Excess Aluminium Lab Report

Decent Essays
This lab is designed to find the mass of copper produced when excess aluminium is reacted with 2.00g of copper salt [Copper (II) chloride decahydrate]. This will be achieved by dissolving the given amount of copper salt in distilled water and then adding in the aluminium rod. The reaction will commence as copper will begin to form on the aluminium.

Calculating the percent yield is commonly used in the atom economy of a chemical reaction, which is a measure of the initial substance which becomes the useful product(s). Reactions with low efficiency which generate a great amount of waste and produce a smaller amount of the product desired have low atom economies and therefore a lower percent yield. On the contrary, chemical reactions which creates little waste and a greater quantity of the needed product has a high atom economy and a percent yield closer to 100% as fewer atoms are being lost, in the sense of waste. Scientists, working in chemical manufacturing factories, use the theoretical yield to determine the maximum amount of product that can be produced by a certain chemical reaction. Product can also be lost in filtration and transferring process. Scientists can then test and modify the procedure and variables so that the actual yield is as close to the theoretical yield as possible, therefore increasing the percent to an ideal 100%. This allows big companies and manufacturers to gain more profit and helps reduce environmental risks as less waste and potentially harmful products are being produced.
…show more content…
If the copper salt and aluminium reacts ideally then, the actual yield of copper produced will be equal to the theoretical yield, which is determined through calculations, meaning there is a 100% yield because it is the maximum amount of copper which can be produced with the given amount of copper

Related Documents

  • Great Essays

    The maximum amount of product that can be determined from an experiment is called the limiting reagent, this is because this reagent runs out first. In our lab the amount of Cu3(PO4)2 was determined from the amount of CuCl2 in the reaction. When CuCl2 ran out no more Cu3(PO4)2 could be produced. The theoretical Yield is found by calculating the maximum amount of product the limiting reagent can produce. The theoretical yield in our experiment was .304 grams, we calculated this value using stoichiometry from the the following equation:2 Na3PO4 + 3 CuCl2 → Cu3(PO4)2 + 6 NaCl .Since…

    • 779 Words
    • 4 Pages
    Great Essays
  • Improved Essays

    This lab makes use of the reaction excess powdered calcium carbonate and different concentrations limiting hydrochloric acid in order to determine the effect of changing concentration on the rate of the reaction. Students will carry out 3 trials of 5 experiments each trial. The five different experiments are for the various concentrations of hydrochloric acid (0.2, 0.4, 0.6, 0.8, 1.0 mol/L). First measure out approximately 2 grams of powdered calcium carbonate using a weighing boat and analytical balance. Then, measure out 30 mL of 0.2 M hydrochloric acid into a volumetric flask.…

    • 198 Words
    • 1 Pages
    Improved Essays
  • Decent Essays

    Alka Seltzer Lab Report

    • 426 Words
    • 2 Pages

    Introduction An Alka seltzer is a Blood thinner and a nonsteroidal anti-inflammatory drug that can treat pain, fever, headache, and inflammation. Its two main ingredients are citric acid and baking soda. When the tablet is dropped in water, the citric acid and baking soda react, which causes the alka seltzer to dissolve. If an alka seltzer is dropped in orange juice, then it will dissolve quicker compared to water because the orange juice has a higher level of acidity.…

    • 426 Words
    • 2 Pages
    Decent Essays
  • Improved Essays

    After the reaction, and an incision to release the gas, the mass also had to be identified, which was less than the previous mass, 255.9 grams. The experimental molar mass was 0.0894 grams, found by using the moles of 〖Co〗_2 and the masses. The percent yield came about by dividing the experimental molar mass by the theoretical (44.01grams) to create 20 percent. The percent yield shows how far off the experimental calculations were from the truth. Overall, by using the Alka-Seltzer, what could be concluded was that Alka-Seltzer reacts…

    • 425 Words
    • 2 Pages
    Improved Essays
  • Improved Essays

    Alka Seltzer Lab

    • 250 Words
    • 1 Pages

    The purpose of this lab was to understand the Law of Conservation of Mass and how it works, using half of an Alka-Seltzer tablet, concealed in a water to fill the container, while a balloon sealed the top to keep it a closed system. The hypothesis was, if the Alka-Seltzer chemical reaction is a closed system, then the mass of the products will equal the reactants. The data did not support the hypothesis because the products were almost always a different mass to the reactants but only the last trial revealed that the mass of the reactants was equal to the products. Usually, the trials indicated a loss of mass until the third trial was done, which was a success. Since the experiment was a closed system, matter could not leave or enter.…

    • 250 Words
    • 1 Pages
    Improved Essays
  • Improved Essays

    6.03 Calorimetry Honors

    • 731 Words
    • 3 Pages

    Determining the Percentage Yield of a Chemical Reaction Question: What is the percentage yield of the reaction of sodium carbonate and calcium chloride dihydrate (the dihydrate must be included with the molar mass calculation)? Predictions: Predict the mass of sodium carbonate and calcium chloride dihydrate that will be required to produce 1.90 grams of calcium carbonate: Therefore, the predicted mass of sodium carbonate is 2.0 grams and the predicted mass of calcium chloride dihydrate is 2.8 grams. Materials: 2 Beakers (150 mL) Calcium chloride Sodium carbonate…

