Compound X Is A White Powder Observation Essay

Improved Essays
1. Observation.
- Compound X is a white powder. It is a solid.

2. Questions.
- What is compound X?
- What will happen when compound X is heated and reacted with C20H14O4 (phenolphthalein – an acid-base indicator)? (1)
- How does compound X react with C20H14O4 (phenolphthalein)? (2)
- How does compound X react with water? (3)
- How does compound X react with hydro chloric acid (HCL)? (4)

3. Predictions.
- Compound X is calcium carbonate (CaCO3).
- (1) When compound X is heated and reacted with C20H14O4, the substance will turn pink.
- If a red litmus paper is dipped in the substance moistened with de-ionized water, it will turn blue.
- (2) When C20H14O4 is added to compound X, the product will be a white liquid, and no other change will occur.
…show more content…
Next, compound X is heated in a beaker with the burner. Then C20H14O4 is added with a dropper pipet. Observations are made. (1)
Second of all, using a lab scoop, 0.4 g from compound X is put into a 50 ml beaker. It is weighted out with a digital balance. Then, the first step of the experimenting procedure is: with a lab scoop, a small amount of the substance goes into one of the test tubes. After that, phenolphthalein is added using a clean dropper pipet. Observations are made. This will determine whether compound X is a base, an acid, or a salt (neutral). (2)
Then, into another test tube a small amount of compound X is put using the same method. Next, water is added to the substance with a clean dropper pipet to see its reaction with water. Observations are made. (3)
Finally, the first step is repeated. Afterwards, hydro chloric acid (HCL) is added with a clean dropper pipet to the content. Observations are made. (4)
Additionally, a lit candle is put into the beaker with the rest of compound X in it. Subsequently, hydro chloric acid is added to the powder with a dropper pipet. This will determine what the released gas is (if there is any). (4)
7.
…show more content…
Compound X is calcium carbonate (CaCO3). First of all, the prediction about the phenolphthalein turning the heated compound X into a pink liquid was supported, which means that it is not a base or an acid. The hypothesis was also backed up – compound X is a salt (calcium carbonate (CaCO3) =(heat)= calcium oxide (CaO) + carbon dioxide (CO2)). Additionally, the phenolphthalein did not change compound X’s color, so the prediction and the hypothesis were supported – compound X is a salt. Furthermore, the experiment with the litmus paper has the same results – both the prediction and the hypothesis were supported (the substance is a salt). Moreover, the prediction and the hypothesis about the dissolving of the powder in water were not supported. Compound X is insoluble (it has very low solubility). Lastly, both the prediction and the hypothesis about compound X’s reaction with hydrochloric acid (HCL) were supported. There is a reaction whose products are water and salt (and a gas – carbon dioxide). The reaction is as follows: X + 2HCL = H2O + CO2 + salt (metal of X+CL2). Due to the reason that this reaction needs two chloride molecules, the electrical charge of the metal of compound X should be +2. A number of sources show that therefore, compound X is calcium carbonate

Related Documents

  • Improved Essays

    Salicylamide and NaI were dissolved in ethanol and cooled in a water bath. Then household bleach was added while stirring vigorously. Then NaOCl and HCl were added as well. Product was collected by vacuum filtration and then recrystallized from 96% ethanol and obtained a yield of 2,07g (54%). IR- and H-NMR-spectrum were taken.…

    • 960 Words
    • 4 Pages
    Improved Essays
  • Improved Essays

    In this lab there was 2 objectives which where to recognize when a chemical reaction has occurred and practice collecting detailed observations in the laboratory using proper scientific terms. Reaction set #1 (1a) place approximately 1 ml of 0.1 M Pb (No3)2 solution into a test tube. Then sequentially add drops of 0.25M k2CRO4 solution until you see evidence of a chemical reaction. The products of this reaction are aqueous KNO3 and solid PbCrO4. (1b) place approximately I ml of .1M Pb (NO3)2 solution in a test tube.…

