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14 Cards in this Set
- Front
- Back
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Question
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Answer
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Na⁺NH₂⁻"
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"Converts alkyne to ionized product:
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HC≡CH + Na⁺NH₂⁻ → HC≡C⁻Na⁺"
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Br‚ÇÇ"
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Breaks DB and puts Br on α Carbon
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Br‚ÇÇ"
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Puts a Br trans on each α Carbon
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"What does it do to an dibromonated alkane
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H‚ÇÇBrC-CBrH‚ÇÇ?
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NH‚ÇÉ(l)"
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Two dehydrohalogenations to give alkyne
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What about two additions?"
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"Br on α Carbon
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H‚ÇÇO‚ÇÇ
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NaOH"
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H‚ÇÇO‚ÇÇ
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NaOH"
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HgSO‚ÇÑ"
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Tautomer on more substituted Carbon
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Pd"
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Hydrogenates alkyne to alkane
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Lindlar"
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Cis Hydrogenates alkyne to alkene
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NH‚ÇÉ(l)"
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Trans hydrogenates to alkene
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