Experiment 2:
Aim: In this experiment you will determine the mass of a single drop of water by a graphical method. You will evaluate its uncertainty.
Data:
Table 1:
Number of Drops:
Mass of Beaker + drops/g (0.01g)
1
2.36 g
2
2.38 g
3
2.40 g
4
2.44 g
5
2.46 g
6
2.48 g
7
2.50 g
Chart 1:
Analysis: The mass of 1 drop of water is 0.4g. By taking the total mass and dividing it by the number of drops we can figure out the average mass of a drop of water. However the number of drops should be more than three as we have to take into consideration that the mass of the boat is combined with the mass of the drops. However, we are measuring the combined weight of both and therefore there is no need to measure the mass of the boat by itself. The major possible error is that …show more content…
It is clear that while the results are very precise it is not very accurate. For example for 5 drops of water the mass of 1 drop is 0.492 which is 60% away from the correct answer shows that the data is not very accurate. However the data is precise as looking at graph 1, it can be easily seen that the mass goes up by 2 the majority of the time. The data itself shows it goes up by .2g and the percentage uncertainty shows that it only has 0.4% of not being percies. It is fair to say that there is most likely a systematic error as the data is not very accurate and there is a huge percent error. There is a very small chance of there being a random error with the random uncertainty being only 0.4%. The pipette could be replaced with a volumetric pipette. This would allow for us to be able to measure the amount of water that is placed within. Therefore a drop would be more accurate as we could control the amount of volume that is lost from the pipette. Maybe it would've been better to use a different balance beam of the same model to determine whether the original balance beam is faulty or if that brand is not very
Aim: In this experiment you will determine the mass of a single drop of water by a graphical method. You will evaluate its uncertainty.
Data:
Table 1:
Number of Drops:
Mass of Beaker + drops/g (0.01g)
1
2.36 g
2
2.38 g
3
2.40 g
4
2.44 g
5
2.46 g
6
2.48 g
7
2.50 g
Chart 1:
Analysis: The mass of 1 drop of water is 0.4g. By taking the total mass and dividing it by the number of drops we can figure out the average mass of a drop of water. However the number of drops should be more than three as we have to take into consideration that the mass of the boat is combined with the mass of the drops. However, we are measuring the combined weight of both and therefore there is no need to measure the mass of the boat by itself. The major possible error is that …show more content…
It is clear that while the results are very precise it is not very accurate. For example for 5 drops of water the mass of 1 drop is 0.492 which is 60% away from the correct answer shows that the data is not very accurate. However the data is precise as looking at graph 1, it can be easily seen that the mass goes up by 2 the majority of the time. The data itself shows it goes up by .2g and the percentage uncertainty shows that it only has 0.4% of not being percies. It is fair to say that there is most likely a systematic error as the data is not very accurate and there is a huge percent error. There is a very small chance of there being a random error with the random uncertainty being only 0.4%. The pipette could be replaced with a volumetric pipette. This would allow for us to be able to measure the amount of water that is placed within. Therefore a drop would be more accurate as we could control the amount of volume that is lost from the pipette. Maybe it would've been better to use a different balance beam of the same model to determine whether the original balance beam is faulty or if that brand is not very