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Objective: To determine the Force, Mass, Acceleration relationship on an inclined plane with friction.
Hypothesis: Increasing the mass of the cart will decrease the …show more content…
∆x=vi∆tavg + 1/2a∆t avg2
Mass 1= 1.08
Mass 2= 1.93
Mass 3= 2.64
Complete a full analysis for each mass.(indicate formulas used for each computation and include all units)
Kinematics:
Known: vi=0 m/s ∆x= 0.91m ∆t avg= 1= 1.3s 2=1.97s 3= 0.83s a= 1= 1.08 2= 1.93 3= 2.64 m/s squared (v/t)
Unknown: vf =1= 1.4 m/s 2= 1.9 m/s 3= 2.2 m/s (Vf= Vi + at) ρf= 1= kgm/s 2= 0.04 kgm/s 3= 0.02 kgm/s ( p=mv)
1.89 N
1.89 N
Fn
Fn
0.189 N
0.189 N
0.318 N
0.318 N
Dynamics
FBD:
0.098 N
0.027 N
0.026 N
0.094 N
0.001 N
0.098 …show more content…
Reflect on the behavior of the carts motion based upon mass and angle. Defend your hypothesis based upon your findings.
My hypothesis was correct! My logic was that more weight would create more force and friction on the object, thus making it go slower and a shorter distance. Taking a look at the car’s design, I realized that the more weight put on, the more pressure on the wheels. So, when the weights got bigger the friction increased.
My group and I started off by measuring the ramp that the car was placed on. The car was 25 cm high on a 91 cm long ramp at an angle of 15.8˚ and was started from rest (Vi) (O). Instead of slowly increasing the mass, my group slowly decreased it. First mass, was a 0.2 kg weight (for trial 1), then a 0.02 kg weight (for trial 2), and then a 0.01 kg weight (for trial 3). Time ranged from around 1.3 seconds (s) (for trial 1) to 1 second (s) (for trial 2) then to 0.8 seconds (s) (for trial 3). The next step was to find the acceleration for which we used x=ViTavg + 1/2Tavg2. We realized the acceleration (a) got bigger as the mass did too, as it jumped from around 1.1 m/s 2(for trial 1) to about 1.9 m/s2(for trial 2) then finally to around 2.6 m/s2(for trial 3). Using (Vf= Vi + at) told us our velocity from there and it went from 1.4 m/s to 1.9 m/s to 2.2 m/s. Because of The results confirmed my hypothesis of, the lighter the weight, the faster the
Hypothesis: Increasing the mass of the cart will decrease the …show more content…
∆x=vi∆tavg + 1/2a∆t avg2
Mass 1= 1.08
Mass 2= 1.93
Mass 3= 2.64
Complete a full analysis for each mass.(indicate formulas used for each computation and include all units)
Kinematics:
Known: vi=0 m/s ∆x= 0.91m ∆t avg= 1= 1.3s 2=1.97s 3= 0.83s a= 1= 1.08 2= 1.93 3= 2.64 m/s squared (v/t)
Unknown: vf =1= 1.4 m/s 2= 1.9 m/s 3= 2.2 m/s (Vf= Vi + at) ρf= 1= kgm/s 2= 0.04 kgm/s 3= 0.02 kgm/s ( p=mv)
1.89 N
1.89 N
Fn
Fn
0.189 N
0.189 N
0.318 N
0.318 N
Dynamics
FBD:
0.098 N
0.027 N
0.026 N
0.094 N
0.001 N
0.098 …show more content…
Reflect on the behavior of the carts motion based upon mass and angle. Defend your hypothesis based upon your findings.
My hypothesis was correct! My logic was that more weight would create more force and friction on the object, thus making it go slower and a shorter distance. Taking a look at the car’s design, I realized that the more weight put on, the more pressure on the wheels. So, when the weights got bigger the friction increased.
My group and I started off by measuring the ramp that the car was placed on. The car was 25 cm high on a 91 cm long ramp at an angle of 15.8˚ and was started from rest (Vi) (O). Instead of slowly increasing the mass, my group slowly decreased it. First mass, was a 0.2 kg weight (for trial 1), then a 0.02 kg weight (for trial 2), and then a 0.01 kg weight (for trial 3). Time ranged from around 1.3 seconds (s) (for trial 1) to 1 second (s) (for trial 2) then to 0.8 seconds (s) (for trial 3). The next step was to find the acceleration for which we used x=ViTavg + 1/2Tavg2. We realized the acceleration (a) got bigger as the mass did too, as it jumped from around 1.1 m/s 2(for trial 1) to about 1.9 m/s2(for trial 2) then finally to around 2.6 m/s2(for trial 3). Using (Vf= Vi + at) told us our velocity from there and it went from 1.4 m/s to 1.9 m/s to 2.2 m/s. Because of The results confirmed my hypothesis of, the lighter the weight, the faster the