To start off the students had to use three measurements. They had built the pulley, in order to use the masses connected to the cart. The pulley and ramp would be in an inline position that then is measured next to the table by a protractor. One side of the string would hold the cart going down the ramp while the other side would hold weights. The students would put the car on the ramp …show more content…
Plugging that into the equation, getting (0.16kg)(9.8m/s2)=(9.8m/s2)Sin(36). The second step after distributing, which they get 1.568kg=m5.76; getting an answer of m=272kg. The group had to find the average of all three measurements to get a final answer of the mass of the object. 0.239kg+0.255kg+0.272kg=0.766kg/3=0.255kg. The students final answer was 0.255kg of the weight of the green car. Therefore the students findings had led them that the green cars measurement was 255g. After using the equation FT=Fp I have found that to calculate the mass you need the degree of the incline ramp and the mass of counterweights. The goal was to determine the mass of the cart to nearest gram and I used kilograms to then convert to grams. Being able to know the mass of an opposing and degree of the incline could easily help you determine the weight of the car's