    • 731 Words
    • 3 Pages
    Improved Essays
  • Improved Essays

    In the nine unknown solutions experiment there was nine solutions that were labeled with just numbers from one to nine and all of these one to nine solutions were mixed together randomly to see what kind of reaction it would form. There were mostly no reactions being formed but the reactions that were soluble and insoluble formed different colors of precipitate. The main importance in finding the nine unknown solutions was to prevent any inaccuracies that might form when there is a chemical compound forming. This experiment was done to determine the identity of the nine unknown solutions like color (physical trait), and chemical characteristics.…

    • 791 Words
    • 4 Pages
    Improved Essays
  • Improved Essays

    Goals The goal of the lab was to investigate the properties and structure of an unidentified compound that was discovered in a local landfill. The group was called in to help determine the chemical and physical properties of the compound so we can let the people of the town know so it can be taken care of properly with or without further precautions to be taken. Another goal of this project was to devise the synthesis of the unknown compound. Experimental Design In order to determine the correct identity of our unknown compound, we first started with a couple preliminary tests, which include physical state and smell.…

    • 757 Words
    • 4 Pages
    Improved Essays
  • Improved Essays

    Purpose: The purpose of this lab is to establish a concrete understanding of limiting reagents and percent yields. In addition, the lab should give the administrator the ability to analyze the effects of reactants on the product of a chemical reaction. Procedure: In part A of the lab, the first step in the procedure is to add 20 mL, and 25 mL of CaCl2 to two different flasks.…

    • 400 Words
    • 2 Pages
    Improved Essays
  • Improved Essays

    Hydrate Lab

    • 805 Words
    • 4 Pages

    In the experiment the percent of water and percent of copper can be calculated with the masses that were taken before and after the reaction. The calculations of the percent of water and copper are shown below: Water: 5H2O:(2.194g3.385 g)*100 64.814% Copper: Cu:(1.104 g3.385 g)*100 32.614% When finding the theoretical percent of water and copper one can find the molar mass of each and find the percent. The calculations are shown below: Water: 5H2O:(90 g153.546 g)*100 58.614% Copper: Cu:(63.546 g153.546 g)*100 41.356% Analysis of results…

    • 805 Words
    • 4 Pages
    Improved Essays
  • Superior Essays

    Unknown Lab Report

    • 1472 Words
    • 6 Pages

    An unknown sample #18 was obtained on November 6, 2017. The sample came in a glass test tube with a cotton swab that contain the unknown sample. To find the identity of the unknown sample, we had to conduct several biochemical tests to eliminate and narrow down possible organisms that fit the biochemical description to accurately identify our unknown organism of interest. These biochemical tests provided insight on the physical color retention of our unknown sample, and through’s the unknown organism’s ability to break down tested compounds to determine if it had the corresponding enzyme that would allow it to do so. The testing of unknown organisms to accurately discover its identity is crucial in the field of health science.…

    • 1472 Words
    • 6 Pages
    Superior Essays
  • Improved Essays

    Observed/theoretical X 100 1.476 g/3.08 g X 100=47.9% Discussion of Results: There was too much error introduced into the experiment to be able to indicate exactly which product was obtained through the experiment. I believe the results were supposed to include the product being erythro-2,3-dibromo-3-phenypropanoic acid and the mechanism that took place in the experiment was in fact the bromonium ion mechanism. My group’s percent error was 47.9% which is extremely low. This low percent error was gained from the lack of mass of the product obtained after vacuum filtration.…

    • 717 Words
    • 3 Pages
    Improved Essays
  • Great Essays

    X 10-2 mol Molarity of Na2CO3 = (2.359 X 〖10〗^(-2) mol)/(0.25 L) = 9.436 x 10-2 mol L-1 Na2CO3 + 2HCL 2NaCl + CO2 + H2O The 20 mL aliquot of Na2CO3 solution with concentration 9.436 x 10-2 mol L-1 was reacted completely with 15.05 mL of HCl solution with unknown concentration. Therefore, the molarity of HCl solution can be calculated by (M_A V_A)/(M_B V_B ) = a/b ((9.436 X 〖10〗^(-2) ) (0.02))/(M_B (0.01505))= 1/2 MB = 0.2508 mol L-1…

    • 746 Words
    • 3 Pages
    Great Essays
  • Great Essays

    Gravimetric Analysis of a Metal Carbonate Purpose The purpose of this lab is to find the mass of an unknown metal by conducting a double-displacement precipitation reaction, which is our gravimetric analysis. Once we find the precipitate mass, we can then find the molar mass by using the molar ratio given in the reaction equation. Procedure First, we set up the ring stand with a Bunsen burner, put a crucible on top of the pipe stem triangle and heated the crucible for a minute, then let it cool down.…

    • 890 Words
    • 4 Pages
    Great Essays
  • Improved Essays

    The aim of this experiment was to determine the percentage composition of magnesium and oxygen in magnesium oxide and evaluate if the composition varies or remains constant. To test this, magnesium was heated and made to react with the oxygen gas in the atmosphere. This reaction formed the ionic compound, magnesium oxide. The percentage composition was later calculated based on the results of the experiment as shown in the above calculations, Figure 4. These results were compared to the expected percentage composition also calculated in calculations, Figure 1.…

    • 917 Words
    • 4 Pages
    Improved Essays