Math 221 Entire Course Assignments Essay

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MAT 221 Week 1 Assignment 1 Simplifying Expressions
This assignment is comprised off of the properties of real numbers. In this assignment we will use these properties to simplify using 2a (a – 5) + 4(a – 5), 2w – 3 + 3(w – 4) – 5(w – 6), & 0.05(0.3m + 35n) – 0.8(-0.09n – 22m).
Simplifying: 2a(a-5)+4(a-5)
In this expression we will use the distribution property which will remove the parentheses. After this you will combine all of the like
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That is not inclusive but rather a compound inequality statement which is 17 < BMI < 22. Moreover, over 30 is an inequality statement with a positive infinity which is any BMI that is greater than 30, or BMI > 30 which will be written as (30, +∞). Anyway, my BMI will be calculated, and I will explain how I arrived at the results. Sometimes, a person’s BMI can be misleading, so reasons will be provided about why. Finally, there is an evaluation of the regions outside of the “probably not overweight” range by using the set and interval notations along with a simple graph of the regions.
Now, I am five feet and eleven inches tall, and I weigh 180 pounds. Remember that one foot is equivalent to twelve inches. Since I am five feet tall, we will multiply five with twelve to get sixty. Now, I am an additional eleven inches taller than five feet, that is, sixty inches. Hence, we will add eleven inches to sixty inches to make that seventy one inches. The formula is:
BMI = (703W)/(H^2) where BMI is the Body Mass Index, W is the weight in pounds, and H is height in inches. Since I am seventy one inches tall, we will denote that as H = 71. Since I am 180 pounds, we will denote that as W = 180. Hence, plug both of the values into the formula, which is BMI = (703*180)/(71^2). 71^2 is 71 squared which means that 71 times 71 is 5,041. 703*180 is 703 times 180 equals 126,540. Hence, we will have BMI =
MAT 221 Week 3 Assignment 3 Two-Variable Inequality

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