Purpose
The purpose of this experiment is to identify the rate constant in kinetics reactions during the t-butyl chloride convert into hydrolyzed.
Theory
Kinetics reaction analyzes the how fast the chemical reaction occurs when two solution mix together. Chemical reaction is changing their properties and reagents concentration which create new products. There is a titration method to check the kinetic reaction.
For example, of chemical equation as aA + bB → cC+ dD
This equation describes the general term in rate of concentration. A and B is the reactant and C and D is the product thus, expresses the proportion. K is the rate constant and t is the change in time. reaction rate=-1/a d[A]/dt=-1/b b[B]/dt=1/c d[C]/dt=1/d d[D]/dt
Rate = K[A]x[B]y …show more content…
Obtain buret and rinse twice with 3 mL of NaOH and fill with NaOH. Hang it out with clamp. Cap buret with small beaker to prevent evaporation. In 250 mL flask, gain 100 mL of 50% isopropyl alcohol/water and add 5 drops of phenolphthalein. Then add 1 mL of tert-butyle chloride. And Then add 1 mL of the NaOH into the flask and mix it. Record the time after the solution change into pink to colorless. Repeat these 10 to 15 times and record their times. Also, record the temperature of solution. Obtain half full water in 600 mL beaker and heat up the water to 4O C. place the flask into the beaker for 60 min and wait the temperature at 35 C to 40 C. once again, Titrate with NaOH solution record the kinetic reaction as finial …show more content…
(mL to L) n(OH)= 0.25 mol/L * 0.004 = 0.001 moles n(OH)= 0.25 mol/L *0.005= 0.00125 moles n(OH)= 0.25 mol/L *0.006=0.00150 moles n(OH)= 0.25 mol/L *0.007= 0.00175 moles n(OH)= 0.25 mol/L *0.008= 0.00200 moles n(OH)= 0.25 mol/L *0.009 = 0.00225
n(RCL)=molarity x total V NaOH 39mL to 0.039 L n(RCL)= 0.25mol/L x 0.039 = 9.75 x 10-3 moles nRCl = n°RCl – nOH
Trail
n(RCL) = 9.75 x 10-3 - 0.001 = 0.0088 n(RCL) = 9.75 x 10-3- 0.00125 = 0.0085 n(RCL) = 9.75 x 10-3- 0.00150= 0.0083 n(RCL) = 9.75 x 10-3- 0.00175 = 0.0080 n(RCL) = 9.75 x 10-3 - 0.00200 =0.0078 n(RCL) = 9.75 x 10-3-0.00225 =0.0075
Discussion
The purpose of this experiment is to identify the rate constant in kinetics reactions during the t-butyl chloride convert into hydrolyzed.
Theory
Kinetics reaction analyzes the how fast the chemical reaction occurs when two solution mix together. Chemical reaction is changing their properties and reagents concentration which create new products. There is a titration method to check the kinetic reaction.
For example, of chemical equation as aA + bB → cC+ dD
This equation describes the general term in rate of concentration. A and B is the reactant and C and D is the product thus, expresses the proportion. K is the rate constant and t is the change in time. reaction rate=-1/a d[A]/dt=-1/b b[B]/dt=1/c d[C]/dt=1/d d[D]/dt
Rate = K[A]x[B]y …show more content…
Obtain buret and rinse twice with 3 mL of NaOH and fill with NaOH. Hang it out with clamp. Cap buret with small beaker to prevent evaporation. In 250 mL flask, gain 100 mL of 50% isopropyl alcohol/water and add 5 drops of phenolphthalein. Then add 1 mL of tert-butyle chloride. And Then add 1 mL of the NaOH into the flask and mix it. Record the time after the solution change into pink to colorless. Repeat these 10 to 15 times and record their times. Also, record the temperature of solution. Obtain half full water in 600 mL beaker and heat up the water to 4O C. place the flask into the beaker for 60 min and wait the temperature at 35 C to 40 C. once again, Titrate with NaOH solution record the kinetic reaction as finial …show more content…
(mL to L) n(OH)= 0.25 mol/L * 0.004 = 0.001 moles n(OH)= 0.25 mol/L *0.005= 0.00125 moles n(OH)= 0.25 mol/L *0.006=0.00150 moles n(OH)= 0.25 mol/L *0.007= 0.00175 moles n(OH)= 0.25 mol/L *0.008= 0.00200 moles n(OH)= 0.25 mol/L *0.009 = 0.00225
n(RCL)=molarity x total V NaOH 39mL to 0.039 L n(RCL)= 0.25mol/L x 0.039 = 9.75 x 10-3 moles nRCl = n°RCl – nOH
Trail
n(RCL) = 9.75 x 10-3 - 0.001 = 0.0088 n(RCL) = 9.75 x 10-3- 0.00125 = 0.0085 n(RCL) = 9.75 x 10-3- 0.00150= 0.0083 n(RCL) = 9.75 x 10-3- 0.00175 = 0.0080 n(RCL) = 9.75 x 10-3 - 0.00200 =0.0078 n(RCL) = 9.75 x 10-3-0.00225 =0.0075
Discussion