixture of the two miscible liquids contained a low boiling point and high boiling point. The method used to separate the two miscible liquids was simple distillation and therefore a simple distillation apparatus was set up. The apparatus included 250mL distillation flask, a 100ml receiving flask, a condenser for water to run through, and a thermometer to monitor the temperature. The…

Through both simple and fractional distillation an equimolar solution of ethyl acetate and propyl acetate was seperated. After distilling 20 mL of the mixture the samples were collected in fractions, which were then analyzed using gas chromatography. The mole ratios of the distillations were converted to a percentage to analyze percent composition. Simple distillation yielded the following results: S1- 69.88% EA/ 30.12% PA, S2- 66.73% EA/ 33.27% PA, and S3- 46.42% EA, 53.58% PA. Fractional…

Twenty kids one answer, who will figure it out. Everyone has been given the task to find the mystery mixture. At first they all had different clams. But now it is getting narrowed down. But there are some people that had different opinions. Everyone have been given water, a well tray, and a vial, along with other chemicals. I will explain how the class had gotten answer they did. And how they think it is right. The claim that will be explaining will be citric acid and baking soda. One of the…

but will generally create a mixture of two possible alcohols, the endo product and the exo product. In this case, the exo product will be the major product, which would be isoborneol and the endo product will be the minor product, which would be borneol.…