Initially, sand and hydrogen peroxide were added in a test tube to create a mixture. Based on the observation conducted, no reaction was visible (i.e. no gas occurred). In result, the solution did not react because it does not contain the desired enzyme in order to break down H2O2. An enzyme is needed to decompose H2O2 into water and oxygen. With this knowledge, students were able to determine that the results for the rest of the tests did make sense. For example, the solution contained manganese dioxide and H2O2 reacted. This indicates that catalase enzyme was present in manganese dioxide which is classified as an inorganic compound. When these two substances mixed, H2O2 eventually turned into water and oxygen. The rate of reaction of this
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Hence, the presence of catalase enzyme activated hydrogen peroxide to break down into water and oxygen.
In the second and third step, it was observed that the all mixtures contained enzymes other than potato. When liver and H2O2 created into a solution, heat was produced and bubbles formed. Since the test tube has gotten warmer, the reactions took place would be exothermic. Table 2 shows the effect of an enzyme between H2O2 with liver and potato. The result of the liver with H2O2 provided an evidence that an enzyme was present. The fresh liver contained catalase thus it was expected to break down hydrogen peroxide (Scientific American, 2016). This can be proven based on observations conducted during lab. When this reaction occurred, oxygen gas were produced and created foam. On the other hand, when piece of potato exposed to H2O2, the solution did not react. According to research, this reaction should have occurred. Since potato also contain catalase, meaning it should have broken H2O2 into oxygen and water (Rembac, 2013). One possible source of error during the test of potato and H2O2 would have been because the potatoes were pre-cuts for the lab. If the …show more content…
The most favorable pH value is the point where the enzyme is most active. This is known as the optimum pH. Extremely high or low pH values generally result in complete loss of activity for most enzymes. Lower pH values mean higher H+ concentrations and lower OH- concentrations (Adam- Day, 2015). The results presented on table 4 showed that the liver dipped in 100% has lower reaction rate compared to liver dipped in 50% vinegar reacting with H2O2. The liver dipped in 100% concentration has a very high pH values. Although exergonic reaction occurred in both concentration test, they produced different amount of bubbles and different rate of reaction. The one exposed in 100% concentration formed less amount of bubbles and slower rate of reaction due to its extreme pH values. The extreme acidity altered the enzyme. In comparison, the one exposed in 50% concentration has more efficient enzymes because its pH values is moderate- not too high or low (refer to table 4). The evidence showed that the reaction bubbled rapidly with a result of 60 mL of gas produced in 20 seconds. Hence, the liver placed in a higher concentration will have a slower reaction compared to the liver added in a lower
Hence, the presence of catalase enzyme activated hydrogen peroxide to break down into water and oxygen.
In the second and third step, it was observed that the all mixtures contained enzymes other than potato. When liver and H2O2 created into a solution, heat was produced and bubbles formed. Since the test tube has gotten warmer, the reactions took place would be exothermic. Table 2 shows the effect of an enzyme between H2O2 with liver and potato. The result of the liver with H2O2 provided an evidence that an enzyme was present. The fresh liver contained catalase thus it was expected to break down hydrogen peroxide (Scientific American, 2016). This can be proven based on observations conducted during lab. When this reaction occurred, oxygen gas were produced and created foam. On the other hand, when piece of potato exposed to H2O2, the solution did not react. According to research, this reaction should have occurred. Since potato also contain catalase, meaning it should have broken H2O2 into oxygen and water (Rembac, 2013). One possible source of error during the test of potato and H2O2 would have been because the potatoes were pre-cuts for the lab. If the …show more content…
The most favorable pH value is the point where the enzyme is most active. This is known as the optimum pH. Extremely high or low pH values generally result in complete loss of activity for most enzymes. Lower pH values mean higher H+ concentrations and lower OH- concentrations (Adam- Day, 2015). The results presented on table 4 showed that the liver dipped in 100% has lower reaction rate compared to liver dipped in 50% vinegar reacting with H2O2. The liver dipped in 100% concentration has a very high pH values. Although exergonic reaction occurred in both concentration test, they produced different amount of bubbles and different rate of reaction. The one exposed in 100% concentration formed less amount of bubbles and slower rate of reaction due to its extreme pH values. The extreme acidity altered the enzyme. In comparison, the one exposed in 50% concentration has more efficient enzymes because its pH values is moderate- not too high or low (refer to table 4). The evidence showed that the reaction bubbled rapidly with a result of 60 mL of gas produced in 20 seconds. Hence, the liver placed in a higher concentration will have a slower reaction compared to the liver added in a lower