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18 Cards in this Set
- Front
- Back
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Mole
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The SI base unit used to measure the amount of a substance
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Avogadro's Number
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number 6.0221367 x 10^23; number of represenative particles in a mole
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Molar Mass
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The mass in grams of one mole of any pure substance
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Percent Composition
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The percent by mass of each element in a compound; Perecent Composition= (mass of element in 1 mole of compound/ molar mass of compound) x 100
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Empirical Formula
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Formula with the smallest whole-number mole ratio of the elements
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Molecular Formula
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Formula that specifies the actual number of atoms of each element in one molecule of a substance
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Hydrate
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Compound that has a specific number of water molecules bound to its atoms
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Mole to Molecule ratio
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1 Mole = 6.02x10^23 molecules
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Mole to Atoms ratio
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1 Mole = 6.02x10^23 atoms of one element
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The molar mass of carbon tetrachloride is ______ g/mol
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153.82
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What is the chemical formula of ammonium oxlate monohydrate?
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(NH4)2C2O4*H2O
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A compound that has specific number of water molecules bound to its atoms is known as what?
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Hydrate
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How many moles are present in 165 g manganese?
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3
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The name of this iron compound, FePO4*4H2O, is what?
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Iron (III) phosphate tetrahydrate
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Why isn't this the correct dimensional analysis setup to determine the mass of 4.50 moles of KCl?
4.50 moles KCl x (39.10 g/1 mole) = 176 g KCl |
The molar mass used must be the molar mass of the whole compound KCl not just the molar mass of K the conversion factor should read 74.55 grams/1 mole KCl
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A student heats a sample of Copper(II) Sulfate in a crucible and records the data shown in the table, what is the complete formula and name for the compound before heating?
Mass of empty crucible=127.40 g Mass of crucible + sample before heating = 152.00 g Mass of crucible + sample after heating = 146.90 g |
CuSO4*2H2O; copper (II) sulfate dihydrate
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Find the formula with the percent compostition shown
Ca 38.76 % of compound P 19.97 % of compound O 41.26 % of compound |
Ca3(PO4)2
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What is the correct dimensional analysis setup to convert 127.34 g of LiNO3 to number of molecules and find the final answer?
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127.34gx(1 mole/68.95g)x(6.02x10^23particles/1 mole)= 1.112x10^24 molecules
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