Mech Vent Ch1-5 Misc

Front 1

Calculate the amount of pressure needed to attain a tidal volume of 0.5L (500ml) for a patient with a normal respiratory system compliance of 0.1 L/cm H2O. (pg 6)

Back 1

Remember that C= change in Vol/change in press. You can manipulate the formula to read: change in press=change in vol/compliance.
pressure=.5/0.1
pressure=5 cmH20
A Palv change of 5 cmH2O would be required to achieve a 0.5 L tidal vol. in a person with normal compliance (Cl)

Front 2

The normal compliance in spontaneously breathing patients is 0.05-0.17L/cmH2O or ___. (pg 6)

Back 2

50-170mL/cmH2O

Front 3

The compliance in intubated patients is: Males 40-50 mL/cmH2O (up to 100mL/cmH2O) & females___. (pg 6)

Back 3

35-45 mL/cmH2O (up to 100mL/cmH2O)

Front 4

Raw=(_____)/flow (pg 7)

Back 4

PIP-P plat

Front 5

Raw can also be =___.

Back 5

P ta (pressure trans airway)/flow

Front 6

Time constants represent both passive filling and ___. (pg 9)

Back 6

passive emptying

Front 7

Abbrev. for Compliance (pg 3)

Back 7

C

Front 8

Abbrev. for Resistance (pg 3)

Back 8

R

Front 9

Abbrev. for Airway Resistance (pg 3)

Back 9

Raw

Front 10

Abbrev. for Pressure at the mouth (pg3)

Back 10

P m

Front 11

Abbrev. for Airway Pressure (usually upper) (pg 3)

Back 11

P aw

Front 12

Abbrev. for Pressure at the airway opening (mouth or mask pressure) (pg3)

Back 12

P awo

Front 13

Abbrev. for Alveolar pressure (pg3)

Back 13

P alv or P a

Front 14

Abbrev. for Intraplural pressure (pg3)

Back 14

Ppl

Front 15

Abbrev. for static compliance (pg3)

Back 15

C st

Front 16

Abbrev. for Dynamic compliance (pg3)

Back 16

C dyn

Front 17

Formula for Transairway press: (pg3)

Back 17

Pta=Paw-Palv

Front 18

Formula for Transthoracic press: (pg3)

Back 18

Pw or Ptt=Palv-Pbs

Front 19

Formula for Transpulmonary press: (pg 3)

Back 19

Ptp or Pl=Palv-Ppl

Front 20

Formula for Transrespiratory press: (pg3)

Back 20

Ptr=Pawo-Pbs

Front 21

Accessory muscles of insp are:___. (pg3)

Back 21

STPS (steps) sterno, trapezius, pecs & scalene

Front 22

Accessory muscles of expiration are :__. (pg3)

Back 22

rectus, trans. abdom, ext. ob., int. ob., serratus & latissimus dorsi

Front 23

1 mmHg also equals...(pg4)

Back 23

1.36cmH2O

Front 24

1kPa also equals...(pg4)

Back 24

7.5mmHg

Front 25

1 torr also equals...(pg4)

Back 25

1mmHg

Front 26

1atm also equals...(pg4)

Back 26

760mmHg & 1034cmH2O

Front 27

The equation for calculating static compliance... (pg 7)

Back 27

Cs=(exhaled tidal vol)/(P plat -EEP)

also written as Cs=Vt/(Pplat-EEP)

Front 28

The normal resistance values for UNINTUBATED pt is....(pg8)

Back 28

0.6-2.4cmH2O/(L/sec) @ .5L/sec flow

Front 29

The normal resistance vlaues of the INTUBATED pt is...(pg8)

Back 29

approx. 6cm H20/(L/s) or higher (airway resisitance INCREASES as ET tube size DECREASES)

Front 30

Formula for claculating time constant....(pg9)

Back 30

Time constant=C (as the lung fills)*R(as the lung emptys)

Front 31

An intubated, 36 y/o female diagnosed with Pneumonia is being vented @ a vol of 0.5L (500 ml). The PIP is 24cmH2O & Pplat is 19cmH2O. The baseline pressure is 0. The insp. gas flow is constant @ 60L/min (1L/s). What are the static compliance & airway resistance? Are these normal values?

Back 31

C=.5/19=0.263 L/cmH2O
Raw is estimated @5cmH2O
The pt's compliance is low(maybe a stiff lung condition) & Raw is low for an artificial airway