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765 Cards in this Set
- Front
- Back
Classify as correct organism type : influenza |
virus |
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Classify as correct organism type : tinea |
fungus |
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Classify as correct organism type : red tide |
algae |
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Describe why some soil organisms may produce antimicrobial substances |
Because they are in competition with othermicrobes. |
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Briefly outline how a GMO can be created to produce insulin |
The genetic information from pigs tocreate insulin was copied to the genetic code of yeast, with was then bread toproduce insulin in large quantities |
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Give microbial examples of nitrogen cycling |
Legume plants (eg lentils, peas) have bacteriapresent in their root nodules that convert nitrogen from the atmosphere (N2)into fixed nitrogen the plants can use for growth (NH3) |
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Give microbial example of carbon dioxide cycling |
Microorganisms take part in nutrient cycling, e.g. of carbon and sulphur, convert these elements into forms that can be taken up by plants Carbon dioxide sink |
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Briefly explain how ruminants contribute to global warming |
Methane produced by their gut microbes as a biproduct breaking down cellulose |
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Define bioremediation |
Some microorganisms will break downpollutants, such as oil, pesticides and solvents |
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Explain how stromatolites contribute to a liveable planet |
The oxygen present in the atmosphere isdue to microbial activity – by photosynthetic cyanobacteria that first existedmore than 3.5 billion years ago |
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Briefly describe why microbes evolve so quickly |
Microbes have a very short life cycle compared to larger organisms, so have more chances to mutate in the same time frame. |
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Describe why the human body is an ecosystem |
9 out of 10 cells in a human body are not ‘human’ cells, but are instead microbes, mostly bacteria. |
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. Give examples of biofilms |
Moss growing on a rock Staphylococcus growing on a catheter Plaque build up on the surface of teeth A colony of Staphylococcus growing on a nutrient agar plate |
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Explain factors that limit uncontrolled growth of microbes |
5. Limits on food, space and energy |
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State the dimension of a staphylococcal cell |
Up to 1 µm in diameter |
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Explain why a virus is not a cell |
Viruses do not replicate independently,only replicate once they have infected another cell. Have no ribosomes. Rely onthe host cell for protein production. |
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List features that make viruses different from bacteria |
Bacteria – have ribosomes, cell walls, can replicate, larger (c. 1000nm), treated with antibiotics Viruses – no ribosomes or cell walls, need other cells to replicate, have DNA or RNA enclosed in a coat of protein, smaller (c. 20-400nm), treated with an antiviral. |
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Describe how the genetic information is arrangedin bacterial cells |
Circular genome in a nucleoid. Many haveplasmids (extrachromosomal circular DNA) with genes that have particularproperties eg. Antibiotic resistance. |
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Explain the origin of mitochondria |
A bacterial cell was engulfed by an ancient eukaryotic cell, they developed a symbiotic relationship (endosymbiosis) |
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Explain how Pasteur disproved spontaneous generation |
With an experiment with swan necked flasks and the boiling of samples showed that samples remained sterile unless contaminated. |
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Describe an experiment to prove an organism causes a specific disease |
5. Koch’s Postulates: 1. Microorganisms are isolated from a deadanimal 2a.microorganisms are grown in pure culture2b.microorganisms are identified 3. microorganisms are injected into a healthyanimal 4. disease is reproduced in the second animal,microorganisms are isolated from this animal 5a. these microorganisms are grown in pureculture 5b. identical microorganisms are identified |
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Hershey and Chase experiment |
Did not know if DNA or Protein entered the E. coli cells to produce new phage particles •grew T2 in either - 35S labeled protein or 32P labeled DNA •infected E.coli with T2 - briefly separated E.coli and T2 •DNA of the virus infected the host cell •Protein remained outside the cell |
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The transforming principle |
The transforming principle wasan early name for DNA. In1928, scientists didn't know yet that DNA carried genetic information, but theyknew that there was something that could cause bacteria to transform fromone type to another. |
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The transforming principle |
The transforming principle wasan early name for DNA. In1928, scientists didn't know yet that DNA carried genetic information, but theyknew that there was something that could cause bacteria to transform fromone type to another. |
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Avery, MacLeod and McCartney experiments |
They purified and treated heat killed Streptococcus pneumonia bacteria to determine the chemical nature of the “transforming principle” -Treated four mixtures of polysaccharides, proteins, DNA and RNA with enzymes to degrade one of those macromolecules - Only DNA transformed non pathogenic bacteria into pathogenic |
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basic nucleotide structure |
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. the difference betweenpurines and pyrimidines |
Purinesand Pyrimidines are nitrogenous bases that make up the two differentkinds of nucleotide bases in DNA and RNA. -Purines -The two-carbon nitrogen ring bases(adenine and guanine) - Pyrimidines - one-carbon nitrogen ring bases (thymine and cytosine) |
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. the difference between purines and pyrimidines |
-Purines -The two-carbon nitrogen ring bases(adenine and guanine) - Pyrimidines - one-carbon nitrogen ring bases (thymine and cytosine) |
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the base pairing rules |
A=T G=C (A=U for RNA) |
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Chargaff’s rules |
DNA from any cellof all organisms should have a 1:1 ratio (base Pair Rule) of pyrimidine and purine bases- G=C and A=T |
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Chargaff’s rules |
DNA from any cellof all organisms should have a 1:1 ratio (base Pair Rule) of pyrimidine and purine bases- G=C and A=T |
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DNA replication process as it occurs at the replicating fork |
During DNA replication a DNA double helix must unwind and separate -DNA polymerase enzymes use each single strand as a template for the synthesis of a new double strand. - Strand separation is catalyzed by a Helicase enzyme. |
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leading strand |
synthesized in the 5’-3’direction (direction the same as the replication fork movement) -it is synthesized continuously; there are no breaks in-between. -it is formed as nucleotides are continuously added to the 3’ end of the strand after polymerase reads the original DNA template. |
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lagging strand |
-the strand which is synthesized in the 3’-5’ direction (oppositeto the movement of the replication fork) -It grows or is synthesized away from the fork. - it is synthesized in fragments. -The primase, which is responsible for adding an RNAprimer, has to wait for the fork to open before putting in the primer. -The lagging strands have fragments of DNA which are calledOkazaki fragments. |
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DNA polymerase |
enzymes which are responsible forsynthesizing DNA -add nucleotides one by one to the growing DNAchain - require a template and a primer (starter) -synthesize DNA in the 5' to 3' direction. |
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DNA ligase |
a DNA-joining enzyme. -If two pieces of DNA have matching ends, ligase can link them to form a single, unbroken molecule of DNA. |
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proofreading, |
During DNA replication (copying), most DNApolymerases can “check their work” with each base that they add. -If the polymerase detects that a wrong(incorrectly paired) nucleotide has been added, it will remove and replace thenucleotide right away, before continuing with DNA synthesis |
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telomeres. |
Eukaryote chromosomes have telomeres at the ends (t-loop model) •telomeres do not contain genes •telomeres contain multiple repeats of short nucleotide sequence •100-1000 copies of repeats •repeat sequences are evolutionarily conserved •in humans & all vertebrates repeat sequence is 5’- TTAGGG -3’ |
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What type ofmicroorganism is the primary cause of Tinea? (a) Bacteria (b) Fungus (c) Virus (d) Archaea (e)Parasite |
b) fungus |
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The use of microorganisms to break down pollutants is known as: (a) bioinformatics (b) bio recycling (c) bioprocessing (d) bioremediation (e) biosynthesis |
d) bioremediation |
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Which of the following best describes why some soilmicroorganisms produce antimicrobial substances? (a) To protect themselvesfrom other microorganisms (b) To improve soil quality (c) To inhibit the growth of othermicroorganisms (d) To aid the production ofbiofilms (e) To inhibit the growth ofviruses |
c) to inhibit the growth of other microorganisms |
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Which of the following is not an example of a biofilm? (a) Moss growing on a rock (b) Staphylococcus growing on a catheter (c) Plaque build upon the surface of teeth (d) Algal growth of the surface of the water in a swimming pool (e) A colony of Staphylococcus growing on a nutrient agar plate |
d) Algal growth on the surface water in a swimming pool |
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Which of the following is not true about bacterial cell walls? (a) Maintain cell shape (b) Prevent the cell from bursting (c) Attachment site for appendages such as flagella (d) Contain peptidoglycan (e) The gram-negative cell wall is thicker than the gram-positive cell wall |
(e) The gram-negativecell wall is thicker than the gram-positive cell wall |
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Which of thefollowing is not a eukaryotic cell? (a)Algae (b)Tinea mould (c)Giardia (d)Yeast (e) Influenza |
e) influenza |
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Which of the following is not a eukaryotic cell?
(a)Algae (b)Tinea mould (c)Giardia (d)Yeast (e) Influenza |
e) influenza |
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Prokaryoticcells have evolved quickly due to:(a) Mitosis (b) Meiosis (c) Binary fission (d) Endocytosis (e) Apoptosis |
c) Binary fission |
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A news paper report describes that the salmonella virus is the majorcause of food poisoning. This: (a)is correct as salmonella virus is the major cause of food poisoning (b) is incorrect as E. colicauses more cases of food poisoning (c) is correctas viruses are members of the flora of the intestine (d) isincorrect as salmonella does not cause food poisoning (e) isincorrect as salmonella will respond to antibiotics so can’t be a virus |
e) is incorrect as salmonella will respond toantibiotics so can’t be a virus |
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A news paper report describes that the salmonella virus is the major cause of food poisoning. This:
(a)is correct as salmonella virus is the major cause of food poisoning
(b) is incorrect as E. coli causes more cases of food poisoning
(c) is correct as viruses are members of the flora of the intestine
(d) is incorrect as salmonella does not cause food poisoning
(e) is incorrect as salmonella will respond to antibiotics so can’t be a virus |
e) is incorrect as salmonella will respond to antibiotics so can’t be a virus |
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Which of the following diseasesis caused by a virus? (a)Wound infections (b)Cold sores (c)Anthrax (d)Red tide (e) Giardia |
b) cold sores |
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Which of the following diseases is caused by a virus? (a)Wound infections (b)Cold sores (c)Anthrax (d)Red tide (e) Giardia |
b) cold sores |
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A polymorph is about 10 times wider than astaphylococcal cell. Therefore a polymorphs width is:(a) 1 nm (b) 1 um (c) 1 cm (d) 10 nm (e) 10 um |
e) 10um |
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Viruses differ from bacteria because viruses:
(a) are true cells
(b) have a cell wall
(c) do not contain genetic material
(d) only grow on selective agar plates
(e) are not able to metabolise |
e) are not able to metabolise |
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A scientistwishes to prove an organism is the cause of stomach ulcer. The scientist: (a) should not experiment with this as stresscauses stomach ulcers (b) should grow the organisms from thestomach and feed them to rabbits (c) should grow the organisms from thestomach and feed them to mice as these are model organisms for human diseases (d) study and isolate a single organismbefore finding an animal model to test (e) not bother as the stomach is too acid forany type of bacteria to grow |
(d) study and isolate a single organism before finding an animal model to test |
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A scientist wishes to prove an organism is the cause of stomach ulcer. The scientist:
(a) should not experiment with this as stress causes stomach ulcers
(b) should grow the organisms from the stomach and feed them to rabbits
(c) should grow the organisms from the stomach and feed them to mice as these are model organisms for human diseases
d) study and isolate a single organism before finding an animal model to test
(e) not bother as the stomach is too acidic for any type of bacteria to grow |
(d) study and isolate a single organism before finding an animal model to test |
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Viruses: (a) are the most primitive type of cell (b) are not able to infected bacteria (c) causeinfections that can sometimes be treated with chemotherapy (d) canonly divide when inside cells (e) allof the above |
c) cause infections that can sometimes be treated with chemotherapy |
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Extrachromosomal DNA that can replicate independently of the hosts chromosome are known as: (a) Plasmids (b) Phages (c) Ribosomes (d) mRNA (e) Histones |
a) Plasmids |
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Which of the following names does not represent a genus of bacteria? (a) Esherichia (b) Epidermidis (c) Staphylococcus (d) Pseudomonas (e) Klebsiella |
b) Epidermidis |
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In Pasteur’s experiment with the swan necked flask he: (a) Proved the theory of Spontaneous generation (b) Proved the theory of Spontaneous generation was incorrect (c) Discovered endospores were extremely resistant to heat (d) Discovered that a specific organism was required to cause a specific disease (e) Discovered pure cultures of pathogen could be obtained from an animal with a specific disease |
(b) Proved the theory of Spontaneous generation was incorrect |
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Outline when a light microscope and electron microscope are useful |
Light microscopes look at whole cells, electron microscopes look at internal cellstructures and viruses |
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resolution |
The smallest distancebetween two points where you can see the two dots are separate. |
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identify the limit ofresolution for most light microscopes |
Lightmicroscopes have a limit of resolution of ~ 0.2 mm = 200 nanometres (nm) |
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Explain why immersion oil is used forlight power light microscopy |
. increases the light-gathering ability of the lens - oil removes light diffraction |
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Name the parts on a lightmicroscope |
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Explain why immersion oil is used for light power light microscopy |
. increases the light-gathering ability of the lens - oil removes light diffraction |
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Contrast gram-positive andgram-negative cell wall structure |
Gram-positive cell walls have a thicker layer of peptidoglycan -Gram-negative cell walls have a complex, multilayered structure -Gram negative bacteria contain an outer membrane in addition to peptidoglycan - Made up of phospholipid, protein and polysaccharide, often called the lipopolysaccharide layer or LPS -The main function is to provide cell structure, LPS is often toxic to animals – known as endotoxin |
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Explain what is meant by 'heat fixation’ |
heat fixing causes the cells to adhere to the glass slide,
the heat kills most of the cells |
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the importance of endotoxin |
Endotoxin is often toxic to animals if the bacteria is destroyed (ie. by sterilisation) |
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why Mycoplasma spp. areimportant |
Some bacteria and archea exist without cell walls – -known as spheroplasts or protoplasts -One important group are the mycoplasmas -Smallest organisms capable of independent growth - Parasitic, many are pathogenic, resistant to lysozyme and cannot be killed with antibiotics such as penicillin and vancomycin because they lack a cell wall |
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Identify bacterial cell morphologies and arrangements |
round in shape are called cocci cylindrical are called rods (bacilli)
Some rods are curved or spiral
some bacteria remain in groups: chains and clusters Some are: -filamentous, form long, thin cells have tapering ends (fusiform), - branching |
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Outline the steps formaking blood agar |
Shave and apply antiseptic to the surface of the animal blood is to be collected from -collect the blood while avoiding contaminating it as much as possible -put it in cold to prevent contaminants multiplying -cool sterilised agar -add blood to agar aseptically to prevent airborne contaminents |
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the importance of endotoxin |
Endotoxin is often toxic to animals if the bacteria is destroyed (ie. by sterilisation) |
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Which of the following cannot be viewed with a light microscope? a. Influenza virions b. E. coli c. Giardia cysts d. Yeast cells e. Bacillus Endospores |
a. Influenza virions |
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The ability to see two objects as being separate is known as: a. Refraction b. Illumination c. Magnification d. Resolution e. Focus |
d. Resolution |
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Outline the steps for making blood agar |
Shave and apply antiseptic to the surface of the animal blood is to be collected from
-collect the blood while avoiding contaminating it as much as possible
-put it in cold to prevent contaminants multiplying
-cool sterilised agar
-add blood to agar aseptically to prevent airborne contaminents |
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Prokaryotic cells range in size from: a. 0.01 - 0.3 μm b. 0.3 - 5 μm c. 5 - 10 μm d. 10 – 15 μm e. 15 – 20 μm |
b. 0.3 - 5 μm |
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. To increase the magnification of a specimen using a light microscope you: a. Move to an objective lens with a higher aperture b. Move to an objective lens with a lower aperture c. Move the stage up d. Move the stage down e. Increase the intensity of light |
a. Move to an objective lens with a higher aperture |
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. To increase the magnification of a specimen using a light microscope you:
a. Move to an objective lens with a higher aperture b. Move to an objective lens with a lower aperture c. Move the stage up d. Move the stage down e. Increase the intensity of light |
a. Move to an objective lens with a higher aperture |
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7. Oil immersion is used in light microscopy to: a. Increase the light gathering ability of the lens b. Reflect light away from the objective c. Protect the stain from rubbing off the slide d. Lubricate the objective lens to prevent damage e. View internal cellular structures |
a. Increase the light gathering ability of the lens |
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8. Which of the following is not a part of the Light microscope? a. Ocular b. Condenser c. Objective lens d. Fine focus adjustment knob e. Course focus lens |
e. Course focus lens |
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The Gram stain is a useful differential technique in bacteriology because it exploits differences in bacterial: a. Capsules b. Plasma membranes c. Cell walls d. Plasmids e. All of the above |
c. Cell walls |
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What is the correct order of steps in the Gram stain? a. carbol fuschin, iodine, acetone, crystal violet b. carbol fuschin, acetone, iodine, crystal violet c. crystal violet, acetone, iodine, carbol fuschin d. crystal violet, iodine, acetone, carbol fuschin e. crystal violet, carbol fuschin, acetone, iodine |
d. crystal violet, iodine, acetone, carbol fuschin |
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What is the role of acetone in the Gram stain? a. Fixation of bacteria to the slide b. Traps the crystal violet-iodine complex in the gram-negative cell wall c. Removes the crystal violet-iodine complex from gram-positive cells d. Removes the crystal violet-iodine complex from gram-negative cells e. Decolourises gram-positive and gram-negative cells |
d. Removes the crystal violet-iodine complex from gram-negative cells |
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12. A major constituent of gram-positive cell walls is: a. Peptidoglycan b. An outer membrane c. Lipopolysaccharides d. Lipoproteins e. Enterotoxin |
a. Peptidoglycan |
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13. Why is it important to incubate Petri dishes upside down? a. Plates need to be incubated upside down for bacteria to grow b. Prevents condensation from dripping on the agar c. Allows condensation to accumulate on agar d. It makes stacking multiple plates easier e. So that bacteria do not penetrate the agar |
b. Prevents condensation from dripping on the agar |
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Which of the following describes a gram-positive and gram-negative microorganism? a. Staphyloccus aureus and Streptococcus pyogenes b. Staphyloccus epidermidis and Bacillus subtilis c. Streptococcus pyogenes and E. coli d. Giardia lamblia and E.coli e. None of the above |
c. Streptococcus pyogenes and E. coli |
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15. Penicillin works by: a. Dissolving the outer membrane of prokaryotic cells b. Inhibiting protein synthesis c. Interfering with the strength of peptidoglycan d. Causing DNA to coagulate e. Initiating mutations in genetic material |
c. Interfering with the strength of peptidoglycan |
