Identification of Unknown Compounds 64A and 64B
64A, was a white powdery solid substance. 64B, was a clear colorless liquid that had the smell of alcohol.
Solubility analysis is a method of identifying compounds based on how their behavior in other compounds. Solubility is the ability of a solvent to dissolve a solute. For a solvent to dissolve a solute, it has to be able to break the intramolecular forces of the solute. The intermolecular forces between the solvent and the solute have to be greater than the intramolecular forces between the solute particles. Polar substances dissolve in other polar substances so if an unknown compound dissolves in a known polar compound, one can come to the conclusion that the unknown substance is a polar compound. If it does not …show more content…
In this method, a solute is dissolved in a solvent at boiling point to increase solubility. The new solution is then cooled to get pure crystals of the solute. Using this technique of an unknown helps one get a pure substance which could be tested for melting point.
In Figure A, the red arrows show the series of test the first unknown 64A, was put through to determine what type of substance it was. Unknown 64A was insoluble in water, NaOH, and HCl; however it was soluble in H2SO4.
Figure A (Solubility path of compounds 64A and 64B)
Unknown 64B was found to be soluble in water. When it was put to the litmus test the litmus paper was unchanged. It is indicated in Figure A by the green color.
The melting point range of 64A was 48.1°C-49.3°C. Table 1 shows possible compounds that could be 64A. Based on the melting point, two possibilities from Aldehydes and Ketones on the QA Chart are 4-Chlorobenzaldehyde and Benzophenone respectively.
Table 1. Possible Compounds for 64A
64A Melting Point Possible Identities of 64A Melting Point of Possible Identities
48.1°C-49.3°C 4-Chlorobenzaldehyde
Benzophenone 48°C
64A, was a white powdery solid substance. 64B, was a clear colorless liquid that had the smell of alcohol.
Solubility analysis is a method of identifying compounds based on how their behavior in other compounds. Solubility is the ability of a solvent to dissolve a solute. For a solvent to dissolve a solute, it has to be able to break the intramolecular forces of the solute. The intermolecular forces between the solvent and the solute have to be greater than the intramolecular forces between the solute particles. Polar substances dissolve in other polar substances so if an unknown compound dissolves in a known polar compound, one can come to the conclusion that the unknown substance is a polar compound. If it does not …show more content…
In this method, a solute is dissolved in a solvent at boiling point to increase solubility. The new solution is then cooled to get pure crystals of the solute. Using this technique of an unknown helps one get a pure substance which could be tested for melting point.
In Figure A, the red arrows show the series of test the first unknown 64A, was put through to determine what type of substance it was. Unknown 64A was insoluble in water, NaOH, and HCl; however it was soluble in H2SO4.
Figure A (Solubility path of compounds 64A and 64B)
Unknown 64B was found to be soluble in water. When it was put to the litmus test the litmus paper was unchanged. It is indicated in Figure A by the green color.
The melting point range of 64A was 48.1°C-49.3°C. Table 1 shows possible compounds that could be 64A. Based on the melting point, two possibilities from Aldehydes and Ketones on the QA Chart are 4-Chlorobenzaldehyde and Benzophenone respectively.
Table 1. Possible Compounds for 64A
64A Melting Point Possible Identities of 64A Melting Point of Possible Identities
48.1°C-49.3°C 4-Chlorobenzaldehyde
Benzophenone 48°C