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19 Cards in this Set
- Front
- Back
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-Which type of codec has the lowest bandwidth requirement?
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G.723
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-G.711 uses what coding scheme?
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PCM
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-G.726 uses what coding scheme?
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ADPCM
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-G.728 uses what coding scheme?
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LDCELP
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-G.729 uses what coding scheme?
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CS-ACELP
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-G.723 uses what coding scheme?
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MPMLQ
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-What is the disadvantage of encapsulating more samples per PDU?
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The delay becomes more variable
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-What would be the size of voice samples from Cisco voice equipment if a G.728 codec were used?
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20 ms
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-What is the overhead for Frame Relay?
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6 Bytes
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-How many bytes in the Ethernet II overhead are used for CRC?
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4 bytes
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-What is the overhead associated with IPSec?
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50 to 57 bytes
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-What is the overhead associated with MPLS?
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4 bytes
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-Which two examples of protocol-specific encapsulation
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X.25 over TCP/IP
Ipv6 over Ipv4 |
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-Which two examples of experimental encapsulation?
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L2F
L2TP |
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-Which 3 factors must be considered when calculating the total bandwidth of a VoIP call?
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Codec Size
Network-Link Overhead Sample Size |
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-Using a G.729 codec and Frame Relay without CRTP, what is the total bandwidth required for a 40-byte voice sample size?
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17200 bps
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-What is the function of comfort noise generation?
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Provides white noise to make the call sound connected
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-What is the formula used to calculate the total bandwidth?
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Total Bandwidth = ([Layer_2_Overhead + IP_UDP_RTP Overhead + Sample_Size] / Sample_Size) * Codec_Speed
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-Using a G.729 codec and Frame Relay without CRTP, what is the total bandwidth required for a 40-byte voice sample?
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17200 bps
Remember... Total Bandwidth = ([Layer_2_Overhead + IP_UDP_RTP Overhead + Sample_Size] / Sample_Size) * Codec_Speed |