    • 867 Words
    • 4 Pages
    Improved Essays
  • Improved Essays

    Sulphamic Acid Case Study

    • 2390 Words
    • 10 Pages

    moisture : 1-3% 7. Sulphate as SO4 : 0.1-0.5% 8. Physical Appearance : white powder 1.4 Literature Survey In the first method, the SO3 are reacting with the NH3, in first stage. And after made up the ammonium sulfamino and its react with sulphuric acid in a second stage, it is giving the ammonium bisulphate. The ammonium bisulphate is separated by the filtration in form of the ammonium sulphate.…

    • 2390 Words
    • 10 Pages
    Improved Essays
  • Improved Essays

    Methyl Orange Essay

    • 1375 Words
    • 6 Pages

    The las experimental step was to wash the conical flask carefully with distilled water and to repeat the titration with a new amount of water. After this the following data was…

    • 1375 Words
    • 6 Pages
    Improved Essays
  • Superior Essays

    The test was determined complete when sample of the reaction mixture was repeatedly added to the potassium iodide starch test. Once the paper no longer turns blue-black the reaction is considered complete. Potassium iodide starch test paper is a paper strip use to determine if excess sodium hypochlorite remains in the flask. A diethyl extraction was used to remove the lower aqueous layer of the product after the potassium iodide starch test. This removes unreacted diol and leftover acids.…

    • 1586 Words
    • 7 Pages
    Superior Essays
  • Improved Essays

    The aqueous layers were washed once more with dichloromethane to make the solution consist mostly of eugenol acetate. HCl was added to the solution in order to make the…

    • 481 Words
    • 2 Pages
    Improved Essays
  • Great Essays

    Dehydration Lab Report

    • 1082 Words
    • 5 Pages

    Experimental: Fractional distillation is setup by adding 25.0 ml of 2-methylcyclohexanol in a 100-ml round bottom flask and to this 10 ml of 9 M sulfuric acid is added which acts a catalyst to this reaction. The content is swirled is completely for about 2 minutes periodically. Then 3 boiling chips is added to the mixture, now starts the fraction distillation. The mixture is heated with a heating mantle for distillation to occur. It is heated until 10-ml of the mixture remains in the reaction flask or less than 100°C.…

    • 1082 Words
    • 5 Pages
    Great Essays
  • Improved Essays

    Next, 25mL of 0.1 M Acetic acid is pipetted into a 100mL beaker. The 0.1 M Acetic acid is titrated with the 0.1 M NaOH in increments given in the data sheet; mixing well at each point and wait until the pH stabilizes. The pH is recorded at each increment and the electrode is rinsed with distilled water and placed back in the beaker with distilled water. Then, 25mL of 0.1 M Acetic acid is pipetted into a 250mL Erlenmeyer flask. Next, 2-3 drops of the proper indicator is added.…

    • 1003 Words
    • 4 Pages
    Improved Essays
  • Superior Essays

    The appearance is white, it looks sugary/rocky, and has no odor. Sodium Chloride and Potassium Bromide were soluble in distilled water. This is because Sodium Chloride and Potassium Bromide are made from positive sodium ions bonded to negative chloride ions. “Water can dissolve salt because the positive part of water molecules attracts the negative chloride ions and the negative part of water molecules attracts the positive sodium ions” (Jerry Bell, PhD, 2015). Sodium Chloride and Potassium Bromide had a conductivity level of high meaning that the compound is conductive.…

    • 1040 Words
    • 5 Pages
    Superior Essays
  • Superior Essays

    Single displacement reaction happens in the test tube A and double displacement reactions occur in both test tube B and C. In test tube A, the reactants are copper sulfate and magnesium. Magnesium is an element and copper sulfate is a compound. In a single displacement reaction, a reactive element displaces another less reactive element in a compound. After checking the activity series for metals, I know that magnesium is more reactive than copper sulfate; so that in the reaction, magnesium takes place of the copper element in copper sulfate to produce copper metal and magnesium sulfate. During the reaction, a red-brown precipitate is produced.…

    • 1182 Words
    • 5 Pages
    Superior Essays