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16. Mycoplasmas differ from most bacteria because they: a. are not pathogenic b. do not have a cell wall c. do not have a cytoplasmic membrane d. do not carry the metabolic machinery required for replication e. can only be grown in a cell culture |
b. do not have a cell wall |
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17. A smear made from an infected wound reveals lots of pus cells contains gram-positive cocci in chains the most likely cause of the infection is: a. Bacillus subtilis b. Clostridium tentani c. Staphyloccus aureus d. Staphyloccus epidermidis e. Streptococcus pyogenes |
e. Streptococcus pyogenes |
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18. A patient is diagnosed with a urinary tract infection caused by Staphyloccus aureus . What would you see in a Gram stain? a. Clusters of gram-positive cocci b. Chains of gram-positive cocci c. Gram-negative bacilli singularly and in small chains d. Gram-positive bacilli in small chains and clusters e. Gram-positive filamentous rods |
a. Clusters of gram-positive cocci |
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Why is streak plating an important technique in microbiology? a. It allows you to see separate colonies from a mixture b. It allows you to see if you have a pure culture c. It allows you to calculate the number of microorganisms in a sample d. (a) and (b) are correct e. All of the above are correct |
d. (a) and (b) are correct |
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A component of the outer membrane of gram-negative bacteria the often triggers an inflammatory response in animals and humans is known as: a. Mycotoxin b. Aflatoxin c. Endotoxin d. Exotoxin e. Enterotoxin |
c. Endotoxin |
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Should the air holes of the Bunsen Burner be opened or closed? |
open |
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What is the hottest part of the flame? |
which is at the tip of the blue part of the flame. |
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Why do we flame the slide before using it? |
To get rid of any grease or marks on the glass that may interfere with the stain sticking to it. |
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What is the first stain used on the smear, and what is its colour? |
Crystal Violet.( Purple) |
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What is the last stain used and what is its colour? |
Dilute carbol fuchsin. (Dark pink.) |
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How long is the acetone on the slide for? |
No longer than 2 seconds. |
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Why do you work close to the bunsen burner during aseptic technique |
To reduce the risk of aerial contamination of our work. |
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Where is the lid of the bottle we are subculturing from kept? |
Held in our hand by our little finger |
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What is the " primary inoculum"? |
The area of the plate where the material ( on a loop or swab) is spread out over approximately 1/3 to 1/4 of the agar. |
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When is the loop flamed during aseptic technique? |
Between each set of streak lines. |
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lambda |
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1. You are about to pick up a petri dish that contains a culture of bacteria (Staphylococcus aureus) known to cause a wound infection. Before picking up the agar plate you should: a) -make sure the lid is on the petri dish b) put a dressing on any cuts on hands c) all of the above d) wash your hands e) put on gloves |
b) puta dressing on any cuts on hands |
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A student contaminates their families food preparation area at home with bacteria from their laboratory practical. The most likely reason for this was a) the student sucked the end of their pen in class b) the student was infected with the bacteria during the prac class c) the student used their mobile phone during the class d) the student coughed in the food preparation area e) the student breathed in the bacteria during the prac class |
c) thestudent used their mobile phone during the class |
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Sodium hyperchlorite is used in the laboratory to a) clean microscope lenses b) to sanitise the air c) wash hands before leaving the laboratory d) wipe benches before leaving the laboratory e) to put out fires |
d) wipebenches before leaving the laboratory |
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a) The only type of disposal bag that should be used in the laboratory b) The bag where all experimental materials should be placed c) Special bag for sharps d) the disposal bag for paper waste e) disposal suitable for non-sharp experimental materials |
e) disposal suitable for non-sharp experimental materials |
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a) is suitable for use in laboratories for disposal of paper towels used to dry washed hands b) should not be used in laboratories c) has the wrong bin liner in it d) is suitable for all disposable laboratory materials e) can be used for all laboratory plastics |
a) issuitable for use in laboratories for disposal of paper towels used to dry washed hands |
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Glass slides can be placed in a) laboratory waste with petri dishes b) laboratory autoclave bins with recyclable glass c) the plain waste bins d) the yellow autoclave bags e) the yellow sharp bins |
e) theyellow sharp bins |
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a) should not be used in laboratories b) is a fire hazard in laboratories c) should be disposed of in a biohazard bag after cleaning up a spill d) should be used to line the laboratory bench e) should be disposed of in biohazard bags after drying hands |
c) should be disposed of in a biohazard bag aftercleaning up a spill |
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Which of the following is incorrect? a) Practical books should be kept separate from cultures on the bench b) Practical books should not be near the bunsen burner c) The paper clip should be disposed of in a sharps container as it may break bags used for disposal d) Anything disposed of in the laboratory should go into hazardous waste e) Pages of your laboratory records can be removed and discarded |
d) Anythingdisposed of in the laboratory should go into hazardous waste |
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Should glass slidesbe placed in this container? a) Yes, if disposed of in autoclave bags they could puncture the bags and thus injure people carrying the bags b) No, they should be recycled c) No, this container is for needles only d) No, they should be placed in the autoclave bin e) No, they should be put with paper waste |
a) Yes, if disposed of in autoclave bags they couldpuncture the bags and thus injure people carrying the bags |
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When washing hands, you should wet your handsbefore adding liquid soap to your hands a) No, because it dilutes the liquid soap b) No, because you will contaminate the soap c) Yes, because the liquid soap may be irritating to hands d) Yes, because you need less soap e) Yes, because the water activates the liquid soap |
c) Yes, because the liquid soap may be irritating to hands |
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During a prac class you accidentally burn your hand. It is only a minor burn and it no longer hurts. You should a) Still place your hand under cold water even though it has stopped hurting b) tell your partner c) tell your demonstrator d) record the details of the incident so that your demonstrator can file an incident report e) all of the above |
e) all of the above |
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Which is a better surface disinfectant, 70% alcoholor 1% hypochlorite solution? a) Alcohol because it is very good at killing bacteria and viruses b) Hypochlorite because it is very good at killing bacteria and viruses c) Alcohol because it evaporates quickly d) Hypochlorite because it evaporates quickly e) Neither should be used as a surface disinfectant |
b) Hypochlorite because it is very good at killingbacteria and viruses |
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In prac class you spill a bacterial culture on the bench. You should a) Order an evacuation b) Call the demonstrator so that the demonstrator can clean it up c) Put on gloves and use a paper towel to mop up the excess liquid and dispose of this paper in the metal bin d) Put on gloves and use a paper towel to mop up the excess liquid and dispose of this paper in the paper bin e) Put on gloves and use a paper towel to mop up the excess liquid and then surface disinfect the area with 70% alcohol |
e) Put on gloves and use paper towel to mop up the excess liquid and then surface disinfect the area with 70% alcohol |
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During prac class your lab partner cuts open their hand. The first thing you should do before bandaging the cut is a) Wash the hand with soap and warm water b) Don't wash the hand as it will allow bacteria to enter the cut c) Use the alcohol on the bench to disinfect the cut d) Use the hypochlorite on the bench to disinfect the cut e) Call a demonstrator |
a) Wash the hand with soap and warm water |
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Which of the follwoing best describes hand washing? a) most effective if hands dried thoroughly b) apply soap to dry hands to stop dilution c) avoid using paper towels as they are not effective d) solid soap is better than liquid soap e) wash hands at the beginning and end of lab classes |
a) m ost effective if hands dried thoroughly |
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Which is a better surface disinfectant, 70% alcoholor 1% hypochlorite solution?
a) Alcohol because it is very good at killing bacteria and viruses b) Hypochlorite because it is very good at killing bacteria and viruses c) Alcohol because it evaporates quickly d) Hypochlorite because it evaporates quickly e) Neither should be used as a surface disinfectant |
b) Hypochlorite because it is very good at killing bacteria and viruses |
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What must you always wear in a microbiology laboratory? a) hat, shoes and apron b) gown, googles and a hat c) shoes, gown, gloves d) gown, shoes and mask e) shoes, gown and sometimes goggles |
e) shoes, gown and sometimes goggles |
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When are gloves worn in a microbiology laboratory? a) When working with agar plates b) Always when performing staining procedures c) When working with blood and body fluids d) When using a bunsen burner e) All of the above |
c) When working with blood and body fluids |
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What should you do if you get some staining chemicals in your eye? a) Scream uncontrollably b) Hide your disfugured (stained) face from your partner c) Ask for your partners assistance to find the eye wash d) Put your hand up and hope the demonstrator doesn't take too long to see you e) Complete the facial decoration by using some other stain colours |
c) Ask for your partners assistance to find the eye wash |
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Which enzyme Prevents DNA from tangling up as the replication fork migrates during replication?
a) DNA helicase b) DNA gyrase c) DNA polymerase III d) DNA polymerase I e) topoisomerase |
b) DNA gyrase |
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Watson and Crickproposed the ________ model of DNA replication. a) conservative b) semiconservative c) dispersive d) semidispersive e) semidiscontinuous |
b) semiconservative |
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In the semiconservative model of DNA replication, progeny double helices consist of a) one parental DNA strand and one new strand. b) two new DNA strands. c) two parental DNA strands. d) one parental DNA strand and one new RNA strand. e) two new RNA strands. |
a) one parental DNA strand and one new strand. |
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Which of the following is required for the synthesis of DNA during replication? a) dNTPs b) magnesium ions c) template DNA d) DNA polymerase e) all of the above |
e) all of the above |
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During replication, the direction of synthesis of new DNA from the leading strand is a) 5' to 3' only. b) 3' to 5' only. c) from left to right only. d) both 5' to 3' and 3' to 5' e) none of the above |
a) 5' to 3' only |
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During replication, the direction of synthesis of new DNA from the lagging strand is a) 5' to 3' only. b) 3' to 5' only. c) from left to right only. d) both 5' to 3' and 3' to 5' e) none of the above |
a) 5' to 3' only. |
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In the bacterium Escherichia coli, DNA replication is a) unidirectional and dispersive. b) bidirectional and semiconservative. c) unidirectional and semiconservative. d) dispersive and semiconservative. e) bidirectional and dispersive. |
b) bidirectional and semiconservative. |
|
Prior toreplication, the DNA double helix must be untwisted by which type of enzyme? a) helicase b) primase c) polymerase d) topoisomerase e) ligase |
a) helicase |
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At the growing endof a DNA chain, DNA polymerase catalyzes the formation of a ________ bondbetween nucleotides. a) hydrogen b) disulfide c) glycosidic d) phosphodiester e) phosphate |
d) phosphodiester |
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When do you stop wearing a lab gown? a) When the boss walks into the laboratory b) When the temperature of the laboratory rises to uncomfortable levels c) When experiments are finished and you are writing up results d) When required to answer a phone e) When in the corridor outside the laboratory |
e) When in the corridor outside the laboratory |
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In Escherichia coli, replication begins at which chromosome site? a) ori b) the replication fork c) att d) the RBS e) none of the above |
a) ori |
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Okazaki fragmentsare made from the ________ strand of the DNA double helix. a) leading b) lagging c) conservative d) continuous e) dispersive |
b) lagging |
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After removal ofthe RNA primers, Okazaki fragments are joined through a reaction that involveswhich enzyme? a) DNAprimase b) DNA polymerase c) DNAligase d) RNApolymerase e) DNAhelicase |
c) DNA ligase |
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After a region ofDNA has been replicated, ________ removes the RNA primers. a) DNApolymerase I b) DNApolymerase II c) DNApolymerase III d) DNAhelicase e) DNAprimase |
a) DNA polymerase I |
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Which of thefollowing enzymes plays an important role in DNA replication? a) DNApolymerase III b) DNAhelicase c) DNAligase d) DNAprimase e) allof the above |
e) all of the above |
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In eukaryotes, chromosomes are duplicated during which stage of the cell cycle? a) G1 b) S c) G2 d) M e) C1 |
b) S |
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In eukaryotes, DNA replication a) is initiated at several sites on chromosomes. b) occurs bidirectionally. c) is semidiscontinuous. d) all of the above e) none of the above |
d) all of the above |
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The number of replicons in a typical Escherichia coli cell is a) 1. b) 10. c) 100. d) 1,000. e) 10,000. |
a) 1 |
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In eukaryotes,which enzyme is responsible for replicating the ends of the chromosomes? a) DNApolymerase I b) telomerase c) DNAprimase d) RNApolymerase e) DNAgyrase |
b) telomerase |
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In eukaryotes, DNA replication begins at a) a single origin of replication on each chromosome. b) a single origin of replication for each nucleus. c) multiple origins of replication on each chromosome. d) all of the above e) none of the above |
c) multiple origins of replication on each chromosome. |
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In eukaryotes, DNA replication is a) unidirectional. b) bidirectional. c) semiconservative. d) both A and C e) both B and C |
e) both B and C |
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An ARS isthe site of origin of replication in a) E.coli b) yeast c) Drosophila d) humans e) allof the above |
b) yeast |
|
In eukaryotes,which enzyme is responsible for replicating the ends of the chromosomes?
a) DNA polymerase I b) telomerase c) DNA primase d) RNA polymerase e) DNA gyrase |
b) telomerase
|
|
The ________ geneencodes wild-type DNA polymerase in E. coli. a) dnaB b) polA c) oriC d) polAex1 e) exoIII |
b) polA |
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Which enzyme activityis associated with DNA polymerase I? a) 5'to 3' exonuclease b) 3'to 5' exonuclease c) 5'to 3' polymerase d) bothB and C e) allof the above |
e) all of the above |
|
The ________ gene encodes wild-type DNA polymerase in E. coli.
a) dnabB b) pol A c) ori C d) pol Aex1 e) exoIII |
b) polA |
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________ prevents the separated strands of double stranded DNA from reannealing during replication. a) DNA polymerase b) DNA primase c) Single strand binding protein d) Topoisomerase e) Reverse transcriptase |
c) Single strand binding protein |
|
In E. coli, theerror rate associated with replication is a) 1/1,000,000,000 b) 1/1,000,000 c) 1/100,000 d) 1/10,000 e) 1/1,000 |
a) 1/1,000,000,000 |
|
In eukaryotes, a replicon is a) asingle chromosome. b) theentire genome. c) thedistance between adjacent origins of replication. d) thedistance between the origin of replication and the termination of replication. e) oneDNA strand of a single chromosome. |
d) the distance between the origin of replication and the termination of replication. |
|
Some bacteria are motile because they have: a) Pili b) Fimbriae c) Flagella d) Plasmids e) Capsules |
c) Flagella |
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When flagella are attached at many sites around the surface of a prokaryotic cell they are called: a) Lophotrichous b) Peritrichous c) Monotrichous d) Polar e) Atrichous |
b) Peritrichous |
|
If a bacterium is monotrichous this means: a) The cell has plasmid b) The cell can travel in one direction only c)The cell has one flagellum d)The cell is not motile e) The cell is covered in fimbriae |
c)The cell has one flagellum |
|
The presence of motility is demonstrated in the Cragie tube test by: a) The production of gas bubbles b) A colour change c) Growth at the site of inoculation only d) Growth/Turbidity throughout the medium e) Growth of single colonies |
d) Growth/Turbidity throughout the medium |
|
What cellular structure possessed by N. gonorrhoeae allows it to adhere to host membranes and cause infection? a) A capsule b) Fimbriae c) Flagella d) Endotoxin e) Plasmid |
b) Fimbriae |
|
Which of the following cellular components allows genetic material to be transferred by conjugation? a) Fimbriae b) Flagella c) Cell wall d) Pili e) Phages |
d) Pili |
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You perform a hanging drop motility test on Klebsiella and you see the cells moving around the same spot. This indicates: a) The bacteria are motile b) The bacteria are motile but may have come from an old culture c) The bacteria have short flagella and cannot move far d)Flagella may have been damaged by shaking the culture too forcefully e) Brownian motion |
e) Brownian motion |
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What is Brownian motion? A) Bacterial motility in the direction of an attractant b) Bacterial motility away from a repellent c)Bacterial motility in random directions d) Refers to the rotating action of flagella e) Occurs when molecules in a solvent bump into bacterial cells |
e) Occurs when molecules in a solvent bump into bacterial cells |
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The movement of bacteria in the direction of light is known as: a) Photosynthesis b) Phototaxis c) Brownian motion d) Chemotaxis e) Streaming |
b) Phototaxis |
|
The conversion of a spore to a vegetative cell is known as: a) Germination b) Vegetation c) Sporulation d) Phosphorylation e) Transformation |
a) Germination |
|
Telomerase iscomposed of a) proteinonly. b) proteinand RNA. c) proteinand DNA. d) RNAand DNA. e) proteinand lipid. |
b) protein and RNA. |
|
At the growing endof the DNA chain, DNA polymerase catalyses the formation of a ........ bondbetween nucleotides. a) hydrogen b) disulfide c) glycosidic d) phosphodiester e) phosphate |
d) phosphodiester |
|
DNA was shown to be the genetic material by a) Watson and Crick b) Hershey and Chase c) Gierer and Schraam d) Mirsky and Reis e) Beadle and tatum |
b) Hershey and Chase |
|
DNA and RNA both contain
a) phosphate b) ribose c) guanine d) both A and C e) all of the above |
d) both A and C |
|
DNA and RNAmolecules are composed of a) aminoacids b) nucleotides c) phospholipids d) fattyacids e) monosaccharides |
b) nucleotides |
|
DNA polymeraseenzyme is capable of adding incoming dNTPs in the following fashion: a) 5'to 3' only b) 3'to 5' only c) both3' to 5' and 5' to 3' d) fromleft to right only e) noneof the above |
a) 5' to 3' only |
|
In a molecule ofDNA, hydrogen bonds form between a) adenineand cytosine b) guanineand adenine c) adenineand uracil d) cytosineand thymine e) thymineand adenine |
e) thymine and adenine |
|
In a molecule of DNA, hydrogen bonds form between a) adenine and cytosine b) guanine and adenine c) adenine and uracil d) cytosine and thymine e) thyminea nd adenine |
e) thymine and adenine |
|
In a molecule of DNA, hydrogen bonds form between a) adenine and cytosine b) guanine and adenine c) adenine and uracil d) cytosine and thymine e) thymine and adenine |
e) thymine and adenine |
|
In thebacterium Escherichia coli, DNA replication is a) unidirectionaland dispersive b) bidirectionand semiconservative c) unidirectionaland semiconservative d) dispersiveand semiconservative e) bidirectionaland dispersive |
b) bidirectional and semiconservative |
|
In the semiconservativemodel of DNA replication, progeny double helices consist of a) oneparental DNA strand and one new strand b) twonew DNA strands c) twoparental strands d) oneparental strand and one new RNA strand e) twonew RNA strands |
a) one parental DNA strand and one new strand |
|
The number ofpurine molecules in a molecule of DNA is ............. to the number ofpyrimidines. a) greaterthan b) lessthan c) equalto d) exponentiallylarger than |
c) equal to |
|
The pentose sugarin RNA is a) dextrose b) ribulosebisphosphate c) ribose d) deoxyribose e) ribulose |
c) ribose |
|
Which DNA base isconsidered a purine? a) adenine b) cytosine c) uracil d) thymine e) allof the above |
a) adenine |
|
Which RNA base is apyrimidine? a) cytosine b) thymine c) uracil d) bothA and C e) allof the above |
d) both A and C |
|
Five different types of bacteria are exposed to UV radiation for 90 seconds. Which would you expect to survive? a) A gram-negative cell such as E. coli b) A gram-positive cell such as Staphylococcus c) A gram-negative environmental isolate of Serratia d) A water loving gram-negative isolate of Pseudomonas e) A spore-forming bacteria such as Bacillus |
e) A spore-forming bacteria such as Bacillus |
|
Mycolic acids prevent Gram stain penetration and are found in the cell walls of: a) Staphylococcus b) E. coli c) Mycobacterium d) Bacillus e) Streptococcus |
c) Mycobacterium |
|
Mycobacterium can best be described as: a) gram-positive bacilli b) gram-negative bacilli c) acid-fast bacilli d) resistant to all stains because their cell wall is full of lipids e) lacking a cell wall |
c) acid-fast bacilli |
|
The loose unstructured arrangement of glycocalyx around a prokaryotic cell is known as: a) A slime layer b) Capsule c) Peptidoglycan d) Biofilm e) Cell wall |
a) A slime layer |
|
Which of the following is not true about biofilms?
