Hue, Saturation, And Intensity Aresi In HSI Color Model

Improved Essays
Hue, Saturation, and Intensity are represented as HSI in HSI colour model. The HSI model is used as an alternative to, or alongside the RGB representation. In this model, the hue of a colour is its angle measure on a colour wheel. Pure red have hue value as 0°, pure green have hue value as 120°, and pure blues have hue value as 240°. Neutral colours like white, grey, and black are set to hue value 0° for feasibility. Intensity is total brightness of the colour and also defined numerically as the average of the equivalent RGB values. Saturation is a measure of a colour’s purity/greyness. Purer colours have a saturation value closer to 1, while greyer colours have a saturation value closer to 0. Video signals and image signals are recorded …show more content…
The three colours are spread evenly on the circle over 360. Red is assigned to an angle of 0, while green to an angle of 120, blue to an angle of 240 and remaining colours can be found on the other points. Grey scale is located in the centre of the hue circle because all shades of grey are an even combination of the three main colours.
The saturation of a colour is the purity of a colour and tells the amount of white contained in the pure spectral colour. To represent the two hue and saturation, a vector pointing to the pure spectral colour is used and the value of this vector gives the saturation. For an example, an input signal of R=B and G=0 is given and this results in a pointer to 315 (Magenta). Because the magnitude of G is zero, there is no white contained in the representation of magenta and therefore the length of the vector is one. The intensity perception of a colour is represented in the HSI model by a second pointer and it is located at right angle to the hue–saturation vector because all colours fade either into pure white or black when the intensity is increased, or
…show more content…
As the RGB to HSI image processing algorithm is be implemented in hardware, a digitised version of the three primary colours are used. For the implementation of the RGB to HSI algorithm in hardware R, G, B are used specifically to indicate digitised inputs of red, green and blue. Quantisation of each input signal is eight bits which results in a 24 bit RGB images, these are standard for high quality image reproduction and can be used in image recording formats such as BMP, PPM and Sun Raster

Related Documents

  • Improved Essays

    By figuring out the color position, we looked at the fraction of the red and greens light orange has; .75R and .2G. In order to find out the fraction of blue, we used the equation 1 = r+ g +b because the fractions of red, green and blue equal to one (Gilbert 103). We substituted in r and g and got b by itself; in order to get b by itself, we subtracted r and g from both sides resulting in b = 1 - r -g. The fraction of blue is .05. Next we calculated the…

    • 799 Words
    • 4 Pages
    Improved Essays
  • Great Essays

    The Rf values for the green dye used in the green Crayola marker are .958, 1.00, .970, .970, and .990. The statistics for these numbers are .978 for the mean, .970 for the median, .970 for the mode, .0170 for the standard deviation, and .978 ± .0170 for the best answer. Finally, the Rf values for the dye used in the orange Crayola marker are .931, .918, .961, .899, and .969. The statistics for these numbers are .936 for the mean, .931 for the median, no mode, .0293 for the standard deviation, and .936 ± .0293 for the best answer. Overall, the statistics for the Rf values of the dyes used in Crayola markers significantly vary from the statistics of the dyes used in the Skittles of the same color.…

    • 2116 Words
    • 9 Pages
    Great Essays
  • Superior Essays

    Lens Equation Analysis

    • 1124 Words
    • 4 Pages

    This means that the tanθ is the same for each triangle; Tanθ=opp/adj=h_0/f=(-h_1)/(d_1-f) Where h_0 is the object height, f is the focal length, h1 is the image height, d0 is the object distance and d1 is the image distance For the triangle below the central axis a minus sign has been added. This is because both θ are assumed to be positive. However the image height is inverted and therefore negative so to keep both tanθ’s positive a minus sign has been added. The same operation done above can also be done for the similar triangles in figure 3. Tanθ^ '=h_0/d_0 =(-h_1)/d_1…

