Diffusion Lab Report

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After placing the sucrose tubings into the water for 30 mintues, they each varied with different masses and percent changes. By comparing the percnt changes, the researchrs determined the molarity of ach solution. They believed that solution A was .4M, solution B was 1.0M, solution C was .6M, solution D was .8M, solution E was .2M, and solution F was water. However, after reviewing the classes data, the students realized that solution B was 1.0M and solution D was .8M. The graph showed the error because it was not linear. So, the hypothesis was correct, but the expirmental error must have been a leakage while the tubes were soaking in water resulting from the tubes being tied too loose. In the future, I would suggest filling some other vessel with a semipermeable …show more content…
As the solute becomes more concentrated the diffusion process quickens because the molecules have much more contact, resulting in an even spread.
1b. What other variables might influence the rate and direction of osmosis? The properties of the cell and its selectively permeable membrane, the solute, and the surrounding environment could influence the rate and direction of osmosis.
1c. How would diffusion of a starch be different from a protein?
Diffusion of a starch would be slower because of the larger particles but it travels without energy whereas a protien employs active transport to move.
1d. How could you prove or disprove that a specific solute, such as sucrose, was able to diffuse through a semipermeable membrane?
To prove or disprove where or not a specific solute was able to diffuse, you would measure the percent change of the mass in an expirement. First, place the solute into a semipermable dialysis tube and then place the tubing into a cup of water. Weigh the tubing in the beginning and at the end to calculate the percent

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