Purpose
In this experiment, volumetric glassware was used in order to determine the density of an unknown liquid. Additionally, the opposite process was used to determine the calibration of a piece of glassware using a known density. In the first activity, “Density of Liquids”, the identity of a liquid was determined by calculating its density (g/mL). First the mass (g) of a specific volume (mL) of water and the unknown liquid was found. Their densities (g/mL) were then calculated by dividing the mass (g) by the density), the calculated density was then compared to a list of known densities to determine the liquid’s identity. In the second activity, “Volumetric Pipette”, a 10 mL pipette’s calibration was tested. First the initial mass (g) and the temperature (°C) of the water were recorded, then using the pipette water was dispersed into a flask and weighed again. The mass (g) of the water dispersed in each trial was found by subtracting the initial mass from the final mass. Then by plugging the temperature into a line best-fit equation, the density of the water …show more content…
The calculated density of the water was found to be 0.9969 (g/mL). The density of water at 20.0 °C is listed to be 0.9982 (g/mL) which means the difference in densities could have been caused by a difference in temperature. The difference in density could be the result of an inaccurate measurement. The amount of liquid measured into the flask may not have been exactly 5.00 mL which would have altered the weight and volume of the sample. This difference would cause the density to be off by a small margin.
Also, during the first activity, the density of the unknown liquid A was found to be 0.6540 (g/mL). This density is close to the density of hexane which was listed to be 0.6548 (g/mL). The difference between the calculated density and the listed density is not too wide which means unknown liquid A is most likely
In this experiment, volumetric glassware was used in order to determine the density of an unknown liquid. Additionally, the opposite process was used to determine the calibration of a piece of glassware using a known density. In the first activity, “Density of Liquids”, the identity of a liquid was determined by calculating its density (g/mL). First the mass (g) of a specific volume (mL) of water and the unknown liquid was found. Their densities (g/mL) were then calculated by dividing the mass (g) by the density), the calculated density was then compared to a list of known densities to determine the liquid’s identity. In the second activity, “Volumetric Pipette”, a 10 mL pipette’s calibration was tested. First the initial mass (g) and the temperature (°C) of the water were recorded, then using the pipette water was dispersed into a flask and weighed again. The mass (g) of the water dispersed in each trial was found by subtracting the initial mass from the final mass. Then by plugging the temperature into a line best-fit equation, the density of the water …show more content…
The calculated density of the water was found to be 0.9969 (g/mL). The density of water at 20.0 °C is listed to be 0.9982 (g/mL) which means the difference in densities could have been caused by a difference in temperature. The difference in density could be the result of an inaccurate measurement. The amount of liquid measured into the flask may not have been exactly 5.00 mL which would have altered the weight and volume of the sample. This difference would cause the density to be off by a small margin.
Also, during the first activity, the density of the unknown liquid A was found to be 0.6540 (g/mL). This density is close to the density of hexane which was listed to be 0.6548 (g/mL). The difference between the calculated density and the listed density is not too wide which means unknown liquid A is most likely