III. Results
Table 2: KHP Vs. NaOH Titration data
Trial
Initial KHP acid Volume (ml)
End KHP acid volume (ml)
Volume difference (ml)
Volume of NaOH Base Used (ml)
1
7 mL
16 mL
9 mL
10.0 mL
2
16 mL
27.5 mL
11.5 mL
10.0 mL
3
27.5 mL
38.5 mL
11 mL
10.0 mL
Table 3: Titration of HCl with NaOH
Trial
Initial NaOH Volume (ml)
End NaOH base volume (ml)
Volume difference (ml)
Volume of HCl acid Used (ml)
1
4.5 mL
14.5 mL
10 mL
10.0 mL
2
30 mL
41.5 mL
11.5 mL
10.0 mL
3
19 mL
31 mL
12 mL
10.0 mL
Table 4: Standardization of Reagents
Trial
Primary Standard KHP Concentration (M)
Theoretical concentration of NaOH (M)
Standardized NaOH concentration (M)
Theoretical concentration of HCl (M)
Standardized HCl concentration (M)
1
0.1
0.1 …show more content…
The molar mass of KHP was 204.22g.
Molarity x Volume (L) = Moles of KHP
Moles of KHP x Molar Mass of KHP = grams of KHP
0.1 x 0.05 = 0.005 moles of KHP
0.005 x 204.22 = 1.0211 g KHP
Dilution of NaOH and HCl
To find out how to dilute NaOH and HCl the equation M1V1 = M2V2 is used. For both the M1 and V1 were given as 0.1 and 250 mL respectively. The M2 was given as 3. The equations were set up as follows: g HCL = 0.1 x 250 = 3 x V2 → (0.1 x 250)/3 = V2 = 8.3 g HCl g NaOH = 0.1 x 250 = 3 x V2 → (0.1 x 250)/3 = V2 = 8.3 g NaOH
Preparation of Ascorbic Acid Solution
The vitamin C tablet was crushed and 0.5 grams of ascorbic acid was mixed with 50 mL of deionized water to form the Ascorbic Acid Solution
Preparation of NaHCO3 solution
The baking soda was measured to 0.5 grams and was mixed with 50 mL of deionized water to form the Sodium Bicarbonate Solution.
Experimental Concentration of NaOH
M = Molarity or Concentration
Known moles of NaOH divided by known volume is equal to experimental concentration times experimental volume.
Experimental Concentration = 0.3 M
Experimental Concentration of …show more content…
The amount of components was found and quality control found that the manufacturers details were off. This proves that even professionals need quality control because they can knowingly or accidentally state the contents of a product inaccurately. There were sources of error throughout the experiment including non exact substance transfer, inaccurate magnet placement, and difficulty stopping tests at the proper time which could have led to the results being off. Nonetheless, it proves that error is possible and that it is necessary for quality control to incur.
VI. Research Connection In China, people have been treated for hepatitis with glycyrrhizin acid without really knowing what they are doing. Quality control is used to ensure that a manufacturer produces what they say and ensures that producers do not make false claims. When going over the checklist of items that the producers claimed, no study had examined each.2 After completing the study it was determined that the effectiveness of glycyrrhizin acid is low.2 In addition, the safety of using glycyrrhizin acid to treat hepatitis is unknown and will now require more clinical testing.2
Table 2: KHP Vs. NaOH Titration data
Trial
Initial KHP acid Volume (ml)
End KHP acid volume (ml)
Volume difference (ml)
Volume of NaOH Base Used (ml)
1
7 mL
16 mL
9 mL
10.0 mL
2
16 mL
27.5 mL
11.5 mL
10.0 mL
3
27.5 mL
38.5 mL
11 mL
10.0 mL
Table 3: Titration of HCl with NaOH
Trial
Initial NaOH Volume (ml)
End NaOH base volume (ml)
Volume difference (ml)
Volume of HCl acid Used (ml)
1
4.5 mL
14.5 mL
10 mL
10.0 mL
2
30 mL
41.5 mL
11.5 mL
10.0 mL
3
19 mL
31 mL
12 mL
10.0 mL
Table 4: Standardization of Reagents
Trial
Primary Standard KHP Concentration (M)
Theoretical concentration of NaOH (M)
Standardized NaOH concentration (M)
Theoretical concentration of HCl (M)
Standardized HCl concentration (M)
1
0.1
0.1 …show more content…
The molar mass of KHP was 204.22g.
Molarity x Volume (L) = Moles of KHP
Moles of KHP x Molar Mass of KHP = grams of KHP
0.1 x 0.05 = 0.005 moles of KHP
0.005 x 204.22 = 1.0211 g KHP
Dilution of NaOH and HCl
To find out how to dilute NaOH and HCl the equation M1V1 = M2V2 is used. For both the M1 and V1 were given as 0.1 and 250 mL respectively. The M2 was given as 3. The equations were set up as follows: g HCL = 0.1 x 250 = 3 x V2 → (0.1 x 250)/3 = V2 = 8.3 g HCl g NaOH = 0.1 x 250 = 3 x V2 → (0.1 x 250)/3 = V2 = 8.3 g NaOH
Preparation of Ascorbic Acid Solution
The vitamin C tablet was crushed and 0.5 grams of ascorbic acid was mixed with 50 mL of deionized water to form the Ascorbic Acid Solution
Preparation of NaHCO3 solution
The baking soda was measured to 0.5 grams and was mixed with 50 mL of deionized water to form the Sodium Bicarbonate Solution.
Experimental Concentration of NaOH
M = Molarity or Concentration
Known moles of NaOH divided by known volume is equal to experimental concentration times experimental volume.
Experimental Concentration = 0.3 M
Experimental Concentration of …show more content…
The amount of components was found and quality control found that the manufacturers details were off. This proves that even professionals need quality control because they can knowingly or accidentally state the contents of a product inaccurately. There were sources of error throughout the experiment including non exact substance transfer, inaccurate magnet placement, and difficulty stopping tests at the proper time which could have led to the results being off. Nonetheless, it proves that error is possible and that it is necessary for quality control to incur.
VI. Research Connection In China, people have been treated for hepatitis with glycyrrhizin acid without really knowing what they are doing. Quality control is used to ensure that a manufacturer produces what they say and ensures that producers do not make false claims. When going over the checklist of items that the producers claimed, no study had examined each.2 After completing the study it was determined that the effectiveness of glycyrrhizin acid is low.2 In addition, the safety of using glycyrrhizin acid to treat hepatitis is unknown and will now require more clinical testing.2