Discussion
The findings in this lab show that the melting point of Alum is 92.5 degrees Celsius. During the first trial a temperature of 91.0 degrees Celsius was recorded, but during the second trial a temperature of 93.0 degrees Celsius was found. Averaging the two temperatures gives a total around 92.0. The literature melting point of Alum is said to be 92.5 degrees Celsius and the data from similar studies, such as, Chemistry 103: Synthesis of Alum, together show that the results from the experiment were about 0.5 degrees Celsius off.
In the lab the hydration of water in Alum Crystals was determined. After completing the second part of the lab the mass of Anhydrous Alum and the amount of water driven off were found. The mass of Anhydrous …show more content…
Through the other procedures, the hypothesis for procedure two came out at most accurate, heating the alum Crystals and creating an anhydrous substance did cause a decrease in the mass proving procedure to be successful. Although the hypothesis for procedure three was reasonable complications with filtration did come up, the alum did not separate from the liquid properly, so a new direction was determined, which was letting the solution naturally separate and then evaporate the liquid until only powder was left leaving it successful. The importance of finding in the first lab was to predict that the melting point of alum was 92.5 degrees Celsius. The findings of the second, which was determining the hydration of water in alum crystals, wasn't fairly on point, but from other experiments they were fairly close. And on the third, which determined the percent of sulfate in alum, proved to be off by 50% because of the precipitates remaining in the crucible while being massed. Cooling was also important because the heat affects mass, and that could have thrown off the numbers on the balance as it was being massed and would have given a totally different calculation or might've damaged the scale. These tests weren't the only that could verify the composition of alum, but the IR spectrum would also be an
The findings in this lab show that the melting point of Alum is 92.5 degrees Celsius. During the first trial a temperature of 91.0 degrees Celsius was recorded, but during the second trial a temperature of 93.0 degrees Celsius was found. Averaging the two temperatures gives a total around 92.0. The literature melting point of Alum is said to be 92.5 degrees Celsius and the data from similar studies, such as, Chemistry 103: Synthesis of Alum, together show that the results from the experiment were about 0.5 degrees Celsius off.
In the lab the hydration of water in Alum Crystals was determined. After completing the second part of the lab the mass of Anhydrous Alum and the amount of water driven off were found. The mass of Anhydrous …show more content…
Through the other procedures, the hypothesis for procedure two came out at most accurate, heating the alum Crystals and creating an anhydrous substance did cause a decrease in the mass proving procedure to be successful. Although the hypothesis for procedure three was reasonable complications with filtration did come up, the alum did not separate from the liquid properly, so a new direction was determined, which was letting the solution naturally separate and then evaporate the liquid until only powder was left leaving it successful. The importance of finding in the first lab was to predict that the melting point of alum was 92.5 degrees Celsius. The findings of the second, which was determining the hydration of water in alum crystals, wasn't fairly on point, but from other experiments they were fairly close. And on the third, which determined the percent of sulfate in alum, proved to be off by 50% because of the precipitates remaining in the crucible while being massed. Cooling was also important because the heat affects mass, and that could have thrown off the numbers on the balance as it was being massed and would have given a totally different calculation or might've damaged the scale. These tests weren't the only that could verify the composition of alum, but the IR spectrum would also be an