Isolated Colonies and Soil Samples A. Purification of Serratia marcescens and Staphylococcus epidermis The objective was to grow isolated colonies on a nutrient agar medium (NA). Many microorganisms found in soil are able to grow on this medium. Since there are many organisms that are found in the soil, only a few of this organisms are adapted to live in this specific medium obtained. The NA plate is the first way to isolate microorganisms because the organisms that will be left on the plate will be those who can live on the complex medium. The process of isolating a colony is done by “streaking out” isolated colonies found in a sample. Streaking out uses a sterile loop to dilute the sample and distribute single cells on a section of the
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The two locations that were chosen was near Littlefield dormitory (Sample A) and near the Biomedical Engineering building (Sample B). The procedure used to obtain these samples required using a moistened swab and sterile water. The moistened swab was inserted into the soil, below the surface, and then it was inserted and mixed into the sterile water. These two samples were then brought back into lab so that it could be streaked on two NA plates and two ACT plates. These “streaked out” samples were allowed to grow at room temperature for two days. Each member of the group was allowed to pick a specific area of one of the NA plates in order to isolate those colonies on to a new NA plate for further observation. Once the first isolation was made, the next isolation of the newly grown isolated colonies were isolated again after two days. These results can be seen in figure …show more content…
The first is done by inoculating the culture in a tube that contains glucose fermentation broth. These tubes, that contain the unknown culture, are allowed to incubate at the optimum temperature (room temperature) that the colonies were able to grow in. In order to determine whether or not my unknown was able to metabolize glucose, it would be expected that the tube would turn yellow. If it did not metabolize glucose, the broth would be red. If there was not growth the tube would remain clear. The results can be seen in figure 3.2 and the picture shows that the broth turned yellow. These results show that the unknown species was able to metabolize glucose. An oxidation reaction was done next to determine the bacteria contained the enzyme cytochrome C oxidase. This can be identified by using the reagent tetramethyl-p-phenylaminediamine (TMPD). If the enzyme is present then the filter paper will turn blue. Based on my results, my unknown does not contain he enzyme cytochrome C oxidase because it did not turn
The two locations that were chosen was near Littlefield dormitory (Sample A) and near the Biomedical Engineering building (Sample B). The procedure used to obtain these samples required using a moistened swab and sterile water. The moistened swab was inserted into the soil, below the surface, and then it was inserted and mixed into the sterile water. These two samples were then brought back into lab so that it could be streaked on two NA plates and two ACT plates. These “streaked out” samples were allowed to grow at room temperature for two days. Each member of the group was allowed to pick a specific area of one of the NA plates in order to isolate those colonies on to a new NA plate for further observation. Once the first isolation was made, the next isolation of the newly grown isolated colonies were isolated again after two days. These results can be seen in figure …show more content…
The first is done by inoculating the culture in a tube that contains glucose fermentation broth. These tubes, that contain the unknown culture, are allowed to incubate at the optimum temperature (room temperature) that the colonies were able to grow in. In order to determine whether or not my unknown was able to metabolize glucose, it would be expected that the tube would turn yellow. If it did not metabolize glucose, the broth would be red. If there was not growth the tube would remain clear. The results can be seen in figure 3.2 and the picture shows that the broth turned yellow. These results show that the unknown species was able to metabolize glucose. An oxidation reaction was done next to determine the bacteria contained the enzyme cytochrome C oxidase. This can be identified by using the reagent tetramethyl-p-phenylaminediamine (TMPD). If the enzyme is present then the filter paper will turn blue. Based on my results, my unknown does not contain he enzyme cytochrome C oxidase because it did not turn