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12 Cards in this Set

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  • Back
In a one-way ANOVA, if the computed F statistic is greater than the critical F value you may
reject H0 since there is evidence that not all the means are the same.
When would you use the Tukey-Kramer procedure?
To test for differences in pairs of means
The F test statistic in a one-way ANOVA is
MSA/MSW
The degrees of freedom for the F test in a one-way ANOVA are
(c - 1) and (n - c).
In a one-way ANOVA, the null hypothesis is always
there is no difference in the population means.
An airline wants to select a computer software package for its reservation system. Four software packages (1, 2, 3, and 4) are commercially available. The airline will choose the package that bumps the fewest mean number of passengers as possible during a month. An experiment is set up in which each package is used to make reservations for 5 randomly selected weeks. (A total of 20 weeks was included in the experiment.) The number of passengers bumped each week is given below. How should the data be analyzed?
Package 1: 12, 14, 9, 11, 16
Package 2: 2, 4, 7, 3, 1
Package 3: 10, 9, 6, 10, 12
Package 4: 7, 6, 6, 15, 12
One-way ANOVA F test
When the F test is used for ANOVA, the rejection region is always in the right tail.
True
If you are comparing the mean sales among 3 different brands you are dealing with a three-way ANOVA design.
False
In a one-factor ANOVA analysis, the among sum of squares and within sum of squares must add up to the total sum of squares.
True
TABLE 11-1

An airline wants to select a computer software package for its reservation system. Four software packages (1, 2, 3, and 4) are commercially available. The airline will choose the package that bumps as few passengers as possible during a month. An experiment is set up in which each package is used to make reservations for 5 randomly selected weeks. (A total of 20 weeks was included in the experiment.) The number of passengers bumped each week is obtained, which gives rise to the following Excel output:

REF QUIZ11 #10 Table 11-1

Referring to Table 11-1, the within groups degrees of freedom is
16
ABLE 11-1

An airline wants to select a computer software package for its reservation system. Four software packages (1, 2, 3, and 4) are commercially available. The airline will choose the package that bumps as few passengers as possible during a month. An experiment is set up in which each package is used to make reservations for 5 randomly selected weeks. (A total of 20 weeks was included in the experiment.) The number of passengers bumped each week is obtained, which gives rise to the following Excel output:

REF QUIZ11 #11 Table 11-1


Referring to Table 11-1, the among-group (between-group) mean squares is
70.8.
TABLE 11-1

An airline wants to select a computer software package for its reservation system. Four software packages (1, 2, 3, and 4) are commercially available. The airline will choose the package that bumps as few passengers as possible during a month. An experiment is set up in which each package is used to make reservations for 5 randomly selected weeks. (A total of 20 weeks was included in the experiment.) The number of passengers bumped each week is obtained, which gives rise to the following Excel output:

REF QUIZ11 #12 Table 11-1


Referring to Table 11-1, at a significance level of 1%,
there is sufficient evidence to conclude that the mean number of customers bumped by the 4 packages are not all the same.