Mgcl2 Lab Report

We ran MgCl2 through various tests to see if its properties match our UWC. the first test was to compare the solubility of UWC and MgCl2. We added 1mL of distilled water to two different beakers each and gradually added 1g of MgCl2 and 1g of our UWC to each beaker. Approximately after 15 minutes, both solids dissolved in the water and MgCl2 passed this test. The second experiment was the halide test to determine if there are any Cl- ions in both solutions. We added 1 mL of 6M HNO3 and 1mL of 0.1M AgNO3 together to both 1mL of the unknown compound and another beaker 1mL of MgCl2 solution and detected if a white solid forms. In both beakers there was the formation of solid, which meant that was Cl- ions present in both beakers. Next we did the ammonium test to see the presence of any NH4 ions. We added 1 mL of 6M NaOH to both beakers that contained 1mL of unknown solution and 1mL of MgCl2 solution. Both beakers didn’t have any sort of ammonium smell. In the end MgCl2 passed the halide test but not …show more content…
The various experiments, we did the Halide test for Ions, ammonium tests, flame tests and solubility tests. According to the results in table 1.1, the unknown substance passed the halide test forming white precipitate, proving the presence of Cl- ions in it. While t failed the ammonium and sulfate test, demonstrating that NH4+ ions SO4 ions were not present in the compound. In general when the flame test is done, bright colors may appear, but this compound showed no color. We performed experiments and associated the volume of water of MgCl2 melted with that of our unknown and MgSO4 to figure out if they have the same ability to melt ice. According to the data provided in table 1.2 results of our tests conducted suggest that the identity of our unknown is MgCl2, because the capability of the known MgCl2 and unknown compound to liquefy ice was nearly the same, while MgSO4 had a lower