Continuous probability distribution

Each powder mixture has unique characteristics, and so have a unique optimization curve to achieve an acceptable state of uniformity and particle size distribution. Many blending units are available which offer differing shear, convective and dispersion properties on the powder bed. Convective forces refer to large groups of particles moving in an orthogonal direction to the axis of rotation. Dispersion…

Particle size distribution Introduction The purpose of this lab was to determine the particle size distribution of a particular soil sample by carrying out sieve analysis and hydrometer analysis tests. For the sieve analysis test, a graph for percent finer versus the grain size was plotted from the data collected. The graph was used to determine whether the soil sample was fine-grained or course-grained. Calculations for uniformity and gradation were then done to determine whether the soil was…

questions 1-4 Given the results of the chi square, the birds feeding behavior are not the same.The birds are acting randomly when it comes to behaviors at the feeding stations. The chi square at 14 degree of freedom equals 49.99 , with the probability set at 0.05, the chi-square was bigger than the critical value. This data rejects the null hypothesis which states that there will be no significant difference between the observed and expected portions of birds at the feeding stations. So,…

Chi- Square Goodness of Fit Testing Assuming Equal Expected A handful of students loves numbers and selects a major in Finance, Statistics, or Marketing. While others prefer a major in Leadership or are undecided. Historically, the MBA program at Whatsamatta U has about 40% of their students electing Leadership as their major, 30% selecting Finance as a major, 20% choosing Marketing, and 10% are undecided. Conducting a Chi-Square Goodness of the Fit Test revealed that the class of 200 students…

testing, the critical value is a number that separates a region where the null hypothesis will not be rejected from a region where it will be rejected. It is achieved at a particular percentile range and is then determined using a chart, known as the distribution topic.” The equation below states the critical value at 5% significance level: C.95 =21.026 * The .95 is taken from 100%-5%=95% *The 12 is from the degrees of freedom Lastly, I found what conclusion could be drawn regarding the…

Pectin yield was determined as weight of dry pectin against the weight of initial residues multiplied by 100%. Y=100(P/Bi) Where Y is the extracted pectin yield (%), P is the amount of extracted pectin in grams and Bi is the initial amount of sweet potato residues used to extract pectin. Equivalent weight and Degree of methoxylation The equivalent weight was determined according to the method by Barretina et al., (Barretina et al. 2012). 0.25g pectin was wetted with 5ml ethanol and topped…

Drosophila Melanogaster, or better known as the common fruit fly, is found all over the world and referred to as the cosmopolitan species (Mitrick, 2010). This fruit fly has three main body parts, which include the head, the thorax, and the abdomen. On males, the bottom half of the abdomen is black, while on the female, each segment of the abdomen is striped black. Drosophila have four main stages to their life cycle. These include: egg, larva, pupa and adult. The eggs small and translucent eggs…

Hypothesis This study attempts to assess two research hypotheses. Our hypothesis answers the research question, what difference, if any, can be found between the two concentration when describing dissertation characteristics? Our first hypothesis (H1) states that clinical track dissertations are more likely to be experimental than administrative track dissertations. Our second hypothesis (H2) states administrative track dissertations are more likely to have advanced statistical analyses than…

built-in LA-950 Horiba software. The particle volumetric diameters were expressed as D10, D50 and D90, indicating the diameter under which 10%, 50% and 90% of the sample resided. Following equation was used to calculate the broadness (span) of size distribution. All measurements were done in triplicate for each…

Results In the lab, 478 trials were conducted using a total of 956 crickets. The 478 pairs resulted in 264 wins for the resident cricket and 214 wins for the intruding crickets. These results produced a chi squared value of 5.230. The p-value calculated from this lab was .022. A chi squared value of .022, less than the benchmark of .05 means the data from the lab was significant and statistically rejects the null hypothesis that there was no correlation between residency and aggression…