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64 Cards in this Set

  • Front
  • Back

1. ∆G0 is a representation of:

B & C



B. The energy produced by a reaction under standard conditions



C. The sum of the energy in the products minus the substrates

2. If the above had a ∆G0 of 0 Kcal, and the reactants were at the following concentration, A=10, B=lO, C=1 and D=1O; what would the G be?

-1 .36 Kcal

3. For another reaction as described above, at equilibrium A=[100mM], B=[10 nM], C=[10 mM] and D=[1 nM]; what is the equilibrium constant for this reaction:

0.01

4. What is the ∆G0 for the above reaction (question 3)?

2.72

5. The transition state for enzvmes involves:

A & B



A. Association of products and reactants with the enzyme.



B. The use of chemical around of the enzyme.

6. An enzvme catalvtic site:

None of the above.

7. The above represents what?

A & C



A. A reaction involving a transition complex.



C. An illustration of a chemical reaction involving an enzyme.

8. Which equation gives the rate of formation of product?

Kcat[ES]

9. The equation diagram from problem 8 is primarily of value in describing the formation of product at which stage of the reactions?

Very early followinq addition of enzyme to substrate.

10. For the above enzyme reaction, the compounds are burned to produce the following energy: AB = 10 Kcal, CD = 2 Kcal, AD = 10 Kcal and BD = 1 Kcal. What is the ∆G0 for the entire reaction?

-1 Kcal

11. Which is true?

None of the above.

12. The Gibbs free energy is which of the following?

b) The difference between the energy of the substrates and products.

13. According to the above reaction equation, which equation below gives the rate of formation of the transition complex?

K1[S] + K4[P]

14. According to the above reaction equation in question 13, which equation below gives the rate of formation of the transition complex at time = 0?

K1[S]

15. Why isn't temperature a factor in the equation for ∆G0?

Temperature does not alter the energetics of a reaction.

16. The above reaction comes to equilibrium at A = 10 units, B = 1 unit, C = 1 unit and D = 10 units. What is the ∆G0 for t his reaction?

0

17. The rate at which a reaction reaches equilibrium is dependent upon:

The enerqy of the transition state

18. From the above data, what is the Km (mMol/I) ?

2

19. What is one characteristic of a sequential reaction mechanism?

c. All substrates must bind before any products can be produced.

20. What type of inhibition does the above diagram refer to?

Non-competitive

21. Is there a way for the substrate to overcome this type of inhibition?

No.

22. What position on the enzyme does the inhibitor bind to?

To a site on the enzyme other than the catalytic site. Note, we at times call this an allosteric site. However, the word allosteric is often used more in reference to the special situation where the substrate itself binds not only to the catalytic site, but also to another, regulatory site on the enzyme.

23. What changes in this type of inhibition, Km or Vmax.

Vmax

24. (A) What type of inhibition does the above diagram refer to?

Allosteric substrate stimulation.

24. (B) Is there a way for the substrate to overcome this type of inhibition?

The substrate does not overcome this regulation but is rather responsible for it.

24. (C) What position on the enzyme does the inhibitor bind to?

In this case, the substrate binds to two sites, the catalytic site and a second, allosteric site. This binding can cause either stimulation or inhibition.

24. (D) What changes in this type of inhibition, Km or Vmax.

In this case, the resulting profile does not follow Mechaelis Menton kinetics, so discussion of Km and Vmax is not relevant.

25. Collagen consists of:

A & B



A. Three extended chains of amino acids.


B. A short repeating amino acid motif that generally includes proline.

26. What can be said of the globin protein?

A & B



A. It has many hydrophilic amino acids externally.


B. It consists of primarily hydrophobic amino acids internally.

27. Enzymes increase the rate of reaction by doing which of the following?

Reducing the activation energy of the transition state.

28. The Delta G0 is which of the following?

The difference between the energy of substrates and products.

29. The overall rate of a reaction is determined by:

The difference between the energy of the products minus the reactants.

30. The above reaction comes to equilibrium at A=1, B=1, C=1 and D=10. What is the ∆G0 for this reaction?

- 1.3 Kcal

31. If the ∆G0 for this reaction were 2.7 and A=1, B=1 and C=1; what would the concentration of D be at equilibrium?

.01

32. If each of these peptides were part of an alpha helix, which would you expect to be most likely to be located on the surface of the protein?

Val, Ile, Ser, Asp

47. The overall rate of a reaction is determined by:

None of the above.

48. The above graph represents the initial velocity as a function of the substrate concentration. What is the Vmax?

7

49. Which of the following is true under the following conditions: The enzyme concentration is 5 nM, the substrate concentration is 5mM and the Km is 5uM.

The enzyme is saturated with substrate.

50. Give an explanation for the reduction of Vmax in non-competitive inhibition.

The inhibitor effectively removes some of the enzyme, thereby making it appear that less total enzyme is present and thus a lower Vmax is seen for the enzyme.

51. In a sequential reaction:

The enzyme always exhibits substrate inhibition.

52. (A) What type of inhibition is exhibited in each of the graphs below?

Substrate stimulation

52. (B) What type of inhibition is exhibited in each of the graphs below?

non-competitive

52. (C) What type of inhibition is exhibited in each of the graphs below?

No inhibition, normal mechaelis kinetics.

53. In each case, can the inhibition be overcome by increasing substrate?

No.

54. (A) Where is the site of inhibition?

Substrate.

54. (B) Where is the site of inhibition?

Allosteric site.

54. (C) Where is the site of inhibition?

No inhibition.

55. (A) Is the Km altered?

Yes.

55. (B) Is the Km altered?

No.

55. (C) Is the Km altered?

Not applicable.

33. If each of these peptides were part of a beta sheet, which would you expect to be most likely to be located on the surface of the protein?

Phe, Ser, Ile, Arg

34. Enthalpy in the Gibbs free energy equation is the:

The energy of the products minus the energy of the reactants

35. Enthalpy in the Gibbs free energy equation is the:

Vmax

36. According to the above reaction equation, which equation below describes the condition at equilibrium?

[S]K1 + [P]K4 = [X]K2 + [X]K3

37. The Gibbs free energy is which of the following?

The difference between the energy of the substrates and products.

38. The above graph represents the initial velocity as a function of the substrate concentration. Why does it begin rapidly at first and then gradually decline to near a horizontal line.

Because the enzyme involved becomes saturated at high substrate concentration.

39. What are the characteristics of a ping-pong, double displacement reaction?

40. What type of inhibition is exhibited in the graph above?

Uncompetitive

41. What is altered by the inhibitor above (referring to question 40)?

B & C



B. Km



C. Vmax

42. When concentration of substrate is equal to Km then.

[E] = [ES]

43. When concentration of substrate is greater than Km which is true?

A & C



A. Almost all active sites are filled.



C. Reaction rate is independent of substrate concentration.

44. When concentration of substrate is less than Km which of the following is true?

B & C



B. Rate is proportional to [S].



C. [E] is about equal to [Etotal]

45. For another reaction as described above, at equilibrium A=[100mM], B=[10 nm], C=[10 mM] and D=[10nM]; what is the equilibrium constant for this reaction:

0.1

46. In the Gibbs free energy equation, entropy is related to:

Concentration of the products divided by that of the reactants.