Chemistry Chapter 3 Quiz Lecture

Front 1

Which of the following terms defines the amount of mass in a unit volume?


a. density

b. specific mass

c. specific gravity

d. specific volume

e. none of the above

Back 1

a. density

The formula is M=D times V
Example
M=6
D=2
V=3
6=3x2
Similar to a % formula as well.
Part = whole times %

Front 2

Which of the following terms defines the amount of heat energy required to raise one gram of any substance one degree on the Celsius scale?


a. calorie

b. heat

c. specific heat

d. joule

e. none of the above

Back 2

c. specific heat

Don't confuse this with Joules.

Front 3

Which of the following is a unit factor corresponding to the unit equation:
1 mile = 1.61 kilometers?


a. 1 mi/1 km

b. 1 mi/1.61 km

c. 1.61 mi/1.61 km

d. 1 km/1.61 mi

e. 1 km/1 mi

Back 3

b. 1 mi/1.61 km

Front 4

If a silver chain has a mass of 25.0 g, what is the mass in pounds?


a. 0.0551 lb

b. 0.0264 lb

c. 18.1 lb

d. 37.8 lb

e. 11,400 lb

Back 4

a. 0.0551 lb

1 lb = 454 grams

25g times 1 lb / 454 g

Front 5

If 500.0 mL of liquid mercury weighs 6.53 kg, what is the mass in pounds?


a. 1.44 lb

b. 2.96 lb

c. 7.19 lb

d. 14.4 lb

e. 2960 lb

Back 5

d. 14.4 lb

500ml is just extra info.
6.53/1 times 1000g/1kg times
1lbs./454g = 14.38 lbs.=14.4lbs.

Front 6

If a rectangular stainless steel block measures 5.05 cm by 1.50 cm by 1.25 cm, what is the volume of the stainless steel solid?


a. 0.106 cm3

b. 2.69 cm3

c. 4.21 cm3

d. 6.06 cm3

e. 9.47 cm3

Back 6

e. 9.47 cm3

Mulitply all three to get cm3 or ml or cc

Front 7

A piece of tin foil has a volume of 0.645 mm3. If the piece measures 10.0 mm by 12.5 mm, what is the thickness of the foil?


a. 0.000 516 mm

b. 0.005 16 mm

c. 0.0516 mm

d. 80.6 mm

e. 194 mm

Back 7

b. 0.005 16 mm

.654/10 times 12.5
.654/125 = close to .00516 mm

Front 8

If an automobile engine has a displacement of 155 in.3, what is the volume in cubic centimeters?


a. 9.45 cm3

b. 61.0 cm3

c. 394 cm3

d. 1000 cm3

e. 2540 cm3

Back 8

e. 2540 cm3

155 in.3rd times (
1in./2.54cm)3rd =

Front 9

A 109.35 g sample of brass is added to a 100-mL graduated cylinder with 55.5 mL of water. If the resulting water level is 68.0 mL, what is the volume of the brass?


a. 12.5 mL

b. 32.0 mL

c. 44.5 mL

d. 87.5 mL

e. 123.5 mL

Back 9

a. 12.5 mL

a. 12.5 mL

V=68-55.5= 12.5ml
furthermore
D=M/V
109.35g/12.5ml = 8.75g/ml

Front 10

A rectangular block of aluminum has a mass of 39.589 g and measures 5.10 cm by 2.50 cm by 1.15 cm. Find the density of the aluminum block.


a. 0.370 g/cm3

b. 2.70 g/cm3

c. 3.11 g/cm3

d. 14.7 g/cm3

e. 22.3 g/cm3

Back 10

b. 2.70 g/cm3

5.10 x 2.50 x 1.15 = volume
D=M/V
39.589g/14.66cm3rd

Front 11

Osmium is one of the most dense elements (22.5 g/cm3). What is the mass of 10.0 cm3 of the metal?