    • 1124 Words
    • 4 Pages
    Superior Essays
  • Improved Essays

    The only peak in absorbance is at the lowest end of the visible light spectrum, with a continuous decrease in absorbance as wavelength increases. This coincides with the observation of red as the color of the corresponding solution, since red is at the opposite end of the spectrum. Figure 4 is the spectrum of the cobalt complex with CO3 as its ligand. This complex was observed to be green. This is justified by the dip in absorbance for this complex around the 550 nm mark, since that is the wavelength of green light.…

    • 1030 Words
    • 5 Pages
    Improved Essays
  • Great Essays

    8.5 Also examine the calculated value of the lowest calibration standard (MRL). This step is used to ensure analytes can be accurately reported at the quantitation limit or to demonstrate bias in the calibration model. If the value exceeds 50% of the expected value, inspect the curve for proper values, proper integration and identification, or ensure proper standards were…

    • 1252 Words
    • 5 Pages
    Great Essays
  • Superior Essays

    Color Analysis Lab

    • 1098 Words
    • 5 Pages

    The purpose of this lab is to determine the Ka of an indicator within an unknown solution. This can be determined because acid-base indicators are weak bases or acids, and when neutralized they change colors. The color change is measured by the light absorption spectra in the compound which can be used to calculate the concentration. This experiment measures the concentrations by the different pH values which allows the pKa and Ka to be determined. Through the experiment, and the recorded color change with the use of the Spec 20 the unknown Ka of the solution was found.…

    • 1098 Words
    • 5 Pages
    Superior Essays
  • Improved Essays

    Langmuir Isotherm Essay

    • 924 Words
    • 4 Pages

    Langmuir isotherm The Langmuir adsorption model is established on the following hypotheses: (1) uniformly energetic adsorption sites, (2) monolayer coverage, and (3) no lateral interaction between adsorbed molecules [26]. A mathematical expression of the Langmuir isotherm is given by the following equation: Where qe (mg/g) is the amount of dye adsorbed on the solid adsorbent at equilibrium, qm (mg/g) is the maximum adsorption capacity, KL (L/mg) is the Langmuir equilibrium constant, and Ce (mg/L) is the EBT dye concentration at equilibrium. The essential characteristic of the Langmuir isotherm can be expressed by the dimensionless constant called equilibrium parameter, RL, defined by: Where C0 is the initial EBT…

    • 924 Words
    • 4 Pages
    Improved Essays
  • Superior Essays

    The 1st limitation is that Beer’s law considers that the radiation reaching the sample is of a single wavelength i.e. that the radiation is purely monochromatic. however, even the best wavelength selector passes radiation with a small, but finite effective bandwidth. Polychromatic radiation always gives a negative deviation from Beer lambert’s law, but the effect is smaller if the value of ε is essentially constant over the wavelength range passed by the wavelength selector. For this reason, it is better to get absorbance measurements at the top of a broad absorption peak.…

    • 1410 Words
    • 6 Pages
    Superior Essays
  • Superior Essays

    examples of white-tuning Potential issues • The wiring could be complex because the controllers of intensity and CCT are separate. • Low efficiency compared to non-tunable white LEDs. Full-color tuning Also referred to as RGB, RGBA, RGBW, spectrally tunable and “color changing”, full-color tunable products often consist of 3 or more LED sets. The individual LEDs can be narrow-band LEDs (producing a “pure” color, usually RGB), or coated LEDs. The monochromatic LEDs are usually red, green and blue (the primary colors of light, RGB), and can be augmented with amber (A) and white (W).…

    • 901 Words
    • 4 Pages
    Superior Essays
  • Improved Essays

    If the solution tested negative, it stayed the yellow colour of the iodine solution. Whereas, if the solution tested positive for glycogen it turned a red-brown colour (Morris, 1946). Additionally, the solution turned a blue-black colour if the iodine reacts starch (Bailey & Whelan, 1961). For this test,…

    • 1203 Words
    • 5 Pages
    Improved Essays