Essay on Lab 8 Ionic Reactions

1231 Words Jul 24th, 2014 5 Pages
Ocean County College
Department of Chemistry
Ionic Reactions
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Date Submitted: July 10, 2014
Date Performed: July 8 2014
Lab Section: Chem 181-DL2
Course Instructor: Amal Bassa

Aqueous solutions of ionic substances will be experimented with in this Ionic Reactions lab. Aqueous solutions are solutions that water is solvent. After ionic substances dissolve in water, ions separate and become surrounded by water molecules. When these ion separate, its called dissociation.

The purpose of this experiment is to study ionic reactions, to be able to write balanced equations, and to be able to write net ionic equations for precipitation reactions.

Procedure First, all
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Salts of nitrate: NO3-, chlorate: ClO3-, perchlorate: ClO4-, acetate: CH3CO2-, almost all salts of Cl-, Br-, I-, Salts of sulfate: SO4 2-.

E. Which cations generally do not form precipitates?
Cations of group one and two have barely any insoluble salts, therefore, they do not form precipitate. Cation of Cu, Ag, Fe, Ni, Co, Zn, Hg, Sb, Sn, Al, Cr, and Mn have more insoluble salts so these more commonly form precipitates.

F. Select 10 reactions that produce a precipitate, color change, or gas and write balanced chemical equation and a net ionic equation for each. Remember, a reaction may be indicated by the formation of a precipitate, color change, or the formation of gas. Record the well numbers of the precipitates you chose for your equations.
1) Well D3
Balanced: Ba(NO3)2 (aq) + Na2SO4 (aq)  BaSO4 (s) + Na2(NO3)2 (aq)
Ba 2+ (aq) + 2 NO3- (aq) + 2 Na+ (aq) + SO4 2- (aq)  BaSO4 (s) + 2 Na+ (aq) + 2 NO3- (aq)
Net Ionic Equation: Ba 2+ (aq) + SO4 2- (aq)  BaSO4 (s)
2) Well A7
Balanced: Co(NO3)2 (aq) + NaOH (aq)  CoOH (s) + Na(NO2)2 (aq)
Co 2+ (aq) + 2 NO3- (aq) + Na+ (aq) + OH- (aq)  CoOH (s) + Na+ (aq) + 2 NO3- (aq)
Net Ionic Equation: Co 2+(aq) + OH- (aq)  Co(OH)2 (s)
3) Well C5
Balanced: Fe(NO3)3 (aq) + Na2CO3 (aq)  FeCO3 (s) + Na2(NO3)2 (aq)
Fe 2+ (aq) + 3 NO3- (aq) + 2 Na+ (aq) + CO3 2- (aq)  FeCO3 (s) + 2 Na+ (aq) + 3 NO3- (aq)
Net Ionic Equation: Fe 2+ (aq) + CO3 2- (aq)  FeCO3 (s)
4) Well E5

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