a) They grow on surfaces b) They are associated with nosocomial infections through their growth on medical devices c) Help bacteria resist host immune system defences d) They are easily removed by physical forces e) They protect bacteria from the effect of antibiotics |
d) They are easily removed by physical forces |
|
Which of the following helps to protect a bacterium from phagocytosis by the hosts immune system: a) Peptidoglycan b) Capsule c) Cell membrane d) Pili e) Endospores |
b) Capsule |
|
Which of the following is not true regarding bacterial endospores? a) Produced inside a vegetative cell b) Consist of several layers c) Are able to stay dormant for years d) Contain dipicolinic acid e) Contain a greater water content then vegetative cells |
e) Contain a greater water content then vegetative cells |
|
Endospores are advantageous to the bacteria because: a) They increase the pathogenicity of the microorganism b) They protect microorganisms from being attacked by a hosts immune system c) They are extremely resistant to heat d) They allow a microorganism to survive when environmental conditions are not favourable e) Both (c) and (d) are most correct |
e) Both (c) and (d) are most correct |
|
In a Gram stain you see gram-positive bacilli that contain unstained regions the microorganism. This could be: a) A capsule around Staphylococcus b) A capsule around Streptococcus c) A spore inside Clostridium d) Slime around E. coli e) Slime around Pseudomonas |
c) A spore inside Clostridium |
|
What is the function of peptidoglycan in prokaryotic cells: a) Carbon storage as an energy source b) Water storage preventing cells from becoming dehydrated c) A buffer maintaining pH of the cell d) Adds strength and shape to the cell wall e) Allows bacteria to float |
d) Adds strength and shape to the cell wall |
|
DNA primase is an enzyme that catalyzes the reactions necessary to synthesize a molecule of: a) RNA. b) DNA. c) protein. d) lipid. e) carbohydrate. |
a) RNA. |
|
During replication, the role of DNA primase is to a) untwist the double helix at the origin of replication. b) synthesize the primosome. c) synthesize a short chain of RNA. d) add nucleotides to the growing DNA chain. e) relax the supercoiling of the double helix. |
c) synthesize a short chain of RNA. |
|
Distinguish between bacterial structures harboured by most cells from those only in select species |
Most bacteria have: Chromosome, cytoplasmic membrane, ribosome, cell wall. Some bacteria have: flagellum, capsule/slime layer, pili/fimbriae, endospore |
|
Give examples of types of glycocalyx illustrate by example how bacteria use it |
1. Capsule/slime layer. Thecapsule/slime layer enables bacteria to attach to surfaces and to form biofilms Encapsulated bacteria are more difficult for the immune system to recognise anddestroy |
|
Outline the benefits to bacteria and the disadvantages to humans of biofilms |
1. Biofilm formation allows cells to resist physicalforces of removal, to resist attack by host immune system, protects fromthe action of antibiotics |
|
During replication, the role of DNA primase is to
a) untwist the double helix at the origin of replication. b) synthesize the primosome. c) synthesize a short chain of RNA. d) add nucleotides to the growing DNA chain. e) relax the supercoiling of the double helix. |
c) synthesize a short chain of RNA. |
|
Fimbriae |
-Fimbriae enable bacteria to attach to surfaces such as animal tissues (mucosa of mouth, GIT etc) and also to form biofilms |
|
pili |
Pili involved in genetic transfer between bacteria via conjugation, alsothought to be involved in attachment |
|
types of bacterial flagella |
7. -Monotrichous- Lophotrichousflagella -arranged as a tuft of flagella on one end of the cell -Polarflagella - attached at one or both ends -Peritrichousflagella - arranged at many locations around the cell |
|
How flagella is involved in movement |
enabled by flagella rotation (similar to propeller rotation) -The motor thatrotates the flagellum made up of a rod surrounded by a series of rings |
|
Describe two different ways to detect motility |
7. hangingdrop test -Fresh cultures of live,unstained bacteria used, so cells will be transparent and more difficult to see -Semi-solid agar media(e.g. Craigie tube) can be used: -Motile bacteria willshow diffuse growth through the tube, media will be opaque throughout the tube -Non-motile bacteria willonly grow at the inoculation point, the rest of the media will remaintransparent |
|
Brownian motion |
not motility, caused by bacteria colliding withwater molecules |
|
Brownian motion |
not motility,
caused by bacteria colliding with water molecules |
|
True motility |
bacteriawill move in different directions, not all in the same direction |
|
endospore |
-a cell created within the vegetative cell highly resistant to: - heat/cold, -dehydration, -UV radiation -chemicals - Bacterial endospores can remain dormant for many years |
|
vegetative cell |
Bacterial cell which produces endospores |
|
List some features of endospores |
7. can remain dormant for many years, - don’t stain with basic microbiological dyes - A mature endospore contains 10-25% of the water content of a vegetative cell, -cytoplasm forms a gel which, helps in heat resistance - -Spores are activated e.g. by heat, will germinate rapidly in presence of certain nutrients, outgrow to form vegetative cells |
|
Explain why we use an acid-fast stain to microscopically see Mycobacteria spp. |
surfacelipids of mycolic acid are not readily gram-stained |
|
What genus of pathogenic bacteria often appear asgram-positive cocci: in clusters? In chains? |
Clusters – staphylococci Chains – Streptococci |
|
What is the most common error that occurs whenselecting a colony for subculture? |
A mixture of colonies is selected not a pure culture |
|
How can you tell gram-positive from gram-negative organisms? |
Gram positive stain purple
Gram negative stain pink |
|
Explain why we use an acid-fast stain to microscopically see Mycobacteria spp. |
surfacelipids of mycolic acid are not readily gram-stained |
|
How can capsules be seen microscopically? |
Capsules do not stain can sometimes be seen as clear area in a stain |
|
What is the most common error that occurs when selecting a colony for subculture? |
A mixture of colonies is selected
not a pure culture |
|
What is the purpose of iodine in the Gram stain? |
1. Fixing the first stain |
|
How can spores be distinguished from vegetative forms of bacteria? |
Spores are more resistant to taking up aqueous stains.
Canbe found inside vegetative cells |
|
List the order of stains used in the Gram stain(the red stain can be simply called a counter-stain as various red/pink dyes can beused). |
Stain, iodine, acetone, counterstain |
|
Why do we need to wait until the gram-stained smear is completely dry? |
so that the oil canbe added for viewing under the microscope |
|
Why is it important to separate mixed culture to pure cultures? |
Pure culture is important to study the characteristics of the organism of interest. |
|
Garrod’s study on ‘inborn errors of metabolism’ |
studied people whose urine turned black on exposure to air alkaptonuria) -found that it is genetically inherited disease -postulated that symptoms were a reflection of the individuals inability to make a particular enzyme -a normal person has an enzyme which breaks down alkapton (homogentisic acid) - alkaptonuric individuals lack the enzyme
-first to suggest that genes dictate phenotype through enzymes |
|
Beadle and Tatum’s experiment with Neurospora |
•treated conidia with X-rays (mutagen) •crossed the conidia with prototrophic strain of opposite mating type •this ensured genetic basis of inheritance •one ascospore per cross was cultured on complete media sub-cultured into different tubes •strains that grew only when supplemented with amino acids were sub-cultured into different tubes supplemented with individual amino acids •thus, strains that were mutants for particular amino acids were identified |
|
One gene-One enzyme hypothesis |
function of the gene was to dictate production of a specific enzyme |
|
5. Phenylketonuria (PKU) |
–1/12,000 Caucasian births –Mutation in Phenylalanine hydroxlase gene –Prevents conversion of Phe to Tyr –Phe accumulates and converted to phenylpyruvic acid –Pleiotropic effects: no thyroxine, adrenaline, melanin –Can be managed with dietary restrictions |
|
Phe |
Phenylalanine |
|
Beadle and Tatum’s experiment with Neurospora |
•treated conidia with X-rays (mutagen)
•crossed the conidia with prototrophic strain of opposite mating type
•this ensured genetic basis of inheritance
•one ascospore per cross was cultured on complete media sub-cultured into different tubes
•strains that grew only when supplemented with amino acids were sub-cultured into different tubes supplemented with individual amino acids
•thus, strains that were mutants for particular amino acids were identified |
|
Lesch-Nyhan syndrome |
•Fatalrecessive human trait •1/10,000males •Deficiencyin hypoxanthine-guanine phosphoribosyltransferase –Purinesaccumulate and convert to uric acid •Severeneurological symptoms |
|
Tay-Sachs Disease |
•Rare in general population but more frequent in Ashkenazi Jews –1/3,600 •Gene defect in Lysosomal enzyme •hexA encodes N-acetylhexosaminidase A - Cleaves group from brain ganglioside GM2 •Symptoms – reaction to sharp sounds & cherry-coloured spot on the retina, loss of mobility, early death |
|
Sickle-Cell anemia |
•Recessive mutation •Hemoglobin transports oxygen in blood •Mutation in gene that produces polypeptide of hemoglobin •Hemoglobin different to normal •Red blood cells change shape–sickled shape •Sickle-cell trait–Less severe form of the disease |
|
Cystic fibrosis |
•Most common lethal disease among Caucasians –1/2000 newborns–1/23 are carriers •Causes pancreatic, pulmonary and digestive dysfunction –High viscosity mucus •cystic fibrosis transmembrane conductance regulator (CFTR) –1,480 amino acid long membrane protein •serves as Chloride channel –Deletion of 3 bases – one amino acid missing –∆F508 |
|
Alterations in genes do what to proteins |
can result in alteration in proteins. |
|
Sickle-Cell anemia |
•Recessive mutation
•Mutation in gene that produces polypeptide of hemoglobin
•Red blood cells change shape–sickled shape
•Sickle-cell trait–Less severe form of the disease |
|
Streak dilution isused to isolate strains of bacteria. This means a) tubesof agar are stabbed and organisms are grown b) bacteriaare isolated by double-dilution using a series of test tubes c) bacteriaare spread over the surface of agar plates so that single colonies are obtained d) brothcultures are used to grow bacteria e) biochemicaltests are used to isolate bacteria |
c) bacteria are spread over the surface of agar plates so that single colonies are obtained |
|
In order todetermine whether a culture is mixed, the most important step would be to a) lookat a microscopic preparation b) seeif there was evidence of different colony morphologies on agar c) testto see the antibiotic susceptibilities d) runbiochemical tests on the predominant strain e) usedifferent stains to see if reactions were different |
b) see if there was evidence of different colony morphologies on agar |
|
In order to determine whether a culture is mixed, the most important step would be to
a) look at a microscopic preparation
b) see if there was evidence of different colony morphologies on agar
c) test to see the antibiotic susceptibilities
d) run biochemical tests on the predominant strain
e) use different stains to see if reactions were different |
b) see if there was evidence of different colony morphologies on agar |
|
When viewed under oil-immersion,bacterial width appears to the eye on average around how many millimetres wide? a) 0.5 b) 1 c) 1.5 d) 2 e) 5 |
b) 1 |
|
To determine if aplate culture of bacteria is pure you need to see if a) thereare different sizes of bacteria down the microscope b) thereare different shapes of bacteria down the microscope c) thereare different gram-stained bacteria down the microscope d) colonieshave different sizes on the agar e) anydifferent colony types are on the agar |
e) any different colony types are on the agar |
|
Streak dilution is used to isolate strains of bacteria. This means
a) tubes of agar are stabbed and organisms are grown
b) bacteria are isolated by double-dilution using a series of test tubes
c) bacteria are spread over the surface of agar plates so that single colonies are obtained
d) broth cultures are used to grow bacteria
e) biochemical tests are used to isolate bacteria |
c) bacteria are spread over the surface of agar plates so that single colonies are obtained |
|
To determine if a plate culture of bacteria is pure you need to see if
a) there are different sizes of bacteria down the microscope
b) there are different shapes of bacteria down the microscope
c) there are different gram-stained bacteria down the microscope
d) colonies have different sizes on the agar
e) any different colony types are on the agar |
e) any different colony types are on the agar |
|
What genus ofpathogenic bacteria often appear as gram-positive cocci in clusters? a) Staphylococcus b) Streptococcus c) Bacillus d) Escherichia e) Noneof the above |
a) Staphylococcus |
|
What is the most common error that occurs when selecting a colony for subculture?
a) failure to use aseptic technique
b) failure to flame loop
c) failure to cool loop
d) touching more than one colony
e) selecting wrong agar for subculture |
d) touching more than one colony |
|
How can you tell gram-positive from gram-negative organisms?
a) gram-positiveare purple while gram-negative are pink
b) gram-positiveare in clusters while gram-negative are in chains
c) gram-positive are pink while gram-negative are yellow
d) gram-positive are motile while gram-negative are not
e) gram-positive have spores while gram-negative have not |
a) gram-positive are purple while gram-negative are pink |
|
How can spores be distinguished from vegetative forms of bacteria? a) spores are always gram-positive b) spores are always gram-negative c) spores are non-motile while vegetative bacteria are always motile d) spores do not stain with Gram stain while vegetative bacteria do e) spores are always larger than bacterial cells |
d) spores do not stain with Gram stain while vegetative bacteria do |
|
An organism has acapsule so that it can a) makespores b) bemotile c) growon agar plates d) remaindormant in the environment e) resistthe human immune system |
e) resist the human immune system |
|
The word'counter-stain' means in reference to the Gram stain a) Theiodine that is added to help bind the crystal violet b) Thered stain used to show bacteria that have lost the crystal violet stain c) Theacetone that is used to take away the crystal violet d) Thecrystal violet used to make the cells gram-positive e) Noneof the above |
b) The red stain used to show bacteria that have lost the crystal violetstain |
|
An organism has a capsule so that it can
a) make spores
b) be motile
c) grow on agar plates
d) remain dormant in the environment
e) resist the human immune system |
e) resist the human immune system |
|
What genus of pathogenic bacteria often appear as gram-positive cocci in clusters?
