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33 Cards in this Set
- Front
- Back
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ozone symbol
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O3
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ozone occurs naturally at concentrations of
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60 micrograms/m^3
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the max acceptable exposure of ozone over an 8-hour period as established by the WHO is
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110 micrograms/m^3
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harmful ozone concentrations peak in the
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afternoon
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hydrocarbon emissions and NOx peak _______ and result from _______
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early in the day
incomplete combustion from automobiles |
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what is NOx
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NO, NO2
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what is critical to solving the problem of these reactions
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knowing the rate at which each of these compounds is formed and consumed
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which are emitted from auto comubstion
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NO and hydrocarbons
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hydrocarbons also come from
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plants
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No mixes with O2 to make
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NO2
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when the sun bakes NO2 it makes
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NO + O
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O mixes with oxygen to make
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ozone
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O mixes with hydrocarbons and O to make
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hydrocarbon radicals
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hydrocarbon radicals can turn into
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aldehydes or peroxy radicals
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peroxy radicals can turn into
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ozone
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the amount of a substance present at any given time is a combo of
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how fast it is made and how fast it is destroyed
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the rate constant, k, describes the
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rate of reaction
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the larger the rate constant,
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the faster the reaction
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the reaction scheme for reactions can be written as
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A--k1-->B--k2-->C
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the A->B->C expression can be understood as
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a function of the change of concentration of each species with the change in time
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differential rate expressions are
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a fancy way of describing the change in concentration of one species over time
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d[A]/dt =
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-k1[A]
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d[C]/dt =
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k2[B]
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time-dependent concentration of C will look ______ for k1>>k2 __ k2>>k1
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the same
as |
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the slowest step
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rate-determining step
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steady state approx is used when
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k2>>k1
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with the steady state approximation, we can conclude that the differential-rate law for species B is
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equal to zero
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what represented chemical molecules
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pieces of paper
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each experiment began with
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10 a molecules
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[A]_0
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the initial concentration of A
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how did we use the graphs to find k1 and k2
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we fit Afit, Bfit, and Cfit to A, B, and C
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true or false? if you arrive significantly late and if the TA perceives that time to be very late, he/she may decide not ot let you in for that lab session
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true
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d[b]/dt =
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k1[A] - k2 [B]
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