Topic: Identifying Unknown Substances.
Equipments:
• 5 test tubes.
• 1 beaker of Acid 1 beaker of water
• 4-Litmus papers
• 2 Pipette bulbs.
• 1 robber stopper.
• 1 Bunsen burner.
• Q-tips(4).
• Scoopula.
Observation:
Which substance is which?
Hypothesis:
All the unknown substances that we have are soluble in water.
Procedure
• We had a 4 test tubes filled with small amount of white powder. We labeled each test tube. For example the first test tube was labeled as “Substance A” , the second test tube as “Substance B’’, the third test tube as “Substance C” and last test tube was labeled as “Substance D”
Water solubility test:
1. We took small amount of powder from test tube “A” and we put it on an empty test tube. We also took water from the water beaker using the pipette bulbs. We put the water on test tube “A”. We shook the test tube so that we can see whether the powder in test tube “A” is soluble with water. And then we cleaned the test tube after we were done with test tube “A”
2. We repeated the above step (1) with …show more content…
And according to my data only “Substance C” has the color purple when we put on the flame test. The only basic substance that we have is “Substance B”. According to the picture that I have in my data, Na2Co3 is basic. So that means “Substance B” is Na2Co3 (Sodium Carbonate). Again if we look at the color flame picture that I have, we can see that Magnesium is white, and in my color flame test “Substance A” didn’t show any colors when we put on the flame. This means that since Magnesium is colorless or white “Substance A” is MgSo4 (Magnesium Sulphate). Teacher Jin excluded “Substance D” because it was not pure enough to show or exhibit enough information, so that we can say “Substance D” is CaCo3 (Calcium Carbonate).For example in the flame test it didn’t show an orange color as it suppose
Equipments:
• 5 test tubes.
• 1 beaker of Acid 1 beaker of water
• 4-Litmus papers
• 2 Pipette bulbs.
• 1 robber stopper.
• 1 Bunsen burner.
• Q-tips(4).
• Scoopula.
Observation:
Which substance is which?
Hypothesis:
All the unknown substances that we have are soluble in water.
Procedure
• We had a 4 test tubes filled with small amount of white powder. We labeled each test tube. For example the first test tube was labeled as “Substance A” , the second test tube as “Substance B’’, the third test tube as “Substance C” and last test tube was labeled as “Substance D”
Water solubility test:
1. We took small amount of powder from test tube “A” and we put it on an empty test tube. We also took water from the water beaker using the pipette bulbs. We put the water on test tube “A”. We shook the test tube so that we can see whether the powder in test tube “A” is soluble with water. And then we cleaned the test tube after we were done with test tube “A”
2. We repeated the above step (1) with …show more content…
And according to my data only “Substance C” has the color purple when we put on the flame test. The only basic substance that we have is “Substance B”. According to the picture that I have in my data, Na2Co3 is basic. So that means “Substance B” is Na2Co3 (Sodium Carbonate). Again if we look at the color flame picture that I have, we can see that Magnesium is white, and in my color flame test “Substance A” didn’t show any colors when we put on the flame. This means that since Magnesium is colorless or white “Substance A” is MgSo4 (Magnesium Sulphate). Teacher Jin excluded “Substance D” because it was not pure enough to show or exhibit enough information, so that we can say “Substance D” is CaCo3 (Calcium Carbonate).For example in the flame test it didn’t show an orange color as it suppose