a) Staphylococcus
b) Streptococcus
c) Bacillus
d) Escherichia
e) None of the above |
a) Staphylococcus |
|
Which is the correct order of stains used in the Gram stain? a) crystal violet, iodine, acetone, counterstain b) iodine, crystal violet, acetone, counterstain c) crystal violet, counterstain, acetone, iodine d) acetone, crystal violet, iodine, counterstain e) counterstain, crystal violet, acetone, iodine |
a) crystal violet, iodine, acetone, counterstain |
|
Why do we need to wait until the gram-stained smear is completely dry? a) so that the crystal violet has set into the cells b) so that the iodine has had time to kill the bacteria c) so that the counterstain has time to develop d) so that the oil can be added for viewing under the microscope e) so that the bacteria don t float away |
d) so that the oil can be added for viewing under the microscope |
|
Which of thefollowing is an example of poor aseptic technique? (a) incubatingcultures with the Petri lid dish uppermost (b) failingto obtain single colonies on streak dilution (c) failingto set the microscope up to maximise resolution (d) notwashing hands before leaving the laboratory (e) holdinga broth tube vertically while inoculating |
(e) holding a broth tube vertically while |
|
Which of the following additives do not need tobe sterilised before adding to agar? (a) blood (b) peptone (c) agar (d) carbohydrate (e) yeast extract |
(a) blood |
|
The best description of an aminoacid is that it is a: (a) peptide (b) protein (c) monomer (d) monosaccharide (e) complex medium |
(c) monomer |
|
A suitable carbon source forculturing microbes is: (a) carbon monoxide (b) carbon dioxide (c) methane (CH4) (d) peptone (e) an amino acid |
(d) peptone |
|
Asuitable nitrogen source for a microbe is: (a) peptone (b) glucose (c) alcohol (d) acetone (e) maltose |
(a) peptone |
|
Peptonesare: (a) derived from a defined mixture ofmonomers (b) either animal or vegetable in origin (c) can only be animal in origin (d) a synthetic defined media (e) a complex defined media |
(b) either animal or vegetable in origin |
|
Minimal media would most likely to consist of: (a) agar and water only (b) agar, water and salts only (c) agar, water, salts and a defined carbohydrate/nitrogen source (d) agar, water and peptone only (e) agar, water and yeast extract only |
(c) agar, water, salts and a defined carbohydrate/nitrogen source |
|
Pinpoint growth of bacteria growing on a solid surface could be called: (a) a coccus (b) cocci (c) tissue (d) a collection (e) colonies |
(e) colonies |
|
One of the first solid media for growing bacteriawas: (a) potato slices (b) seaweed (c) jelly (d) butter (e) glass |
(a) potato slices |
|
The source of agar is: (a) potato (b) yeast (c) peptone (d) seaweed (e) blood |
(d) seaweed |
|
A suitable carbon source for culturing microbes is:
(a) carbon monoxide
(b) carbon dioxide
(c) methane (CH4)
(d) peptone
(e) an amino acid |
(d) peptone |
|
To prepareblood agar you must: (a) mix blood and agar then filter sterilise (b) add agar after sterilising the blood (c) add blood at room temperature to agar at45C (d) addblood warmed to 45C to agar at 45C (e) heat blood until it goes a chocolatecolour |
(d) addblood warmed to 45C to agar at 45C |
|
Peptones are:
(a) derived from a defined mixture of monomers
(b) either animal or vegetable in origin (c) can only be animal in origin
(d) a synthetic defined media
(e) a complex defined media |
(b) either animal or vegetable in origin |
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A student finds that the agar culture has heavy growth of bacteria but no individual streak lines. This may have resulted from: (a) too many bacteria in the original sample (b) not flaming the loop between streaking (c) the plate being incubated upside down and condensation making colonies run (d) an impure culture (e) not cooling the loop before streaking |
(c) the plate being incubated upside down and condensation making colonies run |
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Streak dilution should result in:
(a) less colonies of bacteria on the agarplate
(b) more colonies of bacteria on the agarplate
(c) single colonies on part of the agar plate (d) heavy growth of bacteria on the agarplate
(e) even growth of bacteria spread all overthe agar plate |
(c) single colonies on part of the agar plate |
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An agar plate labelled CHA wouldbe useful to grow: (a) bacteria contaminating carbohydrates suchas chocolate (b) bacteria contaminating dairy products such as cheese (c) bacteriarequiring nutrients found inside red blood cells (d) bacteriathat require a defined medium (e) bacteriathat require extra carbohydrates |
(c) bacteria requiring nutrients found inside red blood cells |
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Enrichment broth may be used to isolate Salmonella. This is because Salmonella: (a) require a complex medium (b) require a defined medium (c) may be difficult to isolate when E. coli is present (d) require blood for growth (e) grow in broth rather than solid medium |
(c) may be difficult to isolate when E. coli is present |
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MacConkey agar acts as differential medium because (a) bacteria will appear as fermentors or non-fermentors (b) it will change the appearance of bacteria if motile (c) not all colonies are haemolytic (d) some bacteria will produce pigment on this agar (e) only some bacteria will grow on it |
(a) bacteria will appear as fermentors or non-fermentors |
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HBA is best described as (a) a differential medium when growinghaemolytic and non-haemolytic bacteria (b) an enrichment medium because more bacteria will grow on it (c) an enriched medium because it will grow all bacteria (d) a complex medium because it is notpossible to sterilise blood (e) a defined medium because blood is thedefined ingredient |
(a) a differential medium when growing haemolytic and non-haemolytic bacteria |
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MCA can also be used as a selective medium because it contains (a) blood that will grow select organisms (b) bile salts that favours the growth of some gram-negative bacteria (c) carbohydrates that will be selective for fermentors or non-fermentors (d) pH indicator that will distinguish fermentors from non-fermentors (e) amino acids that favour the growth of gram-positive organisms |
(b) bile salts that favours the growth of some gram-negative bacteria |
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List some heat sensitive culture media additives |
blood vitamins antibiotics |
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Name some suitable carbon and nitrogen sources for complex media |
Carbon often supplied in culture media using glucose, or using more complex mixtures e.g. peptone, yeast extract Nitrogen often supplied in culture media using amino acids, or more complex mixtures such as peptone |
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List some typical ingredients for a defined growth medium such as minimal media |
glucose as carbon source, ammonium phosphate asnitrogen source, trace elements |
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Define the term ‘colony’ of bacteria |
as cells divide on solid media they pile up inone area, forming a colony |
|
Define the term ‘colony’ of bacteria |
as cells divide on solid media they pile up in one area, forming a colony |
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Limitations of potato slices as solid media |
only some bacteria would grow on potato, frequent fungal contamination |
|
Limitations of gelatin as solid media |
wouldn’t remain solid at 37°C – the optimal growthtemp. for most human pathogens |
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Name the source of agar |
red algae |
|
list the properties of agar |
polysaccharide -it remains solid at 37°C -after boiling it remains liquid untilcooled to about 45°C |
|
State the best temperature to warm blood and agar before mixing |
addblood warmed to 45oC to agar at 45oC |
|
State the best temperature to warm blood and agar before mixing |
add blood warmed to 45oC to agar at 45oC |
|
Nutrient Agar |
NA – Solid media - same recipe as nutrient broth + agar |
|
Horse Blood Agar |
HBA– Solid media - nutrient agar with bloodadded, some organisms require nutrients found in blood |
|
Chocolate Agar |
CHA – Solid media - nutrient agar with heatedblood added |
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Distinguish the characteristics of growth media termed enriched, enrichment and differential |
Enriched media – basal media with extra nutrients added, e.g. horse blood agar - Enrichment media – used to assist the growth of target organism in a mixed culture -contains additives which inhibit the growth of non-target organisms and improve the growth of target organisms -Differential/indicator media – contains substances which produce visible difference between organisms with different metabolisms -Used to visually identify target organisms growing in a mixed culture on solid media |
|
Enriched media |
basal media with extra nutrients added, e.g.horse blood agar |
|
Enrichment media |
used to assist the growth of target organism in a mixed culture -contains additives which inhibit the growth of non-target organisms and improve the growth of target |
|
Differential/ indicator media |
contains substances which produce visible difference between organisms with different metabolisms - Used to visually identify target organisms growing in a mixed culture on solid media |
|
Selective media |
1. Selective media will restrict the growth of non-target organisms, may improve the growth of target orgs |
|
MacConkey agar (MCA) |
MacConkey agar (MCA) is a selective media as well as a differential media -Contains bile salts, which inhibit the growth of many microorganisms -The neutral red indicator in MCA differentiates between lactose fermenters/nonfermenters – red when acidic, yellow when basic |
|
Name some basal ingredients of media that are monomers |
-amino acids in the case of proteins, -sugars inthe case of polysaccharides, -nucleotides in the case of DNA and RNA |
|
Describe what is meant by ‘peptone’ |
A mixture of peptides. Meat or milk boiled, its longproteins are broken down into peptides. |
|
What is an organic compound |
complexmolecules that are required by organisms to convert to energy |
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What is the maximum growth temperature of a organism? a) The temperature at which a organism grows the best b) The temperature at which cell division occurs most rapidly c) That temperature at which cell division slows down d) A temperature that if exceeded will inhibit growth e) A temperature greater than which, growth will cease |
e) A temperature greater than which, growth will cease |
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Why do some cells stop growing when the temperature is too cold? a) The cell membrane loses its fluidity b)Proteins become denatured c) Cells become dehydrated d) Enzymes become more active e) The cell membrane becomes overly fluid |
a) The cell membrane loses its fluidity |
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Microorganisms that cause disease in humans can be classed as: a) Psychrophiles b) Psychrotrophs c) Mesophiles d) Thermophiles e) Hyperthermophiles |
c) Mesophiles |
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Bacteria that cause spoilage of refrigerated foods are called: a) Psychrotrophs b) Mesophiles c) Thermophiles d) Hyperthermophiles e) Xerophiles |
a) Psychrotrophs |
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Where are you most likely to find a thermophile? a) In the soil b) In animal intestines c) In cooked food d) A swimming pool e) In a bath tub |
a) In the soil |
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Which of the following growth temperature range might be that of a mesophile? a) 0 C – 4 C b) 0 C – 20 C c) 20 C – 45 C d) 45 C – 65 C e) 65 C – 110 C |
c) 20 C – 45 C |
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The stomach is not a favourable environment for bacterial colonization due to: a. High acidity b. High pH c. Lack of receptors on the mucosa for bacteria to attach d. Lack of moisture e. The shape of the stomach |
a. High acidity |
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Bacillus cereus is often the cause of food poisoning associated with rice because: a) Bacillus cereus grows best at cold refrigeration temperatures b) Bacillus cereus grows best at high cooking temperatures c) Bacillus cereus contains endotoxin in its cell wall that is resistant to heat d) When rice is cooled slowly after cooking Bacillus cereus grows rapidly in the rice e)Vegetative cells are extremely resistant to heat |
d) When rice is cooled slowly after cooking Bacillus cereus grows rapidly in the rice |
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What temperature should hot foods be kept at to prevent food borne disease? a) 4°C – 20°C b) 20°C – 30°C c) 30°C – 40°C d) 40°C – 50°C e) Greater than 60°C |
e) Greater than 60°C |
|
Microorganisms that require oxygen to grow are called: a) Obligate aerobes b) Obligate anaerobes c) Facultative anaerobes d) Aerotolerant anaerobes d) Microaerophiles |
a) Obligate aerobes |
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Which of the following is an example of a strict aerobe? a) E. coli b) Pseudomonas aeruginosa c) Serratia marcescens d) Staphylococcus aureus e) Clostridium perfringens |
b) Pseudomonas aeruginosa |
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What is a facultative anaerobe? a) A microbe that needs oxygen to grow b) A microbe that only grows in the absence of oxygen c) A microbe that grows optimally in oxygen but can grow in its absence d) A microbe that can survive in oxygen but grows anaerobically e) A microbe that grows only in a small amount of oxygen |
c) A microbe that grows optimally in oxygen but can grow in its absence |
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Which of the following bacteria can grow anaerobically: a) E. coli b) Clostridium perfringens c) Staphylococcus aureus d) Streptococcus pyogenes e) All of the above |
e) All of the above |
|
In prac you inoculate a tube of Brewers Thioglycollate medium with Bacteroides fragilis. Following incubation what should you see? a) Growth only at the top of the tube b) Growth only at the bottom of the tube c) Even growth throughout the tube d) Growth throughout the tube that is heavier towards the top e) No growth anywhere in the tube |
b) Growth only at the bottom of the tube |
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Which of the following is an example of a microaerophilic microorganism? a) Bacteroides fragilis b) Clostridium perfringens c) Pseudomonas aeruginosa d) E. coli e) Campylobacter jejuni |
e) Campylobacter jejuni |
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A microorganism that requires sodium chloride to grow is called a: a) Neutrophiles b) Alkalophiles c)Acidophiles d) Osmophiles e) Halophiles |
e) Halophiles |
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A jar of jam is most likely to be spoiled by mould because: a) Jam has a low water activity b) Jam has a high water activity c) Jam has a high pH d) Jam has a low pH e) Moulds grow more rapidly than bacteria |
a) Jam has a low water activity |
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When growing bacteria release acids into culture media the pH is stabilised by: a) Reducing agents b) Growth factors c) Antibiotics d) Buffers e) Differential dyes |
d) Buffers |
|
What is meant by bacterial generation time? a) The time it takes for DNA to replicate b) The time taken for bacteria to start growing on an agar plate c) The time it takes for a microbe to reach its optimal growth rate d) The time taken for bacteria to use all the nutrients in a medium e) The doubling time for a group of cells |
e) The doubling time for a group of cells |
|
Where would you find psychrophiles |
Growmostly in the ocean depths or in certain polar regions, |
|
Where would you would find psychrotrophs |
foodsimproperly stored as they are more common in the environment |
|
Where would you find mesophiles |
moderatetemperature, neither too hot nor too cold, typically between 20 and 45 °C |
|
Where would you would find psychrotrophs |
foods improperly stored as they are more common in the environment |
|
List the reasons that temperature affects growth of bacteria |
At low temperatures -the cell membrane loses fluidity - enzymes stop working - transport in/out goes very slowly -Growth cannot occur At temperatures above the optimum - proteins denature - ribosomal RNA denatures - cell membrane becomes too fluid -Cells cannot continue to grow |
|
State the pH growth range for most microbes |
Most bacteria grow best in a narrow pH between6.5 and 7.5 |
|
Where would you find psychrophiles |
Growmostly in the ocean depths or in certain polar regions, |
|
Where would you find psychrophiles |
Grow mostly in the ocean depths or in certain polar regions, |
|
Where would you find mesophiles |
moderatetemperature, neither too hot nor too cold, typically between 20 and 45 °C |
|
Where would you find thermophilic |
-hot water, -sun lit soils and thermal springs. -Also important in compost heaps were temps can get to 50 – 60. -Endospores of thermophilic bacteria may survive canning processes. |
|
Where would you find Hyperthermophiles |
Hotundersea volcanic vents |
|
Explain and state the temperature chosen to keep foods warm |
Above 65 C. Very few disease causing bacteria can grow above 65 C |
|
Describe why rice salad has frequently been responsible for food poisoning |
Whenrice is cooled slowly after cooking Bacilluscereus grows rapidly in the rice |
|
List the reasons that temperature affects growth of bacteria |
At low temperatures -the cell membrane loses fluidity - enzymes stop working - transport in/out goes very slowly -Growth cannot occur At temperatures above the optimum - proteins denature - ribosomal RNA denatures - cell membrane becomes too fluid -Cells cannot continue to grow |
|
Give an example of an acidophil and why it is used in foods |
Lactobacillus. In yoghurt. Ferments milk sugars and produces an acid product. Acid from fermentation prevents harmful bacteria growing. |
|
State the pH growth range for most microbes |
Mostbacteria grow best in a narrow pH between 6.5 and 7.5 |
|
The study of whichgenetic disease led Garrod to propose that there is a special relationshipbetween genes and enzymes? a) Tay-Sachsdisease b) sicklecell disease c) phenylketonuria d) alkaptonuria |
d) alkaptonuria |
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The one gene-oneenzyme hypothesis was proposed by ___ in 1942. a) Beadleand Tatum b) Meselsonand Stahl c) Garrod d) Morgan |
a) Beadle and Tatum |
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The study of which genetic disease led Garrod to propose that there is a special relationship between genes and enzymes?
a) Tay-Sachs disease
b) sicklecell disease
c) phenylketonuria
d) alkaptonuria |
d) alkaptonuria |
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Mutant strains of abacterium that are unable to grow on a minimal medium are ____________________. a) prototrophic. b) autotrophic. c) auxotrophic. d) phototrophic. |
c) auxotrophic. |
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A methionine auxotroph ____________________. a) can not grow on a complete medium. b) can grow on minimal medium supplemented with methionine. c) can not grow in the presence of methionine. d) can grow on minimal medium with no supplements. |
b) can grow on minimal medium supplemented with methionine. |
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Mutant strains of a bacterium that are unable to grow on a minimal medium are ____________________.
a) prototrophic.
b) autotrophic.
c) auxotrophic.
d) phototrophic. |
c) auxotrophic. |
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In PKU, the absence of enzyme activity effects which step in the phenylalanine metabolism pathway? a) conversion of phenylalanine to tyrosine b) conversion of phenylalanine to phenylpyruvic acid c) conversion of tyrosine to melanin d) conversion of phenylpyruvic acid to melanin |
a) conversion of phenylalanine to tyrosine |
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The Guthrie test for PKU requires the use of which microorganism? a) Saccharomyces cerevisiae b) Escherichia coli c) Neurospora crassa d) Bacillus subtilis |
d) Bacillus subtilis |
|
The one gene-one enzyme hypothesis was proposed by ___ in 1942.
a) Beadle and Tatum
b) Meselson and Stahl
c) Garrod
d) Morgan |
a) Beadle and Tatum |
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The normal versionof the mutant gene responsible for albinism in humans encodes an enzyme thatconverts ____________________. a) phenylalanineto DOPA. b) DOPAto melanin. c) phenylalanineto tyrosine. d) tyrosineto DOPA. |
d) tyrosine to DOPA. |
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The mutant gene responsible for PKU is located on ____________________.
a) the X chromosome.
b) chromosome 12.
c) chromosome 1.
d) chromosome 21 |
b) chromosome 12. |
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Which disease is caused by a mutation in a gene located on the X chromosome? a) PKU b) Tay-Sachs disease c) Lesch-Nyhan syndrome d) albinism |
c) Lesch-Nyhan syndrome |
|
The most severeform of Lesch-Nyhan syndrome affects ____________________. a) femalesonly b) moremales than females c) malesonly d) morefemales than males |
b) more males than females |
|
Which of thefollowing is characterized as a lysosomal storage disease? a) sicklecell anemia b) PKU c) cysticfibrosis d) Tay-Sachsdisease |
d) Tay-Sachs disease |
|
The mutant generesponsible for Tay Sachs disease is located on ____________________. a) chromosome3. b) theX chromosome. c) chromosome10. d) chromosome15. |
d) chromosome 15. |
|
The mutant gene responsible for Tay Sachs disease is located on ____________________.
a) chromosome 3.
b) the X chromosome.
c) chromosome 10. d) chromosome 15. |
d) chromosome 15. |
|
The most severe form of Lesch-Nyhan syndrome affects ____________________.
a) females only
b) more males than females
c) males only
d) more females than males |
b) more males than females |
|
Which of the following is characterized as a lysosomal storage disease?
a) sickle cell anemia
b) PKU
c) cystic fibrosis
d) Tay-Sachs disease |
d) Tay-Sachs disease |
|
A child born to a man and a woman who are both carriers of the mutant allele responsible for cystic fibrosis has a ___ chance of having the disease.
a) 0%
b) 25%
c) 50%
d) 100% |
b) 25% |
|
The NobelPrize-winning researchers who are credited with determining that one enzyme isproduced from one gene are a) Watsonand Crick. b) Beadleand Tatum. c) Hersheyand Chase. d) Garrodand Bateson. e) Avery,MacLeod, and McCarty. |
b) Beadle and Tatum. |
|
The following is a representation of a metabolic pathway involving genes X, Y, Z and W for enzymes that convert substances A to B, B to C, C to D and D to the final product A mutation in the "X" gene would result in an accumulation of which gene product? a) C, D, and the product b) B only c) A only d) A, B, and C e) the product only |
c) A only |
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A mutation in thegene for which enzyme is responsible for the metabolic disorderphenylketonuria? a) adenosinedeaminase b) phenylalaninehydroxylase c) acidphosphatase d) glucose-6-phosphatedehydrogenase e) noneof the above |
b) phenylalanine hydroxylase |
|
The Nobel Prize-winning researchers who are credited with determining that one enzyme is produced from one gene are
a) Watson and Crick.
b) Beadle and Tatum.
c) Hershey and Chase.
d) Garrod and Bateson.
