Essay on Experiment 2: Laboratory Techniques and Measurements

1687 Words Oct 8th, 2012 7 Pages
Experiment 2: Laboratory Techniques and Measurements

Course Number: CHE 111

Abstract: This experiment introduced the student to lab techniques and measurements. It started with measuring length. An example of this would be the length of a nickel, which is 2cm. The next part of the experiment was measuring temperature. I found that water boils around 95ºC at 6600ft. Ice also has a significant effect on the temperature of water from the tap. Ice dropped the temperature about 15ºC. Volumetric measurements were the basis of the 3rd part of the experiment. It was displayed during this experiment that a pipet holds about 4mL and that there are approximately 27 drops/mL from a short stem pipet. Part 4 introduced the student to measuring
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It would measure the weight of the object, not the weight of the volume of water displaced by the object.

G. How did the magnet’s density measurement using the Archimedes’ Principle compare to the density measurement using the calculated volume? Which method might be more accurate?
Why? The measurements were not even close. The mass was consistent, but the volume was different. As we all know, if the volume is off, the density calculation will be off. I’m sure the calculated volume is more accurate, but it is very hard to replicate mathematical calculations in the lab. There is too much room for human error.

H. You are given a small piece of gold colored material and you want to determine if it is actually gold. Using the Archimedes Principle you find that the volume is 0.40 cm3 and the mass is 6.0g. What conclusions can you reach from your simple density analysis? The density is 15g/cm³. That would mean the material is not dense enough to be gold.
Measurements
I. How would you prepare 10 mL of a 0.25M HCl solution if 1M HCl was available? How much
1M HCl is needed? How much distilled water is used?
M1*V1 = M2*V2
M1 = 0.25 M
V1 = 10 mL
M2 = 1 M
V2 = M1*V1 / M2 = 0.25 x 10 / 1 = 2.5 mL
In order to prepare 10 mL of 0.25 M HCl solution, you need dilute 2.5 mL of 1M HCl to 10 mL by adding (10 mL - 2.5 mL = 7.5 mL) water to it.

J. Assuming that your colored drink was originally 2.43 M, what is the

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