# Na2co3 Stoichiometry Lab Report

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3 Pages

Introduction

The Objective was to determine the mass percent composition of the mixture using a chemical reaction and stoichiometry mixture Na2CO3 and NaHCO3. To do the lab by using the constant mass. Constant mass is a quantitative chemistry technique where a single chemical species or group reactants is heated with constant weighing until the mass does not change. After heated the Na2HCO3 will undergo a decomposition and Na2CO3 will not undergo reaction. The balanced equation is 2NaHCO3NaCO3+H2O+CO2. Find the mass percent position use the balanced equation and stoichiometry. Stoichiometry is the math behind chemistry,which using molar mass of reactant and products and calculate the missing variables using the ratio. Finally the mass composition

The mass of the mixture has a mass of 2.06g. The Mass of 1 mole of H2O and CO2 is 62.0g and mass of 2 moles of NaHCO3 is 168g. As can be seen from the calculation the mass percent of NaHCO3 is 1.35g and the Na2CO3 is 0.71g. Both combine together equal the mass of the mixture which are NaHCO3 and Na2CO3.

Discussion/Conclusions

The purple of this lab is to find the mass percent composition of the mixture by using chemical reaction and stoichiometry. The goal was well accomplished. The mass percent composition of NaHCO3 and Na2CO3 add together is equal to 100%. However both add together did not equal to 100%, it is equal to 93.4%. But, it is very close to 100%. The possible error sources error are did not use the balance correctly and the balance is not accurate. To avoid these errors by making sure the balance is 100% accurate and use the balance correctly.

Reference:

1.Holt chemistry. visualizing matter. (1996). Austin: Holt, Rinehart and

The Objective was to determine the mass percent composition of the mixture using a chemical reaction and stoichiometry mixture Na2CO3 and NaHCO3. To do the lab by using the constant mass. Constant mass is a quantitative chemistry technique where a single chemical species or group reactants is heated with constant weighing until the mass does not change. After heated the Na2HCO3 will undergo a decomposition and Na2CO3 will not undergo reaction. The balanced equation is 2NaHCO3NaCO3+H2O+CO2. Find the mass percent position use the balanced equation and stoichiometry. Stoichiometry is the math behind chemistry,which using molar mass of reactant and products and calculate the missing variables using the ratio. Finally the mass composition

*…show more content…*The mass of the mixture has a mass of 2.06g. The Mass of 1 mole of H2O and CO2 is 62.0g and mass of 2 moles of NaHCO3 is 168g. As can be seen from the calculation the mass percent of NaHCO3 is 1.35g and the Na2CO3 is 0.71g. Both combine together equal the mass of the mixture which are NaHCO3 and Na2CO3.

Discussion/Conclusions

The purple of this lab is to find the mass percent composition of the mixture by using chemical reaction and stoichiometry. The goal was well accomplished. The mass percent composition of NaHCO3 and Na2CO3 add together is equal to 100%. However both add together did not equal to 100%, it is equal to 93.4%. But, it is very close to 100%. The possible error sources error are did not use the balance correctly and the balance is not accurate. To avoid these errors by making sure the balance is 100% accurate and use the balance correctly.

Reference:

1.Holt chemistry. visualizing matter. (1996). Austin: Holt, Rinehart and