The objective of this experiment was to identify an unknown sample by preforming classification tests such as: Bisulfite test, Schiff’s test, and Idoform test. Also, to confirm the identity of the unknown by melting point, IR spectroscopy, and 1H NMR.
For the solubility test, 1 mL of deionized water was placed in a test tube. A few drops of the of the unknown was added to the test tube and mixed with a pipette. After a few minutes, the unknown was determined to be insoluble. Next, the Schiff’s test was conducted by adding 2 mL of Schiff’s reagent to a clean and dry test tube. Also, 4 drops of the unknown were added to the test tube and mixed with a pipette. The Schiff’s test was determined to be negative. Then, the Bisulfite test was conducted by adding 1 mL of Bisulfite solution to a clean, dry test tube. 8 drops of the unknown sample were added to the test tube and it was capped. After 10 minutes, the Bisulfite test was determined to be negative. After, idoform test for water-insoluble unknowns was performed. 2 mL of 1,2-dimethyloxyethane was placed in a plastic 15 mL conical test tube. Then 4 drops of the unknown sample and 2 ml of 3M NaOH was added to the conical test tube. Then 3 mL …show more content…
It was insoluble because it did not dissolve after ten minutes. The Schiff’s test was determined to be negative. This meant that the unknown sample did not have an aldehyde present because the solution did not turn purple-fuchsia and stayed yellow. The Bisulfite test was negative and that meant that the unknown did not have an aldehyde, unhindered cyclic ketone, or unhindered ketone present. The Iodoform test for water-insoluble unknowns was conducted and determined to be positive. The brown color of the reagent disappeared and yellow precipitate formed and meant that the unknown had a methyl ketone present. After the classification test, the possible unknowns were narrowed down to acetophenone, 2-octanone, and
For the solubility test, 1 mL of deionized water was placed in a test tube. A few drops of the of the unknown was added to the test tube and mixed with a pipette. After a few minutes, the unknown was determined to be insoluble. Next, the Schiff’s test was conducted by adding 2 mL of Schiff’s reagent to a clean and dry test tube. Also, 4 drops of the unknown were added to the test tube and mixed with a pipette. The Schiff’s test was determined to be negative. Then, the Bisulfite test was conducted by adding 1 mL of Bisulfite solution to a clean, dry test tube. 8 drops of the unknown sample were added to the test tube and it was capped. After 10 minutes, the Bisulfite test was determined to be negative. After, idoform test for water-insoluble unknowns was performed. 2 mL of 1,2-dimethyloxyethane was placed in a plastic 15 mL conical test tube. Then 4 drops of the unknown sample and 2 ml of 3M NaOH was added to the conical test tube. Then 3 mL …show more content…
It was insoluble because it did not dissolve after ten minutes. The Schiff’s test was determined to be negative. This meant that the unknown sample did not have an aldehyde present because the solution did not turn purple-fuchsia and stayed yellow. The Bisulfite test was negative and that meant that the unknown did not have an aldehyde, unhindered cyclic ketone, or unhindered ketone present. The Iodoform test for water-insoluble unknowns was conducted and determined to be positive. The brown color of the reagent disappeared and yellow precipitate formed and meant that the unknown had a methyl ketone present. After the classification test, the possible unknowns were narrowed down to acetophenone, 2-octanone, and