Chm 131-005
5/5/18
Writing Assignment
Figure 1 [This diagram shows at what temperatures/pressures water changes phases. As shown in Figure 1 (“Interactive Student Tutorial”) above water turns into a gas at 100 degrees Celsius. At 0 degrees Celsius and below it becomes a solid. This diagram makes it easy to see that the energy needed (temperature) to change phases greatly increases]
Molality
Molality is the number of Moles of solute divided by kilograms of solvent (Tutapoint “Molality vs Molarity”)
M = (Moles of Solute)/(Kilograms of solvent)
What is the Molal concentration of 98.0794g H2SO4 in 1 kilogram of solvent?
(98.0794g H2SO4)/(1 Kilogram or 1000g) = 0.980794 Mol/Kg (Note correct number of significant figures are shown so further work is not necessary)
Molarity …show more content…
Step 1: Find how many mol of H2SO4 are in 210.0g
2 H x 1.0079g= 2.0158g 1 S x 32.066g = 32.066g 4 O x 15.9994g = 63.9976g
1 Mol of H2SO4 = 2.0158g + 32.066g + 63.997g = 98.0794g
210.0g H2SO4((1 mol)/(98.0794g H2SO4))= 2.141122397 Mol
Step 2: Plug values into equation
M=(Moles of solute)/(Volume of solution (L)) => M=(2.141122397 Mol)/(3 Liters) => M = .7137074657Mol/Liter
Step 3: Determine Appropriate number of significant figures. Round if