e) Avery, MacLeod, and McCarty. |
b) Beadle and Tatum. |
|
Bottles of Diet Coke carry a warning for people with PKU because the sweetener used in this drink contains a) dextroseand fructose. b) phenylalaninehydroxylase. c) tyrosine. d) phenylalanine. e) saccharine. |
d) phenylalanine. |
|
Which of thefollowing human diseases is caused by an autosomal recessive mutation? a) alkaptonuria b) phenylketonuria c) albinism d) cysticfibrosis e) allof the above |
e) all of the above |
|
Lesch-Nyhansyndrome is caused by a mutation in a gene located on which chromosome? a) 1 b) 16 c) 21 d) X e) Y |
d) X |
|
The compulsive self-mutilation behaviors exhibited by Lesch-Nyhan individuals are the result of a mutation in the gene for which enzyme? a) hypoxanthine guanine phosphoribosyltransferase b) hexosaminidase A c) para-hydroxypheynlpyruvate oxidase d) pyruvate kinase e) phenylalanine hydroxylase |
a) hypoxanthine guanine phosphoribosyltransferase |
|
Tay-Sachs disease is most prevalent in which population? a) Pennsylvania Amish b) Ashkenazi Jews of central European descent c) African and African-American blacks d) Caucasians of northern European descent e) Caucasians of Sicilian descent. |
b) Ashkenazi Jews of central European descent |
|
In people who do not have Tay-Sachs disease, the hexA gene encodes an enzyme that a) converts purines to uric acid in the kidneys. b) removes a sugar group from phenylalanine. c) converts tyrosine into melanin in skin. d) cleaves acetylgalactosamine from gangliosides. e) synthesizes glycogen from glucose monomers. |
d) cleaves acetylgalactosamine from gangliosides. |
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Which of the following is characterized as a liposomal storage disease? a) Lesch-Nyhan syndrome b) Tay-Sachs disease c) sickle-cell disease d) xeroderma pigmentosum e) all of the above |
b) Tay-Sachs disease |
|
In people who do not have Tay-Sachs disease, the hexA gene encodes an enzyme that
a) converts purines to uric acid in the kidneys. b) removes a sugar group from phenylalanine. c) converts tyrosine into melanin in skin.
d) cleaves acetylgalactosamine from gangliosides.
e) synthesizes glycogen from glucose monomers. |
d) cleaves acetylgalactosamine from gangliosides. |
|
A person withsickle-cell trait has ________ at the beta-globin gene locus. a) twowild-type alleles b) twomutant alleles c) onewild-type and one mutant allele d) onewild-type and one deleted allele e) onemutant and one deleted allele |
c) one wild-type and one mutant allele |
|
It is possible to distinguish between normal hemoglobin and hemoglobin S using electrophoresis because these two forms of hemoglobin have different a) molecular weights. b) electrical charges. c) densities. d) masses. e) all of the above |
a) molecular weights. |
|
The mutationresponsible for sickle-cell disease is a(n) a) inversioninvolving separate regions of the beta-globin gene. b) pointmutation in the beta-globin gene. c) areciprocal translocation involving the alpha- and beta-globin genes. d) adeletion of part of the beta-globin gene. e) allof the above |
b) point mutation in the beta-globin gene. |
|
The mutation that changes normal hemoglobin to hemoglobin S changes a codon for glutamic acid to one for a) alanine. b) valine. c) glycine. d) tyrosine. e) aspartic acid. |
b) valine. |
|
Among Caucasians, the most common lethal autosomal recessive disease is a) sickle-cell disease. b) hemophilia. c) muscular dystrophy. d) cystic fibrosis. e) phenylketonuria. |
d) cystic fibrosis. |
|
The genes for hemoglobin S and hemoglobin A are a) recessive. b) codominant. c) completely dominant. d) heterozygous. e)heterogenous. |
b) codominant. |
|
Cystic fibrosis is caused by a mutation in the gene that encodes which enzyme? a) pyruvate kinase b) hexosaminidase A c) CFTR protein d) hemoglobin e) tyrosine kinase |
c) CFTR protein |
|
A person with sickle-cell trait has ________ at the beta-globin gene locus.
a) two wild-type alleles
b) two mutant alleles
c) one wild type and one mutant allele
d) one wild-type and one deleted allele
e) one mutant and one deleted allele |
c) one wild-type and one mutant allele |
|
Amniocentesis isbest performed a) beforethe end of the first trimester. b) onthe tenth day after conception. c) afterthe twelfth week of pregnancy. d) atthe end of the second trimester. e) twoweeks before delivery. |
c) after the twelfth week of pregnancy. |
|
A heterozygote witha mutant allele for phenylalanine hydroxylase would have which phenotype? a) severemental retardation b) veryfair skin and blue eyes c) selfdestructive behavior d) allof the above e) noneof the above |
e) noneof the above |
|
Which metabolite isrequired for normal production of the skin pigment melanin? a) phenylalanine b) ceramide c) tyrosine d) bothA and C e) allof the above |
d) both A and C |
|
The mutationresponsible for cystic fibrosis occurs in a gene that is located on whichchromosome? a) 1 b) 7 c) 17 d) X e) Y |
b) 7 |
|
Amniocentesis is best performed
a) before the end of the first trimester.
b) on the tenth day after conception.
c) after the twelfth week of pregnancy.
d) at the end of the second trimester.
e) two weeks before delivery. |
c) after the twelfth week of pregnancy. |
|
What lens do you use to see the bacteria in a hanging drop test? |
the 40X lens. |
|
What do you focus on first in a hanging drop test? |
The edge of the culture drop. |
|
Where would you find Hyperthermophiles |
Hotundersea volcanic vents |
|
Explain and state the temperature chosen to keep foods warm |
Above 65 C. Very few disease causing bacteria can grow above 65 C |
|
Describe why rice salad has frequently been responsible for food poisoning |
Whenrice is cooled slowly after cooking Bacilluscereus grows rapidly in the rice |
|
Give an example of an acidophil and why it is used in foods |
Lactobacillus. In yoghurt. Ferments milk sugarsand produces an acid product. Acid from fermentation prevents harmful bacteriagrowing |
|
how can pH be used in food preservation |
Acidfrom fermentation prevents harmful bacteria from growing. |
|
Explain what can be done to help limit the growth retardation of acid by-products in culture media |
Buffers counter pH variation. Phosphate salts buffer in the pH growth range of most bacteria, they are non toxic and they provide phosphorus and essential nutrient |
|
Name two microbes that grow at lower pH range |
Moulds yeasts grow over a larger pH range than bacteria, an optimum in lower(pH 5 – 6) |
|
Osmosis |
thenet movement of water across a semipermeable membrane from an area of lowersolute concentration to an area of higher solute concentration. to equalizethe solute concentrations on the two sides |
|
Osmotic pressure |
The osmotic pressure of a solution isthe pressure difference needed tostop the flow of solvent across a semipermeable membrane |
|
Define a halophile |
Anorganism that needs salt to grow |
|
What is required for the isolation of Halophiles in growth media |
The addition of salt to the growth medium |
|
Explain aW |
Wateractivity. The amount of water free to act |
|
examples of food spoilage due to low aW requiring organisms |
Mould grown on jam after water condensation |
|
Identify the classification of bacteria based on atmospheric growth requirements |
Aerobes- Some microbes require oxygen for energy extraction from organic chemicals Anaerobes – Somemicrobes can extract energy from organic chemicals only in the absence ofoxygen – Facultativeanaerobes - Some microbes can extract energy from organic chemicals with andwithout oxygen Aerotolerantanaerobes – grow equally well no matter the oxygen levels Microaerophilic – requiring less oxygen thanin the atmosphere but requiring some. Can not grow in air |
|
Aerobe |
Somemicrobes require oxygen for energy extraction from organic chemicals |
|
Identify the classification of bacteria based on atmospheric growth requirements |
Aerobes- Some microbes require oxygen for energy extraction from organic chemicals
Anaerobes – Some microbes can extract energy from organic chemicals only in the absence ofoxygen –
Facultative anaerobes - Some microbes can extract energy from organic chemicals with andwithout oxygen
Aerotolerant anaerobes – grow equally well no matter the oxygen levels
Microaerophilic – requiring less oxygen than in the atmosphere but requiring some. Can not grow in air |
|
Facultative anaerobe |
Some microbes can extract energy from organicchemicals with and without oxygen |
|
Aerotolerant anaerobe |
growequally well no matter the oxygen levels |
|
Explain aW |
Water activity.
The amount of water free to act |
|
give an example of one genus of bacteria of facultative anaerobe |
Escherichiacoli |
|
give an example of one genus of bacteria of aerobe |
Pseudomonasspp. |
|
give an example of one genus of bacteria of anaerobe |
Clostridiumspp. Bacteroides spp. |
|
give an example of one genus of bacteria of Aerotolerant Anarobes |
Lactobacillusspp. |
|
give an example of one genus of bacteria of microaerophilic |
Campylobacterspp. |
|
Identify the generation time of a bacteria |
Time required for a generation (doubling time) varies due to: species variation nutritional factors |
|
Growth phases of prokaryotes |
Exponential growth phase: Cell numbers double at a constant rate: Stationary phase: If nutrients are limited, cells cannot continue exponential growth indefinitely, also a buildup of waste products will inhibit growth - cells growing = cells dying, no increase or decrease in total cell number Death phase: No cell growth, cells die and may lyse, due to lack of nutrients/toxic waste products |
|
Exponential growth phase (prokaryotes) |
1. Cell numbers double at a constantrate: e.g. one E.coli cell after 20 minutes = 2 cells, after 1 hour = 8cells, after 2 hours = 64 cells, after 6 hours = 262,144 cells, after 10 hours= 51,073,741,824 cells |
|
Stationary phase (prokaryotes) |
If nutrients are limited, cells cannot continue exponential growth indefinitely, also a buildup of waste products will inhibit growth - cells growing = cells dying, no increase or decrease in total cell number |
|
give an example of one genus of bacteria of Aerotolerant Anarobes |
Lactobacillus spp. |
|
Which one of thefollowing patterns of growth matches an organism below. Grows Chocolate agarbut not Nutrient agar or Horse blood agar. a) E.coli b) Neisseriagonorrhoeae c) Streptococcuspyogenes d) Bacillussubtilis e) Staphylococcusepidermidis |
b) Neisseria gonorrhoeae |
|
Which of the following bacteria most likely fits the following description: Large, flat, irregular spreading lactose-fermenting on MacConkey agar a) Neisseria gonorrhoeae b) Streptococcus pyogenes c) Staphylococcus aureus d) Neisseria meningitidis e) E. coli |
e) E. coli |
|
Which one of thefollowing agars would be the best to grow streptococci? a) Nutrientagar b) MacConkeyagar c) HorseBlood agar d) Chocolateagar e) noneof the above |
c) Horse Blood agar |
|
E. coli cells appearmicroscopically after being Gram stained as a) gram-positivecocci in chains b) gram-positivecocci in clusters c) gram-positiverods d) gram-negativerods e) gram-negativecocci |
d) gram-negative rods |
|
Which of the following best describes a colony of bacteria? a) 1 mm wide, green with yellow edges and green centre b) 2 mm wide, dome shaped, opaque c) 3 mm wide, furry and smelly d) 4 mm wide, large and flat e) 5 mm wide, spreading and flat |
b) 2 mm wide, dome shaped, opaque |
|
Which one of thefollowing agars would be the minimum required to grow staphylococci? a) Nutrientagar b) MacConkeyagar c) HorseBlood agar d) Chocolateagar e) noneof the above |
a) Nutrient agar |
|
Some bacteria canmove across an agar surface creating a film of growth. This is called a) motility b) swarming c) clouding d) swimming e) sliding |
b) swarming |
|
Which agar would bemost useful when examining a mixture of gram-negative bacteria? a) Nutrientagar b) MacConkeyagar c) HorseBlood agar d) Chocolateagar e) noneof the above |
b) MacConkey agar |
|
Which one of the following agars would be the minimum required to grow staphylococci?
a) Nutrient agar
b) MacConkey agar
c) Horse Blood agar
d) Chocolate agar
e) none of the above |
a) Nutrient agar |
|
E. coli cells appear microscopically after being Gram stained as
a) gram-positive cocci in chains
b) grams positive cocci in clusters
c) gram-positive rods
d) gram-negative rods
e) gram-negative cocci |
d) gram-negative rods |
|
Lactosefermentation can be seen as a) Pinkcolonies on MacConkey agar b) Colourlesscolonies on MacConkey agar c) Haemolyticcolonies on Horse blood agar d) Bubblesin the agar medium e) Swarmingon Horse blood agar |
a) Pink colonies on MacConkey agar |
|
Horse blood agar (HBA) grows a greater variety of organisms than Nutrient agar a) False, nutrient agar has extra ingredients, but HBA only grows blood-borne bacteria b) False, nutrient agar is multi-purpose, but HBA has only few uses c) False, nutrient agar grows soil and animal bacteria, but HBA only grows animal bacteria d) True, HBA grows every bacteria that has been discovered e) True, some bacteria are unable to grow unless blood is used to enrich the agar |
e) True, some bacteria are unable to grow unless blood is used to enrich the agar |
|
Which of thefollowing ingredients gives MacConkey agar differential properties a) peptone b) bilesalts c) sodiumchloride d) lactose e) agar |
d) lactose |
|
Which of thefollowing is enriched and differential? a) Nutrientagar b) MacConkeyagar c) HorseBlood agar d) Chocolateagar e) noneof the above |
c) Horse Blood agar |
|
Streptococci arebest described microscopically as a) gram-negativerods b) gram-positiverods c) gram-negativecocci d) gram-positivecocci in clusters e) gram-positivecocci in chains |
e) gram-positive cocci in chains |
|
In order to find Bacillus anthracis in a soil sample, it would be usefulto
a) usea differential agar such as MacConkey agar
b) grow soil in broth before subculturing to agar
c) use an enriched agar such as Chocolate agar d) investigate colonies that have a typical morphology expected for the organism
e) look for swarming colonies on HBA |
d) investigate colonies that have a typical morphology expected for the organism |
|
Chocolate agarcontains additional carbohydrate compared to Horse blood agar a) True,it is a sweeter form of agar that increases the growth rate of bacteria b) True,the extra carbohydrate makes the agar darker than HBA c) True,there are three different sugars present instead of the single sugar in HBA d) False,chocolate agar is a vegetarian version of a blood product e) False,chocolate agar is a cooked version of HBA |
e) False, chocolate agar is a cooked version of HBA |
|
Which of the following best describes how HBA can be both enriched and differential as agar a) E. coli will be larger and more grey in colour than a Staphylococcus colony b) Streptococcus pyogenes will be haemolytic, but Neisseria meningitidis is not c) Some bacillus colonies will have a ground glass surface, while others will be smooth d) Klebsiella colonies will be large and dome shaped while E. coli will be large and flat e) Staphylococcus epidermidis colonies may be whiter than Staphylococcus aureus |
b) Streptococcus pyogenes will be haemolytic, but Neisseria meningitidis is not |
|
Chocolate agar contains additional carbohydrate compared to Horse blood agar
a) True, it is a sweeter form of agar that increases the growth rate of bacteria
b) True, the extra carbohydrate makes the agar darker than HBA
c) True, there are three different sugars present instead of the single sugar in HBA
d) False, chocolate agar is a vegetarian version of a blood product
e) False, chocolate agar is a cooked version of HBA |
e) False, chocolate agar is a cooked version of HBA |
|
Which of thefollowing ingredients gives MacConkey agar selective properties a) peptone b) bilesalts c) lactose d) NeutralRed e) agar |
b) bile salts |
|
The definition of symbiosis is: a) the process in which one cell divides to form two b) a process in which two cells can transfer DNA via a pilus c) a cellular process in which amino acids are converted to proteins d) a relationship between two organisms e) a process in which a spore is converted to a vegetative cell |
d) a relationship between two organisms |
|
Bacteria that benefit from living in the body without causing any harm are called: a) Commensals b) Mesophiles c) Pathogens d) Organotrophs e) Extremophiles |
a) Commensals |
|
Where in the human body would you find the largest amount of microbes? a) Mouth b) Nose c) Small Intestine d) Large Intestine e) Genitourinary tract |
d) Large Intestine |
|
A throat swab is taken from a healthy individual and a mixture of bacteria grows on the plate. This most likely indicates: a) Tonsillitis b) Influenza c) Normal throat flora d) More tests are needed to make a diagnosis e) Broad spectrum antibiotics should be prescribed |
c) Normal throat flora |
|
In prac class a student places their hand on an agar plate. Following incubation the plate is covered in E. coli. This represents: a) Normal skin flora b) A skin infection c) Normal flora of the oral cavity d) Faecal contamination of hands e) Normal nasopharyngeal flora |
d) Faecal contamination of hands |
|
Which of the following is not an example of commensal relationship? a) Staphylococcus epidermidis growing on the skin b) Staphylococcous aureus growing in the nose c) Neisseria gonorrhoeae growing on urethral epithelial cells d) E. coli growing in the large intestine e) Nonpathogenic streptococci growing in the throat |
c) Neisseria gonorrhoeae growing on urethral epithelial cells |
|
Which of the following is true about a mutualistic relationship: a) One organism benefits b) Both organisms benefit c) One organism benefits and the other is harmed d) Neither organism benefits or is harmed e) Both organisms are harmed |
b) Both organisms benefit |
|
Which of the following describes a parasitic relationship? a) One organism benefits whilst the other remains unaffected b) Both organisms benefit c) One organism benefits and the other is harmed d) Neither organism benefits or is harmed e) Both organisms are harmed |
c) One organism benefits and the other is harmed |
|
Rumen Bacteria found in the stomachs of cows are an example of a: a) Commensal relationship b) Mutualistic relationship c) Neutralistic relationship d) Parasitic relationship e) Mixed relationship |
b) Mutualistic relationship |
|
The growth of Giardia in the large intestine is an example of: a) Commensal relationship b) Mutualistic relationship c) Neutralistic relationship d) Parasitic relationship e) Amensalism |
d) Parasitic relationship |
|
Which of the following describes how a disease may be transmitted indirectly through a vector? a) Kissing b) Sharing a drink bottle c) Eating a chicken dish that has not been cooked properly d) Sitting near someone who is coughing and sneezing e) Being bitten by a mosquito |