a. 0.444 g

b. 2.25 g

c. 22.5 g

d. 225 g

e. 444 g

Back 11

d. 225 g

M=D times V

22.5g/cm3rd times 10.0cm3rd

Front 12

A glass cylinder contains four liquid layers: mercury (d = 13.6 g/mL), chloroform (d = 1.49 g/mL), water (d = 1.00 g/mL), ether (d = 0.708 g/mL). If a piece of ice (d = 0.917 g/mL) is dropped into the cylinder, where does it come to rest?


a. on top of the mercury layer

b. on top of the chloroform layer

c. on top of the water layer

d. on top of the ether layer

e. on the bottom of the cylinder

Back 12

c. on top of the water layer

Front 13

What are the freezing point and boiling point of water on the Celsius scale?


a. 0°C and 100°C

b. 0°C and 212°C

c. 32°C and 100°C

d. 32°C and 212°C

e. 273°C and 373°C

Back 13

a. 0°C and 100°C

Front 14

Aluminum melts at 1220°F. What is the melting point on the Celsius scale?


a. 646°C

b. 660°C

c. 696°C

d. 2138°C

e. 2164°C

Back 14

b. 660°C

C= 5/9 (1220F - 32)

Front 15

Liquid hydrogen boils at –252°C. What is the boiling point on the Kelvin scale?


a. –525 K

b. –252 K

c. –21 K

d. 21 K

e. 525 K

Back 15

d. 21 K

-252c + 273.15 = 21.15 Kelvin

Front 16

When 100.0 g of gasoline undergoes combustion, 9560 kJ of energy are released. Express the heat released in kilocalories. (Given: 4.184 J = 1 cal)


a. 2.28  103 kcal correct

b. 2.28  106 kcal

c. 2.28  109 kcal

d. 4.00  104 kcal

e. 4.00  107 kcal

Back 16

a. 2.28  103 kcal

9560 x 1 cal/4.184 j =

Front 17

How many kilocalories of heat are released when 125 g of water cools from 100.0°C to 19.5°C?


a. 0.644 kcal

b. 1.55 kcal

c. 2.44 kcal

d. 10.1 kcal

e. 12.5 kcal

Back 17

d. 10.1 kcal

125g x 1 calorie x 81.5 Celcius
convert 1 cal to .001 kiloCalorie.
Thus 125 x .001 x 81.5=
10.1875
= 10.1 kcal

Front 18

A 100.0 g sample of aluminum released 1680 calories when cooled from 100.0°C to 20.0¡C. What is the specific heat of the metal?


a. 0.168 cal/(g  °C)

b. 0.210 cal/(g °C)

c. 0.840 cal/(g  °C)

d. 4.76 cal/(g  °C)

e. 21.0 cal/(g  °C)

Back 18

b. 0.210 cal/(g°C)

1680cal/100g times 80celcius =

Front 19

How many significant digits are justified by the unit factor 1 lb/454 g?


a. 1

b. 2

c. 3

d. infinite

e. impossible to determine

Back 19

c. 3

Front 20

An economy car has an EPA highway mileage rating of 22 km/L. What is the mileage rating in miles per gallon? (Given: 1 mi = 1.61 km, and 1 gal = 3.78 L)


a. 3.6 mi/gal

b. 9.4 mi/gal

c. 35 mi/gal

d. 52 mi/gal

e. 130 mi/gal

Back 20

d. 52 mi/gal

22km/L x 3.78/1.61 = 52 m/gal

Front 21

A 73.6 g sample of aluminum is heated to 95.0°C and dropped into 100.0 g of water at 20.0°C. If the resulting temperature of the water is 30.0°C, what is the specific heat of the metal?


a. 0.143 cal/(g  °C)

b. 0.209 cal/(g  °C)

c. 0.418 cal/(g  °C)

d. 0.486 cal/(g  °C)

e. 0.679 cal/(g  °C)

Back 21

b. 0.209 cal/(g x °C)

First do the water:
100g x (1 calorie) x 10C "temp change" = 1000 calories
metal:
73.6g x C x 65C =
-4784 x c
C=4784
..........
1000cal/4784 =
0.209 cal/(gxC)