Hydrogen peroxide

I believe that “The Cosmological Argument” for God is still quite valid, my reasons for defending this argument have been produced after a great deal of reflection on the matter, I have concluded that the argument is still quite useful. To best describe the argument, it is the conclusion that “nothing comes from nothing” as was stated by St. Aquinas, in other words God must exist because if there was nothing then we needed something to “call it into existence” so to speak. This coincides…

Alkaline phosphatase catalyzes the hydrolysis and transphosphorylation of phosphomonoesters (1). A kinetic reaction scheme of AP is presented in Figure 2. Figure 2: Kinetic reaction scheme of alkaline phosphatase (11). Under the hydrolysis reaction, free phosphate and an alcohol molecule are released from the active site. The rate-determining step of this reaction is pH dependent. Transphosphorylation has similar initiate steps as hydrolysis. However, phosphate cannot exit the active site,…

4.2 Resources CO2 Fig.1 depicts the principle of chemical energy transmission system. Fig.2 explain the Eva-Adam process. 5. Thermodynamics of CO2 reforming of methane It is essential to understand the thermodynamic of CDRM represents as follow: CH_4+CO_2 □(→) 2CO+〖2H〗_2 ∆H_298=247 KJ⁄(mol ) (1) ∆G^o=61770-67.32 T This reaction above is highly endothermic which is favored by low pressure but, requires a higher temperature. A reverse…

than N-H bonds. This is because the O-H bond is more electronegative because the electronegativity of O is 3.44 while the electronegativity of N is only 3.04. I2(s) → I2(l) London Dispersion Forces H2O(s) → H2O(l) London Dispersion Dipole-Dipole Hydrogen Bonding NaI(s) → NaI(l) Ionic bonds C16H32(s) → C16H32(l) London Dispersion Forces There was no conductivity observed for ionic compounds in the solid state but there was a high conductivity observed for ionic compounds as an aqueous…

Ivacaftor, C24H28N203, is a 4-oxoquinoline-3-carboxamide molecule which consists of five main functional groups: a quinolone, an amide, a phenol, and two tert-butyls. Quinolones are regularly found in anti-biotics, amides are seen in the synthesis of nylon, phenol can be retrieved from coal tar, and tert-butyl groups are big hydrophobic groups found in tert-butyl alcohol (the simplest tertiary alcohol); none of these functional groups were invented or developed first by the parent company of the…

Title Determining the Empirical Formula of Magnesium Oxide Introduction Chemical formulas imply the arrangement of compounds. Empirical formulas are the simplest whole number ratio of the elements present in a compound (Owen, 2014). However, the actual amount of each type of atom that a compound is consisted of is called the molecular formula. For that reason, the deduction of the empirical formula and the molar mass of a compound is required to determine the molecular formula of the compound.…

References: 1. Catalytic Reduction of p-Nitrophenol and Hexacyanoferrate (III) by Borohydride Using Green Synthesized Gold Nanoparticles, G. Bhagavanth Reddy.; D. Ramakrishna,; A. Madhusudhan,; D. Ayodhya,; M. Venkatesham and G. Veerabhadram*.Journal of Chinese Chemical Society. 17, 2015; 420-428. 2. G.Bhagavanth Reddy,; A. Madhusudhan,; D. Ramakrishna,;D.Ayodhya,;M. Venkatesham.; G. Veerabhadram,; Green chemistry approach for the synthesis of gold nanoparticles with gum kondagogu:…

The space group for α-FePO4 is P3121, with the lattice symmetry being tetrahedral in shape. On the other hand, the space group for β-FePO4 is P6422, with the lattice symmetry being hexagonal in shape. In this writing assignment, FePO4 is studied at varying temperature ranging from 294K to 1073K by neutron powder diffraction. At a relatively low temperature, it adopts the structure of the α-quartz. However, at high pressures, it changes and it can be observed that it becomes a denser…

Mn2+ Divide into two half reactions. Identify the element that is being oxidized and the other being reduced. (Use the entire ion or molecule.) Step 2 Oxidation: S2-  S0 Reduction: MnO4-  Mn2+ Balance all the elements (other than oxygen and hydrogen). Step 3 Oxidation: S2-  S0 Reduction: 8H+ + MnO4-  Mn2+ + 4H2O Balance O and H. The oxidation requires neither O nor H, but the reduction equation needs 4H2O on the right and 8H+ on the left. Step 4 Oxidation: S2-  S0 + 2e- Reduction:…

Water and ethanol both have dispersion forces and hydrogen bonding while kerosene only has dispersion force. It means to say that there is a greater energy needed in order to break the bond that holds the molecules together. In conclusion, intermolecular forces increase direct proportionally with increasing polarization. It should also be noted that the arrangement of the strength of intermolecular forces increase from dispersion, dipole-dipole, hydrogen bonding, to ion-dipole. Lastly, the…