e) Being bitten by a mosquito |
|
Acquiring a disease as a result of touching a contaminated door handle is an example of: a) Droplet transmission b) Airborne transmission c) Direct contact transmission d) Indirect contact transmission e)Vector borne transmission |
d) Indirect contact transmission |
|
Flies crawling on prepared food is an example of how disease may be spread by: a) Direct contact transmission b) Indirect contact transmission c) Vector borne transmission d) Airborne transmission e) Vertical transmission |
c) Vector borne transmission |
|
Which of the following diseases is mostly transmitted directly from person to person? a) Gonorrhoea b) Salmonella gastroenteritis c) Malaria d) S. aureus food poisoning e) E. coli urinary tract infection |
a) Gonorrhoea |
|
Where in the body are you not likely to find commensals? a) Skin b) In the nose c) In the mouth d) Lungs e) Large Intestine |
d) Lungs |
|
Where in the body would the presence of Staphylococcus indicate disease? a) Skin b) Nose c) Blood stream d) Vagina e) Large Intestine |
c) Blood stream |
|
Bacteria commonly found in the body that cause disease in a person with a weakened immune system are called: a) Phagocytes b) Extremeophiles c) Commensals d) Neutrophils e) Opportunistic pathogens |
e) Opportunistic pathogens |
|
The normal flora of the large intestine is beneficial in: a) Minimising available sites for pathogens colonize b) The secretion of antimicrobial substances c) The production of certain vitamins d) Assisting digestion e) All of the above are true |
e) All of the above are true |
|
Which of the following best describes the term pathogen? a) A common bacterium in the body that doesn’t cause any harm b) A microorganism that infects a host c) A commensal that causes disease in a person following a course of antibiotics d) A commensal that grows in a person when their immune system is compromised e) A microorganism that grows in the host and causes harm |
e) A microorganism that grows in the host and causes harm |
|
What is the benefit of Lactobacillus in the Vagina? a) Increases pH preventing growth of pathogens b) Decreases pH preventing growth of pathogens c) Inhibits the growth of commensals d) Resistant to antibiotics e) None of the above |
b) Decreases pH preventing growth of pathogens |
|
commensalism, |
Symbiotic relationship the host (e.g. human, plant, fungi) receives no benefit or harm, the microbe benefits from the interaction |
|
mutualism, |
Symbioticrelationship both organismsbenefit |
|
neutralism |
Symbioticrelationship neither organism benefitsor is harmed by the interaction |
|
parasitism, |
Symbiotic relationship negative effect on host, positive effect on microbe |
|
amenasalism |
Symbiotic relationship no effect on host, negative effect on microbe |
|
symbiosis |
therelationship between the normal microbiota and the host |
|
example of a commensalist organism |
Staphylococcus epidermidis grows on the surface on skin, feeds on sebum secretions, no negative effect for host |
|
example of a mutualist organism |
rumen of cattle -allow cellulose digestion, -the microbes receive a warm, protected environment and nutrients from food legumes and Rhizobacteria -allow for nitrogen fixation in the root nodules, -the nitrogen is used by the plant, -the bacteria obtains carbohydrates Lichen - made up of a fungus and an alga, -the fungus provides a protective structure -the alga is photosythetic, providing food |
|
example of a parasitic organism |
Pseudomonas aeruginosa – loves moisture, -also attaches well to plastic |
|
Genotype |
genetic constitution of an individual |
|
Phenotype |
1. observable trait or set of traits of an individual Phenotype produced by interaction between genotype and environment |
|
Genetic traits |
1. characteristics of an individual Some traits heritable, others not |
|
Mendel’s studies on garden peas: |
1. Selected model genetic organism (peas) Studied one trait at a time Simple interpretation of results Direct experiments to prove hypothesis |
|
Why were peas a good genetic organism? |
1. easy to grow, short life cycle, produced large number of seeds - each plant has stamens and pistils - normally self fertilise enabled Mendel to have strict control over mating -each seed had an embryo |
|
Seven different characters that Mendel studied |
1. -seed shape smooth/wrinkled-seed coat colour/flower colour grey seedcoat, purple flower/white both -seed colour yellow/green -pod colour yellow/green -pod shape inflated/pinched -stem height tall/short -flower position axial/terminal |
|
discrete’characteristics |
1. Either/or characteristics• - no intermediate phenotype• e.g., smooth or wrinkled seeds |
|
continuous’characteristics |
1. Characteristics that change on a gradient |
|
true-breedingstrain |
1. when the plants are allowed to self-pollinatefor many generations, all the offspring were genetically identical |
|
purebreeding strain’? |
1. when the plants are allowed to self-pollinatefor many generations, all the offspring were genetically identical |
|
bacteria that is often on dry skin, |
1. Staphylococcusepidermidis |
|
bacteria that is often in the nasal cavity, |
Staphylococcus aureus,
Staphylococcus epidermis |
|
bacteria that is often in the mouth, |
Staphylococcus, Streptococcus, Lactobacillus, Neisseria, Candida |
|
bacteria that is often in the large intestine, |
E.coli, Lactobacillus, Bacteroides, Enterococcus |
|
bacteria that is often in the vagina |
Staphylococcus, Streptococcus, Clostridium, Candida, Bacteroides |
|
State some benefits to humans of normal flora in the large intestine |
productionof vitamins B12 and K aid in food digestion |
|
bacteria that is often on dry skin, |
1. Staphylococcus epidermidis |
|
Opportunistic pathogen |
only cause disease in the absence of normalhost resistance
or when an opportunity exists |
|
Infection |
1. wherea microorganism is growing in a host, with or without host damage |
|
disease |
1. damagethat impairs host function |
|
Mendel’s monohybrid cross: |
-used true breeding varieties -breeding for a single characteristic |
|
P generation |
1. Parents: Female and Male |
|
F1 generation |
-the first filial generation -offspring of ‘P’ Generation |
|
pathogen |
The parasite grows as the expense of the host,
causing damage while obtaining nutrients and a favourable environment
The pathogenicity of a parasite is measured by its virulence |
|
Whatwas the ratio of F2 individuals he obtained in monohybrid cross? |
3:1ratio |
|
Dominantcharacter |
1. dominant allele fully expressed in appearance |
|
Law of segregation:. |
Recessive traits, which are masked in the F1from a cross between two true breeding strains, reappear in a specificproportion in the F2 two members of a gene pair (alleles)segregate (separate) from each other during gamete formation in meiosis |
|
letteringconvention used to denote alleles. |
Dominant allele represented by ‘capital’ letterand recessive allele by ‘small’ letter e.g., Smooth seeds (S), Wrinkled seeds(s) (Ss) |
|
Law of segregation: |
Recessive traits not seen in F1 reappear in a specific proportion in the F2
two alleles separate from each other during gamete formation in meiosis |
|
The firstgeneration in a series of monohybrid crosses is referred to as the ___generation. a) F1 b) F2 c) A d) P |
a) F1 |
|
F2 generation |
- the second filial generation
-offspring produced by interbreeding ‘F1 l’individuals |
|
In a monohybrid cross between two true-breeding parents that both exhibit the dominant phenotype, ___ percent of the offspring will exhibit the recessive phenotype. a) 50 b) 0 c) 100 d) 25 |
b) 0 |
|
In a monohybridcross between two true-breeding parents, one showing the dominant phenotype andthe other the recessive phenotype, the phenotypic ratio in the F2 generation isexpected to be ____________________. a) 1:2:1. b) 2:1. c) 3:1. d) 1:1. |
c) 3:1. |
|
In a cross betweentwo homozygous dominant parents, the number of phenotypic classes observed inthe offspring is ____________________. a) 2. b) 1. c) 4. d) 3. |
b) 1. |
|
In a cross betweena homozygous dominant parent and a homozygous recessive parent, the number ofphenotypic classes observed in the offspring is ____________________. a) 4. b) 3. c) 2. d) 1. |
d) 1. |
|
In a cross between 2 heterozygous parents, the expected number of phenotypic classes in the offspring is ____________________.
a) 2.
b) 4.
c) 1.
d) 3. |
a) 2. |
|
In a testcross, anindividual of unknown genotype is crossed with a ___ individual to determinethe unknown genotype. a) hemizygous b) homozygousdominant c) heterozygous d) homozygousrecessive |
d) homozygous recessive |
|
An individual with the dominant phenotype, but an unknown genotype, is testcrossed, and all of the offspring exhibit the dominant phenotype. The genotype of the unknown individual is ____________________. a) homozygous recessive. b) heterozygous dominant. c) homozygous dominant. d) heterozygous recessive. |
c) homozygous dominant. |
|
In a particular type of tomato plant, red fruit color is dominant over yellow. In a cross between a heterozygous plant and a homozygous recessive plant, what percentage of the offspring would have yellow fruit? a) 100 b) 0 c) 50 d) 25 |
c) 50 |
|
In a particulartype of tomato plant, red fruit is dominant over yellow fruit, and dwarf heightis a recessive trait. If two plants that were heterozygous for both traits werecrossed, what proportion of the offspring would show the recessive phenotype? a) 1/8 b) 1/2 c) 1/16 d) 1/4 |
c) 1/16 |
|
In a particulartype of tomato plant, red fruit is dominant over yellow fruit, and dwarf heightis a recessive trait. If two heterozygous plant were crossed, what proportionof the offspring would show the dominant phenotype? a) 9/16 b) 2/3 c) 3/8 d) 1/4 |
a) 9/16 |
|
In a particulartype of melon, orange fruit is dominant over green fruit, and round shape if dominantto oval. If a plant that was heterozygous for both traits was crossed with aplant that was homozygous recessive for both traits, what proportion of theoffspring would be heterozygous? a) 3/4 b) 1/4 c) 1/2 d) 9/16 |
b) 1/4 |
|
An albino womanmarries a phenotypically normal man with no family history of albinism. What percentageof their children are likely to be albino? a) 25 b) 100 c) 50 d) 0 |
d) 0 |
|
What percentage of the children of a woman with achondroplasia will carry the disease causing allele? a) 25 b) 50 c) 0 d) 100 |
b) 50 |
|
Two phenotypicallynormal people have 4 children. 3 are phenotypically normal like their parents,but one is an albino. What are the probable genotypes of the parents? a) Bothparents are homozygous recessive. b) Oneparent is homozygous dominant and one is homozygous recessive. c) Bothparents are heterozygous. d) Bothparents are homozygous dominant. |
c) Both parents are heterozygous. |
|
The statisticaltest used to determine if an observed set of data differs significantly fromthe expected results is the ________ test. a) studentt- b) bestfit c) productrule d) chi-square e) ANOVA |
d) chi-square |
|
The inheritance of traits in humans is best studied by a) performing carefully controlled mating experiments. b) construction and evaluating family pedigrees. c) performing and evaluating chi square tests. d) all of the above e) none of the above |
b) construction and evaluating family pedigrees. |
|
SS |
1. homozygous dominant individual |
|
Ss |
1. heterozygous individuals |
|
ss |
1. homozygous recessive individual |
|
The inheritance of traits in humans is best studied by
a) performing carefully controlled mating experiments.
b) construction and evaluating family pedigrees.
c) performing and evaluating chi square tests. d) all of the above
e) none of the above |
b) construction and evaluating family pedigrees. |
|
1. homozygous dominant individual Notation |
SS |
|
1. heterozygous individuals Notation |
Ss |
|
The statistical test used to determine if an observed set of data differs significantly fromthe expected results is the ________ test.
a) student t-
b) best fit
c) product rule
d) chi-square
e) ANOVA |
d) chi-square |
|
|
Punnett square. |
|
Test Cross |
1. if have an unknown genotype -homozygous or heterozygous? -cross it with a true breeding recessive -can determine the genotype of the individual |
|
Mendel’s dihybrid cross: |
1. Looking at how two allele pairs will be inherited. Smooth Yellow (SSYY) crossed with wrinkled green (ssyy) gave Mendel all Smooth Yellow (SsYy) in F1 generation 9 Smooth Yellow: 3 Smooth green: 3 wrinkled Yellow: 1 wrinkled green in the F2 generation. |
|
SsYy x SsYy genotype combinations |
produces16 individuals 9 different genotype combinations 4 differentphenotypes |
|
Independent Assortment |
1. Mendel examined crosses for parents which differed in 2 characters • - SY, sY, Sy and sy combinations of gametes in alleles • sperm and ovum produce 16 classes of allele combinations • 4 phenotypic classes • 9:3:3:1 ratio |
|
Methods of transmission of disease |
1. Contacttransmission -Direct contacttransmission -Indirect contacttransmission -Droplet transmission Vehicletransmission -water, -food, -airborne Vectors -Arthropods -Mechanical transmission -Biological transmission |
|
‘opportunistic pathogen’ by using the example of Pseudomonas |
1. Tinea can lead to Pseudomonas having a secondary opportunistic infection once the skin has cracked, making it wet and smelly. |
|
Contact transmission |
-Directcontact transmission - Indirect contacttransmission - Droplettransmission |
|
Vehicle transmission |
water, food, airborne |
|
Explain why the asymptomatic stage of infection is important in transmission |
1. Spreadingthe organism before you know you know you are infected |
|
Explain why Koch’s postulates have been refined |
Whenthe causative organism cannot be cultured in the laboratory – e.g. Mycobacteriumleprae, the causative agent of leprosy -When thecausative organism will only grow as a co-culture – e.g. viruses will onlygrow inside a host cell -Whendiseases/effects require more than one organism to be present |
|
SsYy x SsYy genotype combinations |
produces 16 individuals
9 different genotype combinations
4 different phenotypes |
|
If the results of a chi-square test on a particular set of data show a P value greater than 0.05, then the hypothesis a) must be rejected. b) must not be accepted. c) cannot be rejected. d) must not be valid. |
c) cannot be rejected. |
|
In humans, recessive traits are expressed in a) females only. b) every generation. c) a person with one recessive allele. d) a person with two recessive alleles. e) both A and C |
d) a person with two recessive alleles. |
|
The offspring of two phenotyically normal people who are heterozygotes for albinism would be expected to exhibit which phenotypic ratio of normal to affected individuals? a) 3:1 b) 1:1 c) 1:2:1 d) 1:3 e) 4:0 |
a) 3:1 |
|
Contact transmission types |
-Direct contact transmission
- Indirect contact transmission
- Droplet transmission |
|
Which of thefollowing is true concerning the inheritance of a dominant trait? a) Everyaffected person must have one affected parent. b) Thetrait is observed in every generation. c) Anaffected heterozygote will transmit the allele to half of his or her offspring. d) allof the above e) noneof the above |
d) all of the above |
|
For a single trait, the offspring of true-breeding parents may a) resemble only one parent. b) be exactly alike. c) be a blend of both parental phenotypes. d) both A and B e) all of the above |
d) both A and B |
|
The probability that two parents will have 3 girls and 1 boy in their family may be determined using the a) product rule. b) sum rule. c) student t-test. d) chi-square test. e) all of the above |
a) product rule. |
|
The probability that two parents will have 3 girls and 1 boy in their family in that order is a) 1/2. b) 1/4. c) 1/8. d) 1/16. e) 1/32. |
d) 1/16. |
|
What is theprobability that the first child of two parents is a girl? a) 1/4 b) 1/2 c) 1/8 d) 1/16 e) 1/256 |
b) 1/2 |
|
For any given gene,the principle of segregation predicts that gametes produced as a result ofmeiosis will contain ____________________. a) halfof both alleles of the gene pair. b) halfof one allele of a gene pair. c ) a single allele of a gene pair. d) bothalleles of a gene pair. |
c) a single allele of a gene pair. |
|
Individuals that are heterozygous for a particular trait have a) two different alleles of the gene. b) multiple copies of the gene. c) two identical copies of the gene. d) two different genes responsible for the trait. e) two identical alleles of the gene. |
a) two different alleles of the gene. |
|
product rule |
The probability of two mutually exclusive eventsoccurring together is the multiplication of the individual probabilities -Multiplying the frequency of alleles to findproportion of progeny phenotypes |
|
allele |
1. Same gene with a slightly different sequence |
|
A chemical used in food preservation |
1. Sodium nitrite |
|
potential problem of sodium nitrate use |
-acarcinogen precursor -Lengthy and costly testing programs required to ensure food safety |
|
Define sterilisation |
killing/removal/inactivation of all viable organisms -including endospores |
|
List some parameters used to control growth of microbes |
- temperature, - pH, - water levels (aw), - oxygen levels |
|
Illustrate the problem of microbes growth in the cold using the Listeria example |
Listeria can cause death in utero meningitis in theimmunocompromised. grows at 4 C. |
|
some methods of control of microbes using heat |
-Pasteurisation -Tyndallisation -Boiling -Hot air oven -Incineration -Autoclaving |
|
Tyndallisation |
1. 80°Con 3 successive days |
|
Boiling |
1. 100°C |
|
Hot air oven |
1. 160-180°C |
|
Autoclaving |
1. steamat >100°C |
|
pasteurisation |
-routinely used for juice and milk -retards growth of spoilage organisms, -increases shelf life -Foods can be boiled at 100°C -doesn’t kill endospores -may change taste and physical properties of heat-sensitive foods -Not a process of sterilisation, -reduces microbial numbers -kills pathogenic bacteria including Listeria and Campylobacter |
|
disinfection |
1. Killing/removal of all vegetative forms, notincluding endospores |
|
ways in which endospores are more resistant to killing |
- Resistant to heat , can withstand temperaturesof 150°C - resistant to UV radiation - resistant to chemical disinfectants |
|
autoclaves |
-Generally heat till 1210C and -then hold for 15 minutes -Flash sterilisers (tend to be smaller bench-style) -1340C for 3 minutes -Important to allow flush out of air - air trapped in load poor transfer of heat -Condensation on items allows transfer of heat rather than conduction -Drying cycle important as bugs can pass through wet packs |
|
Estimate the time needed to have 99.9% kill from a supplied graph |
