Concentration

question of whether an increase in a succinate concentration (a component of the Krebs cycle) will lead to an increased rate of cellular respiration within a cell. We measured the amount of electrons given off by the succinate to fumerate redox reaction by using DPIP. DPIP is an electron acceptor that takes the place of FAD by accepting the electrons and turning from its oxidized blue state to its reduced clear state. We had three tubes with varying concentrations of succinate and measured the…

experience. This was a reality for millions of Jews that experienced life in concentration camps. During World War II, life in concentration camps was grim and left little hope for the Jews’ survival. They were forced to live in horrific conditions, forced to perform hard labor which oftentimes meant working in a state of starvation until death overtook them, and constantly faced execution. Living conditions in concentration camps can be described as horrific. Captive Jews mostly lived in…

stimulates cell whose contents are hypotonic to its environment. The situation is because the concentration of the dissolved substances in the cell is less than the surrounding media. In this case, the cell contents contain 1% sucrose solution that is less concentrated than the 50% surrounding media. Therefore, a large concentration gradient develops between the two media. Consequently, because of the high concentration gradient, the bag loses water faster and this leads to its reduction in…

had to be diluted to get the lower number. The maximum time to dilute solution in this experiment was 2. According to the Beer-Lambert Law, the absorbance changes correspond to the concentration. It expresses the relationship between the light absorbance and concentration. As the absorbance increases, the concentration also increases. The equation of the baseline is also the Beer-Lambert equation. The coordinate…

located in the cell membrane. Diffusion could also be described as the movement of molecules from areas of high concentration to areas of low concentration. The molecules do this because all molecules are constantly moving, so in enough time the molecules will spread evenly. According to figure 1, the cell will make the outside solution the same concentration of water as the concentration on the inside. In higher temperatures the faster diffusion will happen because of the increase in kinetic…

Osmosis can pull water out of the cell if the cell is placed in an environment with a higher solute concentration. 3. Osmosis can pull water into the cell if the cell is placed in an environment with a lower solute concentration. Explanation The experiment revealed that when a cell is placed in a solution that contains the same solute/water concentration as in the cell itself, there is no change in the appearance of the cell. This can be explained by the fact that water moves…

investigating osmosis in potatoes. Four different solutions were created (distilled water, 1% salt (NaCl), 3% salt and 5% salt. The potatoes were sliced until they were 3cm long, each test tube contained 3 strips of potato cores and a different concentration. The potato strips were weighed and the results recorded. The potato cores were left in each solution for 24 hours. Once the test results were collected the data was averaged and placed into a graph and a table. As shown in both the table…

of different potassium ion concentrations. Similar to the first part, the concentration of HC4H4O6- was calculated through titrations of 0.05 M KCl and 0.1 M KCl solutions with known NaOH concentrations. The total concentration of K+ for the solutions with the common ion is equal to the K+ concentrations from the KCl solutions and the K+ concentration from the KHT itself, which is equal to the concentration of HC4H4O6-. A scatter plot graph that compares the concentrations of K+ and HC4H4O6- for…

dialysis cells appeared smaller after adding sugar water and secondly, to prove our hypothesis that water molecules move out of the cell because the concentration of water is greater than inside the cell than it is outside the cell. This experiment was conducted with one control group and one experimental group. The independent variable was the concentration of water, (water and glucose solution). The dependent variable was the size of dialysis cells afterward the lab, measured by the mass and…

along with the Km and the Vmax from series A, the Ki of Series B and C were calculated. The concentration of inhibitor for 50mM lactose was found to be 35714 μM using equation 1. Similar to the substrate concentration, the inhibitor concentration can be found using the same equation, but substituting in the inhibitor molar concentration and volume in place of substrate information. The inhibitor concentration was used along with the slope of series B to find Ki. A sample calculation is shown…