9 minutes -log 10 equals 1 -number of organisms reduced by a power of 10 each minute. - At 3 minutes, 10 organisms were left -If we were 90% sure then there is a 10% chance an organism is still alive (1/10) -If we were 99% sure then there is a 1% chance an organism is still alive (1/100) -So a 99.9% kill requires 3 log reductions, -or 3 lots of the time it takes for a 10 fold reduction below the time it takes to reach 100 organisms |
|
Describe factors that may influence the ability to sterilize in an autoclave |
-starting number of organisms, -pre-cleaning important -Size/volume of item -Dry items take longer to sterilise than moist ones, -high amounts of sugars, proteins or fats in the medium decreases heat penetration -Some items cannot be sterilised by steam, e.g. talc, ointments |
|
ionising radiation |
-High-energy radiation particles which produceelectrons and free radicals from molecules they collide with - These radicals disrupt DNA and proteins inthe cells, leading to death |
|
Describe the different form of filtration |
-Membrane filters -for liquids 0.2 µm (1/20,000th of 1 mm) pore commonly used -HEPA (High efficiency particulate air) filters -to filter air -99.97% efficient -remove particles as small as 0.3 microns |
|
Identify different biological cabinets in the laboratory and their uses |
-UV radiation: -between 220-300 nm wavelength light, -causes modifications and double stranded breaks in cell DNA, leading to death -“Biohazard” cabinets use UV light to sterilise surfaces before/after use |
|
A hospital purchases a new autoclave. They wantto know if they have an outbreak of a bad diarrhoeal bacteria, how long willthey need to autoclave the sheets before sending to the laundry, to be 99.9%sure they have killed the bacteria. |
9 minutes It look 4 minutes to go from 106 to 102 organisms (1000000 to 100) after 2 more minutes there will be 100 which is 1 organism. After 1 more minute there is a 1/10 chance an organism is still alive. After another minute there is a 1/100 chance or 1% chance a bug is still alive, i.e., we can be 99% sure the bugs are dead. In one more minute we can be 99.9% sure. |
|
A HEPA filter can filter particles as small as 0.3 microns. It is likely to be effective in filtering a) Liquids b)Liquids and dust particles c) Dust particles and largemicroorganisms d)Bacteria and viruses e) Bacteria but probably notviruses |
1. (e) Bacteria but probably not viruses |
|
You have some meat that has been in the refrigerator and is starting to smell. You decide that a good way to reduce the microbial contamination would be to freeze it. This works a) By killing bacteria cells b) By killing both bacteria and viruses c) Only onparasitic worms d) By killingbacteria and spores e) By killing allmicroorganisms |
c) Only on parasitic worms |
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You decide that since UV radiation is a sterilising agent, putting bedding and mats out in the sunlight will have a sterilising effect. This statement is a) Correct as UV radiation does sterilise b) Correct as surface sterilisation should be sufficient c) Incorrect as UV radiation is only a surface steriliser d) Partially correct as it will reduce the bacterial loadon the items e) Incorrect as UV radiation does not kill viruses |
d) Partially correct as it will reduce the bacterial load on the items -as a surface steriliser |
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Sterilization is a process a) used to destroy all viable cells and spores b) that destroys viable cells but not endospores c) used to reduce microbial numbers to a safe level d) used to kill bacteria but not viruses e) that is only useful in killing gram negative bacteria |
a) used to destroy all viable cells and spores |
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Endospores are very resistant to: a) Heat b) Disinfectants c) Detergents d) UV radiation e) All of the above |
e) All of the above |
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What is the potential problem of using sodium nitrite as a food preservative? a) It reduces the growth of food spoilage microbes allowing pathogens to grow favourably b)It inhibits the growth of pathogens allowing the rapid growth of spoilage microbes c) It is a carcinogen precursor and large amounts may be toxic to consumers d) It neutralises the pH of food allowing alkalophilic bacteria to grow favourably e) It gives food an displeasing taste |
c) It is a carcinogen precursor and large amounts may be toxic to consumers |
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A fermented food such as pickled cucumbers is very resistant to spoilage by bacteria owing to: a) A low pH a) A high pH b) A low water availability c) A high water availability d) Both (a) and (c) are the most correct |
a) A low pH |
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What makes raw meat highly susceptible to the growth of spoilage bacteria: a) Almost neutral pH b) High water availability c) High availability of oxygen at the meat surface d) Copious nutrients e) All of the above are correct |
e) All of the above are correct |
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How does the addition of sugar or salt to a product assist in controlling microbial growth: a) Decreases pH b) Decreases available water c) Increases redox potential d) Increases water availability e) Increases pH |
b) Decreases available water |
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Fruits are not a favourable growth environment for spoilage bacteria. This is because fruits have: a) A high water activity b) A low water activity c) Have a neutral pH d) Have a alkaline pH e) Have an acidic pH |
e) Have an acidic pH |
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Which of the following is true about the growth of Listeria a) Viable cells are destroyed at 4 C b) Growth is inhibited at 4C c) Growth occurs slowly at 4 C d) Viable cells are very resistant to heat e) (b) and (d) are both true |
c) Growth occurs slowly at 4 C |
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Which of the following processes is used for sterilization: a) Pasteurization b) Boiling c) Autoclaving d) Freezing e) All of the above are true |
c) Autoclaving |
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How does boiling control microbial growth: a) Reduces the number of viable cells to a safe level b) It inactivates viable cells but spores are resistant c) It inactivates spores but viable cells may survive d) It slows microbial growth by causing membranes to lose their fluidity e) It kills viable cells and spores |
b) It inactivates viable cells but spores are resistant |
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Which of the following is not true regarding pasteurisation: a) It increases the shelf life of a product b) It kills pathogens c) It decreases the amount of food spoilage microbes d) It is routinely used on heat sensitive foods such as milk and juice e) It makes a product sterile until it is opened |
e) It makes a product sterile until it is opened |
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What would be the best way to sterilise antibiotics before adding to culture media? a) Pasteurization b) Boiling c) Autoclaving d) Filtration e) Tyndallisation |
d) Filtration |
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Autoclaving achieves sterilization through the use of: a) Pressurised steam b) Dry heat c) Toxic gasses such as ethylene oxide d) Toxic chemicals such as sodium hydroxide e) Ionising radiation |
a) Pressurised steam |
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Which of the following items can be sterilised by autoclaving: a) Antibiotics b) Amino acids c) Volatile solvents such as ethanol d) Fluids
e) Talc |
d) Fluids |
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Which of the following factors might effect how long an item needs to be autoclaved to achieve sterility: a) The initial number of microbes b) The viscosity of a solution c) The size of an item d) The volume of an item e) All of the above are true |
e) All of the above are true |
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In which of the following solutions would you expect heat penetration to be the slowest: a) A jar containing water b) A jar containing saline c) A jar containing 2% oatmeal d) A jar containing 4% oatmeal e) Heat would penetrate all of the above solutions equally |
d) A jar containing 4% oatmeal |
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For which of the following tasks would you use a biological safety cabinet: a) When working with volatile chemicals b) When preparing an E. coli purity plate c) When gram-staining a heat fixed smear d) When working with a hazardous pathogen such as Mycobacterium tuberculosis e) For storing waste |
d) When working with a hazardous pathogen such as Mycobacterium tuberculosis |
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Which of the following is true about the growth of Listeria
a) Viable cells are destroyed at 4 C
b) Growth is inhibited at 4C
c) Growth occurs slowly at 4 C
d) Viable cells are very resistant to heat
e) (b) and (d) are both true |
c) Growth occurs slowly at 4 C |
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A vial containing Bacillus stereothermophilus spores is placed in a standard autoclave run (121 C, 20 minutes). It is then incubated in broth at 55 C overnight. What information will this provide about sterilization effectiveness (pick the best response)? a) Germination of spores indicate the autoclave is working b) Germination of spores indicate the autoclave is not working c) No growth indicates the autoclave is working d) No growth indicates the autoclave is not working e) It will not provided any useful information as spores cannot be grown until germinated |
c) No growth indicates the autoclave is working |
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UV light is effective in the sterilization of: a) The flat surfaces of a biological hazard cabinet b) The surface of an opened nutrient agar plate c) Large amounts of waste d) Test tubes with their lids on e) Both (a) and (b) are true |
e) Both (a) and (b) are true |
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chemical sterilant, |
- Chemical sterilants used in hospitals etcon heat-sensitive equipment, such as thermometers, tubing, will kill endospores - enclosed chambers, - gas added such asformaldehyde/hydrogen peroxide |
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disinfectant |
- may not kill endospores, -used on surfaces Includes: -ethanol, -cationic detergents, -bleach(sodium hypochlorite) |
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antiseptic |
kill/inhibit growth of microorganisms but are non-toxic enough to be used on living tissue |
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sanitiser |
reduce microbial numbers to “safe” levels |
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List factors that adversely affect the function of disinfectants |
-Action of disinfectants affected by material surrounding the microorganisms -Presence of proteins, fats etc in the -surrounding area will protect microorganisms, -many disinfectants are neutralised by organic materials -Some microorganisms form biofilms -Penetration of chemicals reduced -Major problem in hospitals, biofilm formation on catheters etc |
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Give examples of what disinfectants have trouble killing or inactivating |
- spores, -TB bacteria -some viruses |
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hypochlorites |
-Excellentvirucidal - Must be diluted - Corrodes metal -Inactivated by organic matter - Needs to be made up fresh |
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Calculate the dilution required to make 5% hypochlorite 5000 parts per 1,000,000 for 10ml |
1. C1 V1 = C2 V2 5 per 100 x V1 = 5000/1000000 x10 ml Solve for V1 V1 = 5000/1000000 x 10 x 100/5 V1 = 1 ml |
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how alcohol is used as a disinfectant |
- Suitablefor skin - doesn’t kill all viruses - 70% alcohol is better than 100% |
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Name the characteristics of a good hand wash solution |
Goodwetting properties Rinses well Residual activity Chlorhexidine good residual |
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Describe the steps in good hand washing technique |
Wet hands first Add hand-wash solution Rub hands, include wrists finger webbing Scratch palms of hands with each finger to get soap under fingernails Rinse well and dry with paper towel Use paper towel to close taps (if old type) |
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Explain the uses of alcohol hand sanitisers |
Convenient, dries quickly 10 – 15 sec application Less irritating than hand washing No good if hands visibly soiled no goof for proteinaceous material Be careful during diarrhoea outbreaks, glove, wash hands after degloving |
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narrow-spectrum antibiotics |
effective on specific target organisms leave more of the microbial flora intact |
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broad spectrum antibiotics |
effectiveon several groups of microbes disrupt microbial flora of host |
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Identify the bacterial processes to which antibiotic action can affect the growth of bacteria |
-inhibition of cell wall synthesis -inhibition of protein synthesis -inhibition of nucleic acid replication and transcription -inhibition of synthesis of essential metabolites -injury to plasma membrane |
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List ways in which bacteria may become resistant to antibiotics |
- bacteria that produce antibiotics have mechanisms to resist theirown antibiotics - These resistance genes can betransferred to other microbes - Penicillin-resistant bacteria producethe enzyme b-lactamase,cleave the b-lactamring of penicillins - Many microbes become resistant tosulfa drugs by taking up folic acid from the environment instead ofsynthesising it - Some microorganisms have activemechanisms (efflux pumps) for removing antimicrobials |
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Give examples of where the preparation of a disinfectant can be important |
Mustknow the chemical before using it, e.g: safety precautions, optimal strength |
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Distilation formula |
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therapeutic index |
thehigher the TI, the better the drug effectiveness:toxicity |
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Describe how the structure of penicillin was used to make semi-synthetic derivatives |
1. the R group was modified for different results |
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how bacteria exploited the structure of penicillin to become resistant to penicillin |
b-lactam ring is susceptible to the enzyme b-lactamase, they cleave the b-lactam ring of penicillins |
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what is the active part of penicillin |
b-lactam ring beta-lactam ring |
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Following a microbiology practical class the bench is wiped down with sodium hypochlorite. The best description of the result will be to: a) Kill all viable cells and spores b) Kill all viable cells but spores may survive c) Reduce viable microorganisms to a safe level d) Slow the growth of microorganisms e)Destroy most microbes but some pathogens may survive |
b) Kill all viable cells but spores may survive |
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Which is more effective 70% ethanol or 95% ethanol? a) 70% ethanol as it contains water which improves its effectiveness b) They both have the same effectiveness c) 95% ethanol as it is more concentrated d) 70% ethanol as it is more concentrated d) 95% as it is pure alcohol |
a) 70% ethanol as it contains water which improves its effectiveness |
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Chi Square Test: |
used todetermine whether there is a significant association between the two variables. ·Degrees of freedom. · Expected frequencies. · Test statistic. · P-value. |
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Degrees of freedom. Chi squared test |
1. DF = (r - 1) * (c - 1) r is the number of levels for one catagorical variable, c is the number of levels for the other categorical variable. |
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Expected frequencies. Chi squared test |
Er,c = (nr * nc) / n Er,c is the expected frequency count for level r of Variable A and level c of Variable B, nr is the total number of sample observations at level r of Variable A, nc is the total number of sample observations at level c of Variable B, n is the total sample size. |
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Test statistic. Chi squared test |
Χ2 = Σ [ (Or,c - Er,c)2 /Er,c ] Or,c isthe observed frequency count at level r ofVariable A and level c ofVariable B, Er,c is the expected frequency count atlevel r ofVariable A and level c ofVariable B. |
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P-value chi squared test |
probability of observing a sample statistic as extreme as the test statistic. Since the test statistic is a chi-square, use the Chi-Square Distribution Calculator to assess the probability associated with the test statistic. Use the degrees of freedom computed above. |
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1. Chi squared chart |
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formation of peptide bond |
a chemical bond formed betweentwo molecules when the carboxyl group of one molecule reacts with the aminogroup of the other molecule, releasing a molecule of water (H2O). |
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molecular structure of proteins: |
primary structure (polypeptide chain), secondary structure (α-helix), tertiary structure (folding of polypeptide); quaternary structure (binding of different polypeptides) |
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formation of peptide bond |
a chemical bond formed between two molecules
when the carboxyl group of one molecule reacts with the amino group of the other molecule,
releasing a molecule of water (H2O). |
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secondary structure of proteins |
3. α-helix |
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tertiary structure of proteins |
3. folding of polypeptide |
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quaternary structure |
3. (binding ofdifferent polypeptides/proteins |
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Test statistic.
Chi squared test |
Χ2 = Σ [ (Or,c - Er,c)2 /Er,c ]
Or,c is the observed frequency count at level r of Variable A and level c of variable B,
Er,c is the expected frequency count at level r of Variable A and level c of variable B. |
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Properties of Genetic Code |
triplet, continuous, non-overlapping, universal, degenerate redundant |
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The most commontype of mucosal immunoglobulin is: (a) IgG (b) IgM (c) IgD (d) IgA (e) IgE |
(d) IgA |
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The antibody associated with allergy is: (a) IgG (b) IgM (c) IgD (d) IgA (e) IgE |
(e) IgE |
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An epitope: (a) is recognised by the Fab regions of anantibody (b) is formed by light and heavy chain of an antibody (c) is the same for every antibody of a given immunoglobulin class (d) can only bind an antigen when the antibody has been secreted (e) none of the above |
(a) is recognised by the Fab regions of an antibody |
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Which of the following is/aretrue of IgM? (a) It has only two antigen binding sites (b) It is necessary for the effective action of IgG (c) It can exist as a pentamer (d) (a), (b) and (c) (e) none of the above |
(c) It can exist as a pentamer |
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The firstantibody produced in response to an antigenic stimulus is: (a) IgG (b) IgM (c) IgE (d) IgD (e) IgA |
(b) IgM |
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Antibodiesof differing specificity are generated by: (a) rearrangement of gene segments (b) having millions of genes encoding antibody chains (c) somatic mutation of antibody genes (d) (a) and (c) above (e) (b) and (c) above |
(d) (a) and (c) above There are not millions of whole genes rather millions of segments than can be selected and sliced in areas of the genome. |
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Cytotoxic T cells (Tc cells) will recognise viral antigens providing they are: (a) bound by the Class I MHC molecule (b) bound by the Class II MHC molecule (c) independent of any MHC recognition site (d) bound to any MHC molecule (e) not bound to any MHC molecule |
(a) bound by the Class I MHC molecule |
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Which trait(s) are true aboutmacrophages? (a) they serve as antigen presenting cells (b) they are non-specific (c) they serve as antigen-processing cells (d) all of the above (e) none of the above |
(d) all of the above |
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Which statement is true of T lymphocytes? (a) they produce lymphokines (cytokines) (b) they mature in the bone marrow (c) all T- lymphocytes have both the CD4 andCD8 surface protein (d) only cytotoxic T lymphocytes can help B cells to produceantibody (e) all of the above are true |
(a) they produce lymphokines (cytokines) |
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Class II MHC proteins are foundon the surface of: (a) all nucleated cells (b) B lymphocytes only (c) macrophages and dendritic cells (d) B lymphocytes, macrophages and dendritic cells (e) red blood cells |
(d) B lymphocytes, macrophages and dendritic cells B cells also act as antigen presenting cells sohave MHC11 molecules that present antigen |
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Experiment that let to deciphering of Genetic Codes |
Nirenberg & Khorana – 1961 synthesised artificial mRNA -added lysate whichsynthesised protein polyU mRNA translated topoly-phenylalanine ‘UUU’ codes for‘phenylalanine’ |
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3. Nirenberg & Khorana – 1961 |
3. synthesised artificial mRNA-added lysate whichsynthesised proteinpolyU mRNA translated topoly-phenylalanine‘UUU’ codes for‘phenylalanine’ |
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An epitope:
(a) is recognised by the Fab regions of an antibody
(b) is formed by light and heavy chain of an antibody
(c) is the same for every antibody of a given immunoglobulin class
(d) can only bind an antigen when the antibody has been secreted
(e) none of the above |
(a) is recognised by the Fab regions of an antibody |
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Cellular immunity |
- Mediatedby specialised cells -T cells |
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The first antibody produced in response to an antigenic stimulus is:
(a) IgG
(b) IgM
(c) IgE
(d) IgD
(e) IgA |
(b) IgM |
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epitope |
-thepart of an antigen that is recognised -Each antigen cancontain several epitopes: multivalent antigens |
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antigen |
1. substancesthat induce an immune response |
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multivalent antigens |
1. antigenwith multiple epitopes |
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Draw IgG, |
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Draw IgM |
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Draw IgA |
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3. Nirenberg & Khorana – 1961 |
3. synthesised artificial mRNA -added lysate which synthesised protein poly? mRNA translated to poly-phenylalanine‘ UUU’ codes for ‘phenylalanine’ |
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1. Pedigree Analysis, |
familytree across generations |
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1. Are humans a model genetic organism |
no |
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1. why pedigreeanalysis is often difficult to construct |
-records are incomplete -cannot get reliable information about the deceased -reluctance to discuss personal information -abortions, artificial inseminations, illegitimate births are hard to account for -variable phenotypic expression (variable expressivity) affects information collected |
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epitope |
-the part of an antigen that is recognised
-Each antigen can contain several epitopes: multivalent antigens |
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1. Family pedigree |
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multivalent antigens |
1. antigen with multiple epitopes |
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1. How individualsare identified in family pedigrees |
- Arabic numerals - individualswithin a generation numbered in birth order |
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1. Males – family pedigree symbols |
- squares |
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- Males - family pedigree symbols |
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Females - familypedigree symbols |
circles |
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- Female - family pedigree symbols |
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- Sex unknown or unspecified - familypedigree symbols |
–diamond |
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Sex unknown or unspecified - familypedigree symbols |
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- Sex unknown or unspecified
- family pedigree symbols |
–diamond |
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- Stillbirths,miscarriages, abortions - family pedigree symbols |
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- Deceased - family pedigree symbols |
line through |
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Deceased - family pedigree symbols |
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- Proband - familypedigree symbols |
-the individual through whom the pedigree was discovered – denoted by arrow |
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- Proband
- the individual through whom the pedigree was discovered
- family pedigree symbols |
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Females
- family pedigree symbols |
circles
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- unaffectedindividuals - family pedigree symbols |
opensymbols |
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characteristics of acquired immunity |
Specificimmunity that develops after exposure to an antigen, or after transferof antibodies or cells from an immune donor |
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Cellular immunity |
Mediatedby specialised cells -T cells |
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humoral immunity |
Antibody mediated -B cells |
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epitope |
-thepart of an antigen that is recognised -Each antigen cancontain several epitopes: -multivalent antigens |
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antigen |
1. substancesthat induce an immune response |
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multivalent antigens |
1. antigenwith multiple epitopes |
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Draw IgG, |
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Draw IgM |
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Draw IgA |
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1. Where is a genelocated on a chromosome? |
1. at a particular locus |
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1. Where arealternate forms of the gene (allele) |
1. at the same locus on the homologous chromosome. |
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1. How many allelesfor a gene can exist |
1. Multiple |
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1. Allelic forms ofa gene result from? |
1. mutation in that gene. |
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1. Name for thenormal form of gene |
wild type |
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1. Is the wild typeof an allele dominant or recessive |
1. dominant |
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1. Is the mutatedform of an allele dominant or recessive |
1. Recessive |
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1. how to calculatenumber of homozygotes, heterozygotes and genotypes that are possible from agiven number of alleles (n) |
Alleles = n genotypes = n(n+1/2) homozygotes = n heterozygotes= n(n-1)/2 |
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1. How to calculatenumber of genotypes from number of alleles (n) |
1. n(n+1)/2 |
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1. How to calculatenumber of homozygotes from number of alleles (n) |
n |
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1. How to calculatenumber of hetrozygotes from number of alleles (n) |
1. N(n-1)/2 |
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In gremlins, coatcolour is determined by a gene with multiple alleles. The three allelesinvolved are: B (brown colour); b (white colour); and ba (brown andwhite stripes). For this locus, B is dominant to both b and ba , and ba is dominantto b. In a cross between a B/ba male gremlin and a B/b femalegremlin, what percentage of the offspring will have brown and white stripes? a) 0 b) 25 c) 50 d) 100 |
b) 25 |
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For any gene withmultiple alleles, a diploid organism may have a maximum of ________ alleles forthat locus. a) 1 b) 2 c) 6 d) 10 e) 100 |
b) 2 |
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Which of thefollowing traits is determined by a gene with multiple alleles? a) ABOblood groups in humans b) eyecolour in Drosophila c) HLAtypes in humans d) allof the above e) noneof the above |
d) all of the above |
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A person with typeA blood could have which genotype? a) IA/IA b) IA/i c) i/i d) bothA and B e) allof the above |
d) both A and B |
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For traits thatshow incomplete dominance, the phenotype of a heterozygote is a) thesame as the homozygous dominant phenotype. b) thesame as the homozygous recessive phenotype. c) intermediatebetween the homozygous dominant and homozygous recessive phenotypes. d) completelydifferent from either the homozygous dominant or recessive phenotype. |
c) intermediate between the homozygous dominant and homozygous recessive phenotypes. |
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Flower colour insnapdragons is a trait showing incomplete dominance. Therefore, the flowers ofa snapdragon plant that is the offspring of a cross between a plant with red flowersand one with white flowers would be a) red. b) white. c) pink. d) somered and some white. e) redwith white spots. |
c) pink. |
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In a certain typeof plant, the gene for flower colour has two alleles, blue and yellow.Heterozygous plants produce green flowers. This is an example of a) incompletedominance. b) codominance. c) completedominance. d) partialdominance. e) epistasis. |
a) incomplete dominance. |
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New phenotypes thatchange the expected phenotypic ratios for a trait can result when a) differentgenes interact. b) oneallele is dominant to another. c) agene has more than two alleles. d) bothA and C e) allof the above |
d) both A and C |
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The expressivity ofa gene depends on the organism's a) genotype. b) gender. c) age. d) environment. e) allof the above |
e) all of the above |
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A(n) ________ genemasks the expression of a different, nonallelic gene. a) incompletelydominant b) epistatic c) recessive d) codominant e) hemizygous |
b) epistatic |
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A mutation in anessential gene a) willmodify a phenotype. b) isgenerally lethal to the organism. c) suppressesthe activity of other genes. d) hasno apparent effect on the organism. |
b) is generally lethal to the organism. |
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A(n) ________allele causes the death of the individual that carries it. a) recessive b) epistatic c) penetrant d) lethal e) codominant |
d) lethal |
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A person who isknown to have a particular genotype does not show the phenotype specified bythe gene. This is an example of a) incompletedominance. b) epistasis. c) incompletepenetrance. d) phenotypeswitching. e) sexreversal. |
c) incomplete penetrance. |
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Members of a familyhave a condition in which the second toe is longer than the big toe. The traitis found in every generation, but it doesn't always appear in family memberswith the associated genotype. In some people, the second toe is longer on bothfeet; in others only one foot has the affected toe. This gene is a) dominant. b) incompletelypenetrant. c) variablyexpressed. d) allof the above e) noneof the above |
d) all of the above |
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Some fruit fliesthat are homozygous for the recessive eyeless gene have no eyes, while othershave eyes that are smaller than normal. Still others have completely normaleyes. This indicates that the eyeless gene is a) epistatic. b) completelypenetrant. c) codominant. d) incompletelydominant. e) variablyexpressed. |
e) variably expressed. |
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Autosomal traits thatappear in both genders but differ between males and females either in frequencyof occurrence or in phenotype are a) sexlinked. b) sexinfluenced. c) sexdependent. d) sexinhibited. e) sexlimited. |
c) sex limited. |
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In a biochemicalpathway, the product of gene A converts a colourless substance into a yellowsubstance, which in turn is converted by the product of gene B into a greenpigment. Although the organism is normally green, a mutation inactivates gene Band the yellow substance accumulates. Gene A and gene B are a) codominant. b) phenocopies. c) epistatic. d) holandric. e) lethal. |
c) epistatic. |
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Autosomal traitsthat appear only in one gender are a) sexlinked. b) sexinfluenced. c) sexlimited. d) sexinhibited. |
c) sex limited. |
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The degree to whichsymptoms occur in people with the genetic disorder phenylketonuria dependsmostly on the affected person's a) age. b) diet. c) gender. d) allof the above. e) noneof the above |
b) diet. |
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A person with typeB blood could receive a transfusion of blood from someone with blood type a) B b) AB c) O d) bothA and C e) allof the above |
d) both A and C |
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In a biochemicalpathway, the product of gene A converts a colourless substance into a yellowsubstance, which in turn is converted by the product of gene B into a greenpigment. Although the organism is normally green, a mutation inactivates gene Band the yellow substance accumulates. Gene A and gene B are a) codominant. b) phenocopies. c) epistatic. d) holandric. e) lethal. |
c) epistatic. |
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A man with bloodtype A and a woman with blood type B could never produce a child with bloodtype a) A b) B c) AB d) O e) noneof the above |
e) none of the above |
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A person who washomozygous for the recessive mutant allele h, and was IAi at the ABO locus,would have which blood type? a) A b) B c) AB d) O |
d) O |
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Which gene isresponsible for the expression of blood group antigens on the surface of redblood cells? a) B b) A c) H d) I |
c) H |
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The probabilitythat two parents will have 3 girls and 1 boy in their family is? a) 1/4 b) 1/2 c) 1/8 d) 1/16 |
d) 1/16 |
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What is theprobability that the first child of two parents is a girl? a) 1/2 b) 1/4 c) 1/8 d) 1/16 |
a) 1/2 |
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A person with typeO blood carries antibodies for ________ in his (her) blood a) A b) B c) bothA and B d) O |
c) both A and B |
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The genotype for aperson with type O blood is ________ a) IA/IB b) IA/i c) IB/i d) i/i |
d) i/i |
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The serum of aperson with type A blood will contain antibodies against which antigen? a) Aonly b) Bonly c) bothA and B d) O |
b) B only |
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The serum of aperson with type A blood will contain antibodies against which antigen? a) Aonly b) Bonly c) bothA and B d) O |
b) B only |
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Epistasis |
-One gene (pair of allele) masks expression of another gene (pair of allele) -Epistasis may be caused because of presence of dominant allele or both recessive alleles of one gene -Epistasis can also occur in both directions between two pairs of alleles of two genes |
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1. Are Mendelianratios changed due to epistasis? |
Yes. Varies for where the epistasis occurs/behaves |
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1. what happens whenrecessive ‘b’ (b/b) is epistatic to ‘A’ or ‘a’? |
1. 3 ‘A/- b/b’ and 1 ‘a/a b/b’ produce the same phenotype F2 ratio is modified to 9:3:4. |
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1. what happens whendominant ‘A’ (A/-) is epistatic to ‘B’ or ‘b’? |
9 ‘A/- B/-’ and 3 ‘A/- b/b’ produce the same phenotype. F2 ratio is modified to 12:3:1. |
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1. Duplicategenes: |
two genes produce identical phenotype meaning, gene/genotype at one locus produces same phenotype as gene/genotype at other locus |
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1. what happens when recessive ‘a’ (a/a) is epistatic to ‘B’ or ‘b’ and recessive ‘b’ (b/b) is epistatic to ‘A’ or ‘a’? Our A/- and B/- produce same phenotype |
1. ‘A/- b/b’, ‘a/a B/-’, ‘a/a b/b’ will all have same phenotype F2 phenotypic ratio is modified to 9:7 |
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what happens when dominant ‘A’ (A/-) is epistatic to ‘B’ or ‘b’ and dominant ‘B’ (B/-) is epistatic to ‘A’ or ‘a’? 1. |
9 ‘A/- B/-’, 3 ‘A/- b/b’, 3 ‘a/a B/-’ produce the same phenotype. F2 ratio is modified to 15:1.
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1ml to um |
1000um |
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1000 um to ml |
1 ml |
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100 um to ml |
0.1 ml |
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10 um to ml |
0.01 ml |
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1 um to ml |
0.001 ml |
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1 liter in ml |
1000 ml |
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times 10 Scientific notation |
x10 |
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times 100 Scientific notation |
x102 |
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times 1000 Scientific notation |
x103 |
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IgG, |
Immunoglobulin, Monomer, enhances phagocytosis, neutralizes toxins and viruses, protects foetus and newborn |
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IgM |
Immunoglobulin, Pentamer, Especially effective against microorganisms and agglutinating antigens, first antibodies produced in response to initial infection |
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IgA |
Immunoglobulin, dimer (with secretory component), localised protection on mucosal surfaces |
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B cells |
Antibodiesare produced by B cells Beforeactivation, the immunoglobulin is a B cell receptorB cells originateand mature in the bone marrow (and the foetal liver) |
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Explain how antibodies are formed |
1. Antibodiesare produced by B cells |
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Describe how it is possible to form antibody for every possible antigen that could exist |
Rearrangementof gene segments Somaticmutations Generation ofdifferent codons during gene splicing |
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T cells |
Tcells have a specific, but highly diverse receptor; T cells mature in the thymus haveantigen-specific T-cell receptors (TCRs) on their surface; Do not recognisenative antigen, but recognise antigen “presented” by another cell (antigenpresenting cell, APC) |
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Explain how antibody production requires the assistance of helper T cells |
Inorder for a B cell to be fully activated, it must interact with a certain classof T cells Another class of Tcells is required for the elimination of infected cells |
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A toxin is mixed with an antibody. You would expect the toxin to be: (a) neutralized (b) agglutinated (c) opsonized (d) precipitated (e) haemagglutinated |
(a) neutralized |
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In the complement fixation test you would expect bacteria to be: (a) neutralized (b) agglutinated (c) opsonized (d) precipitated (e) haemagglutinated
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(c) opsonized |
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In a test involving agar immunodiffusion you would expect to see antigen: (a) neutralized (b) agglutinated (c) opsonized (d) precipitated (e) haemagglutinated |
(d) precipitated |
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In blood typing you would expect red blood cells to be: (a) neutralized (b) agglutinated (c) opsonized (d) precipitated (e) haemagglutinated |
(b) agglutinated |
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Influenza virus is mixed with erythrocytes causing them to be: (a) neutralized (b) agglutinated (c) opsonized (d) precipitated (e) haemagglutinated |
(e) haemagglutinated |
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A monoclonal antibody could be used as: (a) passive protection against infection (b) active protection against infection (c) treatment for cancer (d) all of the above (e) (a) and (c) above |
(e) (a) and (c) above |
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In the first step of a directELISA test for antigen: (a) a glass slide is stained with a fluorescentantibody (b) a latex antibody solution is added to seeif agglutination takes place (c) wells of a microtiter tray are coatedwith antibody (d) cells bearing antigen are counted in afluorescent sorter (e) proteins are separated by size using electrophoresis |
(c) wells of a microtiter tray are coated with antibody |
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Fluorescent antibodies may be useful to: (a) microscopically visualise a difficult to culture organism (b) label helper T cells and enable them to be counted (c) identify the cause of an infection microscopically (d) all of the above (e) none of the above |
(d) all of the above |
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A good screening test: (a) must not have any false positives (b) should have high sensitivity but may have lower specificity (c) should have high specificity but may have lower sensitivity (d) should always be confirmed with a second test (e) will rapidly confirm positive results |
(b) should have high sensitivity but may have lower specificity |
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Western blots are used to: (a) confirm HIV screening tests (b) measure immunofluorescence (c) count CD4 cells (d) show whether agglutination as occurred (e) rapidly screen patients |
(a) confirm HIV screening tests |
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serology |
the observation of antibody-antigen reactions invitro |
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neutralisation |
-Antibodies attach to the outside of antigens -Blocks adhesion of bacteria and viruses to mucosa -blocks attachment of toxin |
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agglutination |
-Thisoccurs when the crosslinked particles precipitate. •Antibodies binding to particles can cause them to clumpIn vivo, -these are quickly cleared by immune cells • Visibleto the naked eyeveryuseful for diagnosis •Principle behind blood-typing |
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precipitation, |
Antibodies bind to antigen and link them together, -forming a precipitate |
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opsonisation |
apathogen is marked for ingestion and eliminated by a phagocyte. - Afteropsonin binds to the membrane, phagocytes are attracted to the pathogen |
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opsonin |
anymolecule that enhances phagocytosis by marking an antigen for immune destruction |
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haemagglutination |
the clumping together of red blood cells. Viruses such as influenza have surface proteins that act as haemagglutins |
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Haemagglutination inhibition |
- Antiviral antibodies attach to viruses -viruses are thus neutralizes and hemagglutination is inhibited |
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monoclonal antibodies |
- the antibody derived from a single B-cell clone (single cell lineage) • After infection with a pathogen, a polyclonal serum is generated • Defined specificity • Single class (Usually IgG) • Highly reproducible • Can get several MAs to the same antigen • Immortal! |
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Polyclonal antibodies |
antibodies that are secreted by different B cell lineages within the body -(whereas monoclonal antibodies come from a single cell lineage). -After a monyclonal antibody has an infection with a pathogen, a polyclonal serum is generated |
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1. Penetrance |
thepercentage of individuals with a genotype who exhibit the phenotype associatedwith the genotype |
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Expressivity |
1. degree to which a penetrant gene isphenotypically expressed in an individual |
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1. Is expressivityfor an individual or a population |
1. individual |
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1. Is penetrance foran individual or a population |
1. population |
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1. What are thefactors that result in different Penetrance of genotypes |
Environmental factors : Age of Onset: Sex: Chemicals: Temperature: |
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1. What are thefactors that result in different Expressivity of genotypes? |
Environmental factors : Age of Onset: Sex: Chemicals: Temperature: |
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How would you determine the number of genes involved in a set of mutation with same phenotype |
1. If mutation in different genes: they can complement each other If mutation is same gene: no complementation!
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1. Complementationtest (cis-trans test). |
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how eukaryotic chromosomes segregate (separate) during gamete formation |
- through meiosis. – random assortment of chromosomes |
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crossing-over in meiosis |
1. chromosomes switch chunks of DNA |
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Different sex determination systems: |
XX-XY’, - mammals ‘XX-XO’ – many insects ‘ZZ-ZW’ – birds and some fish haplo-diploid – plants |
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environmentalsex determination |
- sequential hermaphroditism -, sex is determined fully or in part by environmental factors. - each individual animal can be both male and female, although not at the same time. – temperature and proximity to other individuals influence this |
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XX-XY |
- operates in mammals, drosophila Male (XY) Female (XX) |
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XX-XO |
- Protenor system – many insects - female has two copies of sex chromosome male has only one sex chromosome Female - XX Male - XO |
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ZZ-ZW’ |
operates in birds and some fish males– ZZ females– ZW |
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haplo-diploid systems |
- sex determination by one gene (two alleles) in plants -chomosomes that carry the sex determining region pair along entire length -typically one sex is heterozygous and the other is homozygous |
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ELISA |
Enzyme-Linked Immunosorbent Assay • Very sensitive detection technique • Relies on enzymes attached to antibodies • Two types: – Direct – Indirect |
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Sandwich ELISA process |
(1) Plate is coated with a capture antibody; (2) sample is added, and any antigen present binds to capture antibody; (3) detecting antibody is added, and binds to antigen; (4) enzyme-linked secondary antibody is added, and binds to detecting antibody; (5) substrate is added, and is converted by enzyme to detectable form |
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screening test |
A good screening test should have high sensitivity (not miss any positives) A trade off is specificity |
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confirmatory test |
7. Specific test for target antigens |
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Explain what happens in a ‘Western Blot’ |
1) Electrophoresis is used to separateproteins in the serum which move based on charge and size. 2) The bands ofprotein are transferred to a nitrocellulose filter by blotting. 3) The filteris washed with the patients serum followed by anti-human antibodies tagged withan enzyme, making the antibodies visible. 4. The test is read. Taggedantibodies stick to the filter and can be seen. |
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Explain how T helper cells might be counted |
T-helper cells have protein receptor CD4 Make antibodies to CD4 and tag with a charge or fluorescence Mix with patient’s blood and pass through cell-counting machine Count the signals to give cell count |
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Describe how fluorescent antibodies might be used |
Fluorescent microscopes can be used toimage antibody interactions when antibodies are tagged with fluorescent dyes Cells canbe separated using flow cytometry |